Google Ads

Google Ads

Bible Wheel Book

Google Ads

+ Reply to Thread
Page 22 of 28 FirstFirst ... 12181920212223242526 ... LastLast
Results 211 to 220 of 275

Thread: 9 1 1

  1. #211
    Join Date
    Aug 2013
    Posts
    470
    1 0 5 0{R.A.M.) occurs first starting at digit # 6 8 1

    6 8 1 + 2 0 2 0 = 2 7 0 1{Hebrew sum of the words in Gen.1:1)

    Count the number of the beast(=1680)) + 6 6 6{that complete's at digit # 2 4 4 2) = 2 3 4 6


    2 3 4 6 occurs first at starting at digit # 2 6 0

    Digit # 2 5 9 + 2 4 4 2 = digit # 2 7 0 1



    6 6 6 + 2 1 6 = 8 8 2

    The first occurrence of 8 8 2 starts at digit # 3 7 2

    Digit # 2 7 0 1 is 3 7 2 digits after digit # 2 3 2 9,

    and digit # 2 3 2 9 is the completion of the first occurrence of 1 5 6.

    3 .(1 4 . . . . 7 3 . . . )(8 6 . . . . 1 5 9 0 + 6 6 6 . . . . 1 5 6} digit # 2 3 2 9

    digit # 2 3 2 9 + 3 7 2 digits = digit # 2 7 0 1

    7 3 + [ 3 6 x 7 3 ] = 2 7 0 1
    Last edited by Scott; 07-15-2020 at 10:57 PM.

  2. #212
    Join Date
    Aug 2013
    Posts
    470
    2 0 2 0 - 1 3 1 8 = 7 0 2 - 6 6 6 = 3 6 { 1 + 2 + 3 . . . . + 3 6 = 6 6 6 )

    1 3 1 8 + 6 6 6 = [ 1 9 4 8 + 3 6 ]

    Israel was reborn as a nation at the time God decided, in the year 1 9 4 8.

    1 9 4 8 doesn't occur till almost the 25000 digit mark,

    but 1 9 4 7, the nearest completed year, completes it's first

    occurrence at digit # 2 0 5 7{3 7 + 2 0 2 0),

    which is, 7 3 + 1,3 1 8 + 6 6 6 digits.

    3 .(1 4 . . . . 7 3 . . . )(8 6 . . . . 1 3 1 8 + 6 6 6 . . . .}digit # 2 0 5 7


    4 9 0{ 7 0 x 7 ) occurs first right after digit # 9 0 6 {p.17, #164),

    and completes at digit # 9 0 9{post # 209)

    In 1 9 4 8 the record number of digits known was 2 0 3 7{ 1 1 + 7 + 2 0 1 9 )

    They didn't know that 4 0 5 digits later 6 6 6 completes its first occurrence at digit # 2 4 4 2
    Last edited by Scott; 07-18-2020 at 11:02 AM.

  3. #213
    Join Date
    Aug 2013
    Posts
    470
    November Eighth Two Thousand Sixteen = 2 4 4 2 = [ 6 6 6 + 1 1 1 0 + 6 6 6 ]


    Donald John Trump = 1 1 1 0

    The first occurrence of this, 2 3 6 8 1 1 1 0, is followed by,

    2 3 6 8 1 1 1 0 2 0 1 7

    His Inauguration was 2 0 1 7

    I consider these obvious "designs",....to be warning's to us about him!


    He was born on 6 / 1 4 of 1 9 4 6

    6 6 6 + 6 1 4 + 6 6 6 = 1 9 4 6


    If we place a span of 2 4 4 2 days finishing on 1 1 / 0 7 / 2 0 2 0

    then 5 / 1 4 / 2 0 1 8 would be day 1 5 3 5.

    In Pi, digit # 1 5 3 5 is the completion of the first occurrence of 9 1 1
    Last edited by Scott; 07-18-2020 at 05:47 PM.

  4. #214
    Join Date
    Aug 2013
    Posts
    470
    The first occurrences of 2 1 6 and 6 6 6,

    cover a span of,

    5 4 1{Israel) + 9 1 1 digits.

    2 1 6 starts right after digit # 9 9 0

    6 6 6 ends at digit # 2 4 4 2


    5 4 1 + 7 7 7 = 1 3 1 8

    2 1 6 completes at digit # [ 7 7 7 + 2 1 6 ]

    ======================================

    9 1 1 + 6 6 6 = 1 5 7 7


    The first occurrence of 1 5 7 7 starts right after digit # 3 2 7 9

    digit # 3 2 7 9 + 1 5 9 0 digits = digit # 4 8 6 9

    digit # 4 8 6 9 is where number 1 5 9 0 completes its first occurrence.

