9 1 1

[Scott]

Count the number = 1 0 7 4

2 5 8 + 1 0 7 4 + 2 5 8 = 1 5 9 0

6 6 6 + 2 5 8 + 6 6 6 = 1 5 9 0


2 5 8 + 2 + 5 + 8 + Two hundred Fifty Eight + Two + Five + eight

= [ 6 6 6 + 1 3 1 8 + 6 6 5 ]



1 5 9 0
+
1
+
5
+
9
+
One Thousand Five Hundred Ninety
+
One
+
Five
+
Nine
+
Zero

= [ 1 5 9 0 + 3 1 4 1 ] { 3 . 1 4 1 5 9, post # 218 )

minus 1 + 5 + 9

= [ 1 5 8 9 + 1 1 0 7 + 2 0 2 0 ]


Christ = 4 6 2 / A=6 B=12 C=18 . . . Z=1 5 6 / God=1 5 6

My middle name = 4 6 2

and when i subtract 4 6 2 from my first and last name,

5 8 2 + 5 4 6 - 4 6 2 = 6 6 6

[Scott]

Count the number of the beast = 1 6 8 0

The first occurrence of 1 6 8 0 completes at digit # 1 3 8 0 1,

3 .(1 4 . . . . . 1 5 9 0 + 4 8 6 9 + 6 6 6 + 2 1 6 + 1 5 9 0 + 4 8 6 9 . . . . 1 6 8)0

Counting those number of digits from digit # 1 instead the decimal point,

would have included the 0 of the first occurrence of 1 6 8 0


My full name, 1 5 9 0, consisting of 7, 5, and 6 letters, completes its first occurrence at digit # 4 8 6 9


8 x 1 5 9 0 + 1 0 8 0 = 1 3 8 0 0

Panin's,
Here is the wisdom = 1 0 8 0

Panin's,
Here is the wisdom, who has (hath) understanding = 2 4 2 4

As i shown several times now, the first occurrence of 2 4 2 4 after 1 1 0 7 digits,

is followed by the first occurrence of 5 4 1. { p.21, post # 202 )

You have counted the number correctly = 2 4 2 4

The short form of my name that people address me as, = 8 3 4

8 3 4 + 1 5 9 0 = 2 4 2 4


6 6 6 completes its first occurrence at digit # 2 4 4 2

1 5 9 0 begins its first occurrence at digit # 4 8 6 6

Digit # 2 4 4 2 + 2 4 2 4 digits = digit # 4 8 6 6


My Son's name = 1 3 8 0
His first + last name, minus his middle, which is my first, = 2 1 6
My first + last, minus my middle, = 6 6 6
My first name that i gave my Son for his middle, = 5 8 2
I was born Jan.1st 1963
1 9 6 3 - 5 8 2 = year 1 3 8 0

The sum of my first middle and last name,

5 8 2, 4 6 2, 5 4 6

Five hundred eighty two
+
Four hundred sixty two
+
Five hundred foUrty Six

= [ 1 5 9 0 + 1 6 8 0 + 1 5 9 0 ]

Never leave the U out of "Fourty" when using gematria,...there was no reason

for removing it from the spelling, except to foul up many supernatural gematria results!

Some people may think it was done to shorten the word, but, why not the word "Fourteenth",

which now has 5 letters more than the word "Forty"?

Four
Fourteen
Fourteenth
Forty?
It became the spelling around the time the English King James version was published in 1 6 1 1

Jesus Christ = 7 5 4 in Hebrew
Jesus Christ = 2 3 6 8 in Greek
7 5 4 + 1 6 1 4 = 2 3 6 8
In Pi's digits the first occurrence of number 1 6 1 4 begins at digit # 1 6 1 0,
and completes at digit # 1 6 1 3


1 5 9 0 + 7 5 6 = [ 1 6 8 0 + 6 6 6 ]

[Scott]

The 2 numbers Jesus Christ{2368) led me to find after counting 6 6 6,

that are the only 2 number's having the unique connection with the

number God chose for the years preceding Enoch's Rapture, 9 8 7,

are, 7 9 8 and 1 9 9 5

7 9 8 + 9 8 7 + 1 9 9 5 = 3 7 8 0


Here's the first occurrence of the number 3 7 8 0, which has the first

occurrence of 4 0 4 4 appearing right before it,



3 .(1 4 . . . . . 2 3 6 8 + 1 5 9 0 + 1 3 1 8 + 2 3 6 8 . . . . . . . 4 0 4 4)3 7 8 0



8 6 + 2 3 6 8 + 1 5 9 0 = 4 0 4 4


My birth year}1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]

I did the same thing with 1 9 9 5 as i did with 6 6 6,

1 x 9 x 9 x 5 = 4 0 5

1 9 9 5 - 4 0 5 = 1 5 9 0

I knew at the time that he had led me to that number, but i didn't recognize my name

structured inside of it because i knew nothing about English gematria at the time.


