# Thread: 9 1 1

1. Senior Member
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The sum of my name 1 5 9 0 completes its first

occurrence at digit # 4 8 6 9

The first 1 5 1 2 digits end with Enoch's Rapture year,

9 8 7{p.11,post # 102)

The last 1 5 1 2 digits begin with 1 9 8 4,

or, 1 3 1 8 + 6 6 6

The number of digits between those 2 groups of 1 5 1 2, are,

6 6 6 + 1 1 7 9

1 1 7 9 + 6 6 6 + 1 1 7 9 + 6 6 6 + 1 1 7 9 = 4 8 6 9

1179, p.21, bottom of post # 202

The number 1 5 1 2 completes its first occurrence at digit # 5 2 2 3

9 + 2 3 + 2 0 1 7 + 1 1 7 9 + 1 9 9 5 = 5 2 2 3
Last edited by Scott; 10-19-2020 at 04:16 PM.

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First occurrence's of 1 4 8 0, 1 9 4 7, and 8 8 8,

3 . 1 4 . . . 1 4 8 0(. . .1947. . .)(1 9 4 7 . . .86 + 666 + 1948. . . 8 8 8)

1 9 4 7 + 8 6 + 6 6 6 + 1 9 4 8 digits

from completion of Christ to completion of Jesus,

with the first occurrence of 1 9 4 7 starting 1 9 4 7 digits

after the first occurrence of Christ.

In Greek,

Jesus = 8 8 8{Amos 9:15 is the last verse of Bible chapter 8 8 8)
+
Christ = 1 4 8 0

= 2 3 6 8

3 . 1 4 . . . . 8(6 . . . .2 3 6 8. . . . . 6 6 6)
Last edited by Scott; 10-26-2020 at 01:19 PM.

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The first occurrence of 1 9 1 7

completes at digit # 1 9 4 8.

The first occurrence of number 1 9 4 7,

and the first occurrence of 2 0 1 8 {End of Generation),

cover a span of 2 0 1 8 digits.

The Sign in the Star's that was to happen before

the generation completed, was the Revelation 12 Sign

John wrote about, in what is the 1179th chapter

of The Bible, that took place on 9 / 2 3 / 2 0 1 7

3 3 days after the total Solar Eclipse that created

two Hurricanes when it dissipated over the ocean.

They were named Maria{Mary) and Jose{Joseph).

September / + Twenty Third / + Two Thousand Seventeen

= [ 9 + 2 3 + 2 0 1 7 + 1 1 7 9 ]

A=6 B=12 C=18.....Z=156

The total number of chapters in The Bible, are

1 1 7 9 chapters short of matching what God decided

would be the Greek numeric sum of his Son's name, 2 3 6 8
Last edited by Scott; 11-01-2020 at 02:33 PM.

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Correction,

The number 1 9 1 7 completes its first occurrence at digit # 1 9 4 7

5. Senior Member
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The number 1 9 1 7 completes its first occurrence at digit # 1 9 4 7.

Digit # 1 9 1 8 is the completion of the second occurrence of the number 1 9 4 9

The 70 weeks of years began 3 5 1 6 years after Adam's creation.

2 3 6 8 completes its first occurrence at digit # 7 4 8 4

3 5 1 6 + 1 9 4 8 + 2 0 2 0 = 7 4 8 4
3 5 1 6 + 1 9 4 7 + 2 0 2 1 = 7 4 8 4
Last edited by Scott; 11-07-2020 at 09:09 PM.

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Christ was born "in" the year 4 0 0 0

The number 1 9 4 7 starts its first occurrence at digit # 2 0 5 4

Digit # 2 0 5 3 + 1 9 4 7 digits = digit # 4 0 0 0

Digit # 4 0 0 0 is the first 6 in the

3rd occurrence of the number 6 6 6

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First occurrence of 2 0 2 1 and 2 3 6 8,

3 . 1 4 . . . . . . . . . 2 0 2(1 . . . . . .1 1 0 7 + 2 0 2 1. . . . . . 2)3 6 8

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6 x 6 6 6 = 3 9 9 6 {1590 + 2406)

The number 3 9 9 6 completes its first occurrence at

digit # 2 1 1 6

The first 3 9 9 6 digits of Pi, end with this string of digits,

2 1 1 1 6 6

3 .(1 4 . . . . .2 1 1 6. . . . 3 9 9 6)

3 .(1 4 . . . . . . . . . . . .3 9 9 6. . . . . . . . 2 1 1 1 6 6)

Counting backwards 2 0 2 1 digits from digit # 2 1 1 7

puts us at digit # 9 6, and digit # 9 6 is the completion of the

first occurrence of the number 2 1 1 7
Last edited by Scott; 11-17-2020 at 11:21 PM.

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The only 2 words in the Bible having a gematria sum of 2 1 1 7

are found in the Greek New Testament,

"Centurion" {Strongs concordance, G 1 5 4 3

"Crucify" { Strongs concordance, G 4 7 1 7

The first occurrence of 1 5 4 3 in Pi,

3 .(1 4 . . . . .4717 + 4716. . . . . 1 5 4 3)

4 7 1 7 first occurs starting at digit # 1 5 4 9 3

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Digit # 1 5 9 0 is the 2nd 7 in the first occurrence

of the number 7 7 7, which is also the first occurrence

of the number 7 7 7 7,

3 .(1 4 . . . . . .1590 . . . . . 7 7)7 7

1 5 9 0 + 7 7 8 = 2 3 6 8

1 5 9 0> 7 7 7 <2 3 6 8

I decided to use the first occurrence of my name, 1 5 9 0,

as the first 4 digits of 7 7 8 digits, and those 7 7 8 digits

ended with the 6th occurrence of 7 7 8, which is followed by a 7,

and the 6th occurrence of the number 2 0 1 9,

3 . 1 4 . . . . . . . . .(1 5 9 0 6 . . . . .7 7 8. . . . . 7 7 8)7 2 0 1 9

3 . 1 4 . . . . . . . . . 1 5 9 0 6(. . . . .7 7 8. . . . . 7 7 8 7 2 0 1 9)

Jesus Christ = 2 3 6 8 / Greek

Jesus Christ = 9 0 6 / English
Last edited by Scott; 11-21-2020 at 12:05 AM.

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