Alex wrote: Mon Feb 23, 2026 12:57 pm
I can help you out with those two numbers.
But I can't help you with that Triangle consisting of 28 numbers as I don't know how or why those 28 values are there.
753 = Lucky-o(6373 = rs Vs(9453 = Tri(137 (i. α)))) = 500 + 3 last digits of Tri(777)
7753 = 753 w. ext...
TV of Vs(7753) = 1307 = 137 (i. α) w. ext...
7777 = 777 w, ext...
TV of Vs(7777) = 4170 = 4000 + Comp(130 "inverse Alpha" (E o)) = Comp(3596 = 500 + 3096 "seven hundred seventy and seven" (E s))
Yes, I can understand, I will pursue my "demonstration".
Within the structure of these numbers, we have the value of 50 + 110 + 37, the first three numbers at the top. Using a descending method from top to bottom, we can find this number by using the seven numbers and adding them one by one to the sum of the previous line:
258 - 37 - 110 - 50 = 61 where is aleph+lamed+lamed or A-I-N.
50 + 160 + 197 + 455 + 721 + 1081 + 1529 = 4193 => 193 + 4 = 197
50 + 160 + 197 + 455 + 721 + 82 + 530 = 2195 = 2 + 195 = 197
50 * 160 * 197 = 1576000 === 576 + 1 = 577
Then, by adding the hundreds place, we get 193 + 4 = 197
We could also have focused on the sums in this way, 50 + 160 + 197 + 455 + 721 + 82 + 530 = 2195
Or, by adding the hundreds place: 2 + 195 = 197
Our first three sums are 50, 160, and 197. We can perform this simple calculation using the descending three-number method:
50 * 160 * 197 = 1576000 === 576 + 1 = 577
For the ascending method, starting from the bottom up, we have:
50 + 110 = 160… same pattern and method
197
405
448 + 360 = 808
808 + 266 = 1074
1074 + 266 = 1332
By multiplying the numbers established above, we a:
160*197*405*808*1074*1332=14755743559526400
Where, by adding the hundreds digits of the number found:
14+755+743+559+526+400= Total 2997
-296, the value of "and the earth" in Hebrew = 2701,
If we take the last three numbers or the first three, and multiply them, we get:
808*1074*1332=1155898944, by transformation we get 1998 (sum of hundreds by addition)
160*197*405=12765600
Or, by adding the hundreds digits of the two numbers Found:
600 + 765 + 12 = 1377
944 + 898 + 155 + 1 = 1998
From a "conservation" structure perspective:
1 + 998 + 1 + 377 = 1377
Considering the last four levels of triangle T7:
258 + 266 + 360 + 448 = 1332, equal to the combined sum of the even/odd numbers in the 6-pointed star (1369/1332).
50*110*37*258*266*360*448 = 2252403901440000
2+252+403+901+440=1998
Three top levels of triangle T7 with 1529
50*110*37=203500
By adding the hundreds digits = 203+500=703
By multiplying the first 5 levels of numbers to obtain a multiple of 37: 19*37
50*37+110*37+37*37+258*37+266*37=26677
=677+26=703
1850+4070+1369+9546+9842=26677
***By adding the hundreds digits of the first 5 numbers 851 + 74 + 370 + 555 + 851 = 2701
360 * 37 = 13320, multiplied by 13 + 320 = 333
448 * 37 = 16576 = 592
***By adding the hundreds digits of the last 5 numbers: 592 + 333 + 851 + 555 + 370 = 2701
592 * 333 * 851 * 555 * 370 = 34450077837600
Using the same method by adding the hundreds digits from the previous number: 600 + 837 + 77 + 450 + 34 = 1998
First three lines = 703 in total
Seven entire lines = 1998
1998 + 703 = 2701
50 + 110 = 160 etc.
197
405
448+360=808
808+266=1074
1074+266=1332
160*197*405*808*1074*1332=14755743559526400
14+755+743+559+526+400
808*1074*1332=1155898944
160*197*405=12765600=600+765+12=1377
944+898+155+1=1377
1+998+1+377=1377
Total 2997 -296=2701….
808 * 1074 * 1332 = 1155898944
944 + 898 + 155 + 1 = 1998
258 + 266 + 360 + 448 = 1332 (sum of even/odd numbers) 6-pointed star (1369/1332).
50*110*37*258*266*360*448 = 2252403901440000
2+252+403+901+440 = 1998
50*110*37 = 203500
By adding the hundreds place = 203+500 = 703
50*110*37*3 = we multiply by 3 because the first 3 numbers are the same.
50*110*37*258*266*360*448*7 = we multiply by 7 because it's the total of the numbers, but also by the multiple. 37.
50*37 + 110*37 + 37*37 + 258*37 + 266*37 = 26677
= 677 + 26 = 703
1850 + 4070 + 1369 + 9546 + 9842 = 26677
***By adding the hundreds digits of the first 5 numbers: 851 + 74 + 370 + 555 + 851 = 2701
360*37 = 13320, by 13 + 320 = 333
448*37 = 16576 = 592
***By adding the hundreds digits of the last 5 numbers: 592 + 333 + 851 + 555 + 370 = 2701
592*333*851*555*370=34450077837600
600+837+77+450+34=1998
First three lines=703_total
Seven entire lines, total =1998
1998+703=2701.