Count the number of the beast + 6 6 6 = 2 3 4 6

1 5 9 0 + 7 5 6 = 2 3 4 6

2 3 4 6 completes its first occurrence at digit # 2 6 3

Digit # 2 6 3 + 3 7 8 0 digits = a completed digit # 4 0 4 3,

which puts us right at digit # 4 0 4 4


3 .(1 4 . . . 2 6 3 . . . 2 3 4 6)( . . . . . . 3 7 8 0 . . . . . . .)(. digit # 4 0 4 4


I forgot to mention on Page 22 post # 220, that year 5 9 3 3 and 5 9 3 4 from Adam,

put us in the center of the time of The Great Depression.

August 1 9 2 9 - March 1 9 3 3

[Scott]

9 x 8 x 7 = 5 0 4

9 8 7 - 5 0 4 = 4 8 3 {6 9 x 7)



Here's the first occurrence of 9 8 7 starting at digit # 1 5 1 0,
and my name which completes at digit # 4 8 6 9, and the
measurement in digits they cover,

3 . 1 4 . . . . . . . . . . . (9 8 7. . . . . 4 8 3 + 6 6 6 + 2 1 6 + 1 9 9 5 . . . . . 1 5 9 0)


Here's the first occurrence of 1 9 9 5 completing at digit # 7 0 7

3 . 1 4 . . . . 2 0 1 9 9 5( . . . 6 6 6 + 2 1 6 . . . .)(. digit # 1 5 9 0

That was the second occurrence of 2 0 1 9 starting at digit # [ 3 6 + 6 6 6 ]


"Revelation chapter Thirteen verse Eighteen" (= 2598)
+
"Here is the wisdom, who hath understanding, let him count
the number of the beast, for it is the number of a man, and his
number is "Six hundred sixty six" (= 8658, Ivan Panin's N.T.)

= [ 6 6 6 + 1 0 5 9 0 ]


6 6 6 + 1 0 5 9 0 = [ 1 5 9 0 + 9 6 6 6 ]

9 6 6 6 first occurs in Pi starting at digit 3 9 9 9 and

3 9 9 9 are the years that precede Christ's birth.

The 3rd occurrence of 6 6 6 is right after digit # 3 9 9 9

I was 2 8 yrs. 8 6 days old the night this experience began,

Here's the first occurrence of 2 8 8 6 and my name,

3 .(1 4 . . . 8 7 0 . . . 2 8 8 6)( . . . . . 3 9 9 9 . . . . 1 5 9 0)

3 .(1 4 . . . 8 7 0 . . . 2 8 8 6)( . . . . . 3 9 9 6 . . . . 1)5 9 0

"You are the man who counted the number of the beast" = 2 8 8 6
"You're the man" = 8 7 0

January First Nineteen Sixty Three + 1 5 9 0 = 3 9 9 6


"You are the one who counted the number of the beast,....

= [ 6 6 6 + 1 5 9 0 + 6 6 6 ]

+

in order to reveal the day(date) of The Rapture"

= a total sum of 5 3 0 4


6 6 6 + 2 1 6 + 1 5 9 0 + 5 3 0 4 + 6 6 6 + 2 1 6 = 8 6 5 8


6 x 6 x 6 = 2 1 6
2 1 6 occurs first right after digit # 9 9 0

November Seventh Two Thousand Twenty = 2 7 2 4

3 . 1 4 . . . . . (2 1 6 . . . . . 1 5 9 0 + 2 7 2 4 . . . . . .}digit # 5 3 0 4


Counting the 4 digits that are the first occurrence of my name,

as being the first 4 of 6 6 6 digits,

the 6 6 6 digits will then divide at 4 5 0 and 2 1 6

right at the 8 in the first occurrence of the number 1 3 1 8

1 3 1 8 completes at digit # 5 3 1 5,

and my name 1 5 9 0 starts after digit # 4 8 6 5

[Scott]