    2 3 6 8 + 9 1 1 = 3 2 7 9 (+ 1 5 9 0 = 4 8 6 9


    1 5 7 7 completes its first occurrence at digit # [ 1 5 6 + 1 1 0 7 + 2 0 2 0 ]


    So it's 2 3 6 8 + 9 1 1 digits to reach the start of the first occurrence of

    1 5 7 7, which is 9 1 1 + 6 6 6, and then 1 5 9 0

    digits from there to reach the completion of the first occurrence of

    the number 1 5 9 0 at digit # 4 8 6 9


    2 3 6 8 + 9 1 1{6 6 6 + 9 1 1 begins) + 1 5 9 0 = 4 8 6 9

    I was completely unaware of most of what i've posted regarding 9 1 1

    when i started this thread and titled it 9 1 1,....God knew what he was about to reveal to me!!
    Last edited by Scott; 07-21-2020 at 10:39 AM.

  5. #215
    Join Date
    Aug 2013
    Posts
    470
    Revelation chapter Thirteen verse Eighteen = [ 1 5 6 + 2 4 4 2 ]

    1 5 6 0 + 6 6 6 + 2 1 6 = 2 4 4 2


    <><><><><><><><><><><><><><><><><>

    Richard Amiel McGough = 1 0 5 0

    1 0 5 0 + 1 3 1 8 = 2 3 6 8

    If i take Jesus Christ from the center of the span of digits our 2 names cover,

    it leaves 2 spans of 9 1 1 at each end, one that begins with the gematria sum of his name,

    and one that ends with mine,

    3 . 1 4 . . . . . . . .(1 0 5 0 . . . . 9 1 1 + 2 3 6 8 + 9 1 1 . . . . 7 5 1 5 9 0 6)
    7 5 6, post # 204

    3 . 1 4 . . . . . . . .(1 0 5 0 . . . . 9 1 1 + 9 1 1 . . . .}digit # 1 5 9 0 + 9 1 1 + 1
    Last edited by Scott; 07-23-2020 at 10:29 AM.

  6. #216
    Join Date
    Aug 2013
    Posts
    470
    (1 0 5 0 . . . . . 9 1 0 . . . . . } digit # 1 5 9 0

    Revelation chapter thirteen verse eighteen = 2 5 9 8

    1(0 5 0 . . . . . . . . . . . 2 5 9 8 + 1 5 9 0 . . . . . . . . . 7 5 1 5 9 0)6

    <><><><><><><><><><><><><><>


    As i was turning 1 0 3 1 2 days old, at about 3:00 am on March 27th 1991,

    i discovered something about the 3 1 1th day of the year, Nov.7th, which is day 3 1 2

    this year because its a leap year, but 11/7 begins after 311 days, and i also discovered

    the 6 6 6, 2 1 6, and 4 5 0

    design in the number set, and, that only 1 number greater than Enoch's Rapture year, 9 8 7,

    has the same features as 9 8 7, and that number is 1 9 9 5

    I went to bed when the sun was coming up, thinking the Rapture could possibly be Nov. 7th 1 9 9 5,

    now more than 2 9 years after that night, i looked for 1 0 3 1 2 and this is what followed,

    1 0 3 1 2 0 3 1 1 9 9 5

    The 5 of 1 9 9 5 is digit # 2 3 8 9 6 8

    My son's name adds to 1 3 8 0, this is its first occurrence, and the first occurrence of 8 6,

    3 . 1 4 . . . . . . . 8 6( . . . . . . . 1 5 9 0 + 1 0 3 1 2 . . . . . )1 3 8 0

    <><><><><><><><><><><><><><><>

    January First Nineteen Sixty Three = 2 4 0 6

    November Seventh Twenty Twenty = 2 4 0 6

    I counted my birth date in digits, from the completion of the first occurrence of my name 1 5 9 0,

    and it brought me to the first occurrence of 1 5 5 9 0

    3 . 1 4 . . . . . . 7 5 1 5 9 0(6 . . . . 2 4 0 6 . . . . . )1 5 5 9 0 7 4 2 2 0 2 0 2 0


    3 .(1 4 . . . . . 2 4 4 2 . . . . 6 6 6)(. . . . 2 4 4 2 + 2 4 0 6 . . . . . . 7 4 2 2 0 2 0 2 0)

    That's the first and second occurrence of 2 0 2 0
    Last edited by Scott; 07-24-2020 at 10:00 AM.

  7. #217
    Join Date
    Aug 2013
    Posts
    470
    The number of digits leading up to that first occurrence 1 5 9 0 thats nestled into

    a 7 5 6, is, 4 8 6 3 digits.

