3 .(1 4 . . . . . . . 3 6 + 6 6 6 digits . . . . . . . 2)(0 1 9 9 5 . . . . . . . 1 3 1 8 digits . . . .}digit # 2 0 2 0 That's the 2nd
The Beast = 4 8 0 4 8 0 + 1 5 9 + 2 6 = 6 6 5 4 8 0 < 1 5 9 + 2 6 > 6 6 6 I think....that if we are
The English sum of "Jesus Christ" = 9 0 6, it first occurs at digit # 1 2 9 3 The Greek sum of "Jesus Christ" = 2 3
It was day 8 6 of year 1 9 9 1 when God had me discover the 6 6 6, 2 1 6, and 4 5 0 design in the number set, and discover
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9 1 1
3 .(1 4 . . . . . . . 3 6 + 6 6 6 digits . . . . . . . 2)(0 1 9 9 5 . . . . . . . 1 3 1 8 digits . . . .}digit # 2 0 2 0
Scott Yesterday, 04:36 PMThat's the 2nd