1 2 3 + 6 6 6 = 7 8 9 {all numbers utilized except 4, 5, and 0

6 x 6 x 6 = 2 1 6

6 6 6 - 2 1 6 = 4 5 0

Page 21 post # 209

[Scott]

3 .(1 4 . . . . . . . . . . 1 0 5 0 + 1 3 1 8 . . . . . . . . . . . . . . digit # 2 3 6 8

3 . 1 4 . . . . .(1 0 5 0 . . . . . 9 1 1 . . . . . digit # 1 5 9 1


3 . 1 4 . . . . .(1 0 5 0 . . . . . 9 1 1 + 2 3 6 8 + 9 1 1 . . . . . . 7 5 1 5 9 0 6)

God = 1 5 6 / English
Elohim = 8 6 / Hebrew
Jesus Christ = 9 0 6 / English
Jesus Christ = 2 3 6 8 / Greek

Richard Amiel McGough = 1 0 5 0

I didn't know those measurements were in Pi's digits, or many things i've shown
since i first i came back to this site almost a year ago, and chose 9 1 1 for the title!
Didn't know this either,

3 . 1 4 . . . . .(1 0 5 0 . . . . 1 5 6 + 9 0 6 + 1 1 0 7 + 2 0 2 0 . . . . . 7 5 1 5 9 0)6



Here again, are the first occurrences of 8 6 and 6 6 6,


3 . 1 4 . . . . . 8(6 . . . . . . . . 2 3 6 8 . . . . . . . . . . 6 6 6)


and first occurrence's of 9 1 1 and 6 6 6,


3 . 1 4 . . . . . . . . . . . 9(9 1 1 . . . . . 9 1 0 . . . . . 6 6 6)



Up until the beginning of Nov.7th 2 0 1 9, i had lived these groups of days,

1 5 9 0 0 + 4 8 6 3

The following string of digits occurs for the first time starting at digit # 4 8 6 4,

7 5 1 5 9 0 6

Last year's 9 / 1 1 i had lived 2 2 groups of 9 1 1 days, and 1 group of 6 6 6 days



Using the first occurrence of my name, 1 5 9 0, as the first

4 digits of 6 6 6 digits, the 6 6 6 digits

will then divide at 4 5 0 and 2 1 6 right at the 8

in the first occurrence of the number 1 3 1 8 which is completed

at digit # 5 3 1 5

5 3 1 4 = January First Nineteen Sixty Three{2 4 0 6) + 1 5 9 0 + 1 3 1 8

5 3 1 5 = 3 9 9 7 + 1 3 1 8

[Scott]

1 5 9 0 first occurs starting at digit # 4 8 6 6

6 6 6 1 5 9 0 first occurs after some 12 million

digits, connected to,

4 8 6 6 6 6 1 5 9 0

[sylvius]

https://www.youtube.com/watch?time_c...ature=emb_logo

In this video Jethro Black discusses the Sea of King Solomon the description of which can be found in I Kings 7:23 and II Chronicles 4:2. Hidden in these verses is the number Pi to 4 decimal places. He also shows the number Pi hidden in the first verse of the Bible and then goes on to reveal the message that is hidden in Pi. This lecture is based on his Slide Show Pi in the Sky which can be purchased from wowdiscoveries.com.

[Scott]

6 6 6 + 2 1 6 = 8 8 2

3 .(1 4 . . . . 3 7 4 . . . . 8 8 2)(. . . . . 3 7 4 + 3 7 4 4 + 3 7 4 . . . . . 1)5 9 0

[Scott]

The number of digits separating the completion of the first

occurrence of the number 1 9 9 5 at digit # 7 0 7,

and digit # 1 5 9 0, is, 6 6 6 + 2 1 6


The first 1 5 9 0 + 6 6 6 digits of Pi end

with the second occurrence of, 9 8 7


3 .(1 4 . . . . 1 9 9 5)( . . . 6 6 6 + 2 1 6 . . . . { digit # 1 5 8 9

3 .(1 4 . . . . . . . . . . . . { digit # 1 5 9 0) + 6 6 6 . . . . . . . . . . . . 9 8 7)


First occurrence of 9 8 7,

3 .(1 4 . . . . . . . . 7 5 6 + 7 5 6 . . . . . . . 9 8 7)

or,

3 . 1 4 . . . . 8 6( . . . . 4 5 0 + 9 8 7 . . . . 9 8 7)


987,1995, page 11 post # 102, page 13 post # 121, page 20 post # 200