    1 4 x 4 8 6 3 + 3 0 7 2 digits,

    brings us to the last digit of the first occurrence of 1 5 9 0 0 ,

    1 5 9 0 0 is followed by 6 2 4 2 0 2 0

    6 / 2 4 / 2 0 2 0

    June Twenty Fourth Two Thousand Twenty = 3 0 7 2

    3 .(1 4 . . . . 4 8 6 3 . . . )(7 5 1 5 9 0 . . . 1 4 x 4 8 6 3 + 3 0 7 2 . . . . 1 5 9 0 0)6 2 4 2 0 2 0

  8. #218
    Join Date
    Aug 2013
    Posts
    470
    Jesus Christ = 7 5 4 / Hebrew

    Jesus Christ = 2 3 6 8 / Greek

    Jesus Christ = 9 0 6 / English


    Digit # 7 5 4 + 2 3 6 8 + 9 0 7 digits = [ 2 4 3 9 + 1 5 9 0 digits ]

    7 5 4, 2 3 6 8, p.20 post 192
    9 0 7 p.21 post # 202


    The first occurrence of 6 6 6 begins right after digit # 2 4 3 9

    and the first occurrence of 6 6 6 is what the 1 5 9 0 digits begin with.



    1 5 9 0 completes its first occurrence at digit # 4 8 6 9

    Digit # 1 5 9 0 is the second 7, in what is both the first occurrence

    of 7 7 7, and 7 7 7 7

    1 5 9 0 + 1 3 1 8 + 4 8 6 9 = 7 7 7 7

    1 5 9 0 < 7 7 7 > 2 3 6 8

    7 7 7 + 3 6 + 7 7 7 = 1 5 9 0

    7 + 7 + 7 x 3 6 + 7 + 7 + 7 = 7 7 7



    4 x 8 x 6 x 9 = [ 1 5 6 + 9 0 6 + 6 6 6 ]

    3 . 1 4 1 5 9

    4 8 6 9 - [ 1 5 6 + 9 0 6 + 6 6 6 ] = 3 1 4 1

    3 1 4 1 - [ 1 5 6 + 9 0 6 + 6 6 6 ] = 1 4 1 3
    Last edited by Scott; 08-01-2020 at 04:47 PM.

  9. #219
    Join Date
    Aug 2013
    Posts
    470
    The number 2 1 6 occurs first in Pi from digit # 9 9 1 to # 9 9 3

    Digit # 7 7 7 + 2 1 6 digits = digit # 9 9 3

    The 2 1 6 digits end with the first occurrence of the number 2 1 6

    Digit # 7 7 7 + 1 5 9 0 digits{that begin with 216) = 2 3 6 7 digits.

    The 4 digit number occurring for the first time starting at digit # 2 3 6 8 is, 3 5 3 4

    3 5 3 4 = [ 1 5 6 + 9 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 ]

  10. #220
    Join Date
    Aug 2013
    Posts
    470
    I've known for months now that 2 7 2 4{Nov.7/20), and 8 6 5 8,

    which is the sum of the words in Panin's N.T.

    translation of Rev. 1 3 : 1 8 (6x6x6=216),

    that led me to 2 7 2 4, are separated by 5 9 3 3 numbers,

    2 7 2 4 < 5 9 3 3 > 8 6 5 8

    5 9 3 4 from one to the other.



    7 7 7 6 + 6 6 6 + 2 1 6 = 8 6 5 8

    3 6 x 2 1 6 = 7 7 7 6

    January first Nineteen Sixty Three + 1 5 9 0 + 7 9 8 + 9 8 7 + 1 9 9 5

    = 7 7 7 6


    1 3 + 1 8 x 2 1 6 + 1 9 6 2 = 8 6 5 8
    1 3 + 1 9 x 2 1 6 + 1 5 6 + 1 5 9 0 = 8 6 5 8
    6 6 6 + [ 6 6 6 0 + 6 6 6 ] + 6 6 6 = 8 6 5 8



    January First Nineteen Sixty Three
    +
    1 5 9 0
    +

    6 6 6

    +
    January First Nineteen Sixty Three
    +
    1 5 9 0

    = 8 6 5 8



    Today is day 2 1 6 for the year 2 0 2 0, so i looked up

    the 4 digit number that the first 2 1 6 digits of Pi

    end with,....5 9 3 3 is the number!

    In Pi's digits 2 1 6 occurs first right after digit # 9 9 0 ,

    9 9 0 + [ 1 5 9 0 + 6 6 6 + 2 1 6 ] + [ 1 5 9 0 + 6 6 6 + 2 1 6 ] = 5 9 3 4
    Last edited by Scott; 08-03-2020 at 09:33 PM.

Thread Information

Users Browsing this Thread

There are currently 7 users browsing this thread. (0 members and 7 guests)

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may post replies
  • You may not post attachments
  • You may edit your posts
  •