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    Scott

    9 1 1

    3 .(1 4 . . . . . . . 3 6 + 6 6 6 digits . . . . . . . 2)(0 1 9 9 5 . . . . . . . 1 3 1 8 digits . . . .}digit # 2 0 2 0

    That's the 2nd

    Scott Yesterday, 04:36 PM Go to last post
    Scott

    9 1 1

    The Beast = 4 8 0

    4 8 0 + 1 5 9 + 2 6 = 6 6 5

    4 8 0 < 1 5 9 + 2 6 > 6 6 6

    I think....that if we are

    Scott 02-15-2020, 10:42 AM Go to last post
    Scott

    9 1 1

    The English sum of "Jesus Christ" = 9 0 6, it first occurs at digit # 1 2 9 3

    The Greek sum of "Jesus Christ" = 2 3

    Scott 02-12-2020, 04:59 PM Go to last post
    Scott

    9 1 1

    It was day 8 6 of year 1 9 9 1 when God had me

    discover the 6 6 6, 2 1 6, and 4 5 0 design in the number set,

    and discover

    Scott 02-11-2020, 11:30 AM Go to last post
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