9 1 1

[Scott]

1 5 9 0 , 6 6 6

1 2 3 + 6 6 6 = 7 8 9
6 x 6 x 6 = 2 1 6
6 6 6 - 2 1 6 = 4 5 0

5 x 9 x 6 x 6 x 6 = [ 1 5 6 + 9 0 6 + 8 6 5 8 ]


[ 1 5 6 + 9 0 6 + 8 6 5 8 ] - 6 6 6 0

= 3 0 6 0{Saturday, November Seventh Twenty Twenty ? )


3 0 6 0 = [ 2 6 + 2 3 6 8 + 6 6 6 ]

2 3 x 6 8 + 2 6 = 1 5 9 0

1 5 x 9 0 + 1 0 1 8{176+666+176) = 2 3 6 8

The reverse of 2 3 6 8 { 8 6 3 2 ) first occurs starting at digit # 1 0 1 8

8 6 3 2 + 2 6 = 8 6 5 8

3 . 1 4 . . . . . . . . . . . 8 6 3 2( . . . . . . . 4 8 6 9 + 1 5 9 0 . . . . . . )2 3 6 8

Digit # 4 8 6 9 is where number 1 5 9 0 completes it's first occurrence.

8 6 completes at digit # 7 5, and adding 1 5 9 0 digits to that,

is 1 6 6 5, (which is 7 0 3 short of 2 3 6 8) + 1 6 1 4 + 1 5 9 0 = 4 8 6 9

The first digit of the first occurrence of 1 9 9 5

begins after the first 7 0 3 digits,

6 6 6 + 3 6 = 7 0 2

1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8

1 9 9 5 - 1 0 1 8 = [ 6 6 6 + 3 1 1 ]

3 of every 4 years Nov.7th is day 3 1 1, but being a leap year Nov.7th

begins after the completion of 3 1 1 days.


The number 4 8 6 9 occurs first starting at digit # [ 1 5 9 0 0 + 6 6 0 6 ]


4 8 6 9 + 1 5 9 0 = 6 4 5 9

These digits precede the first occurrence of 6 4 5 9,

8 6 5 8 3 2 6 4 5 9

That was the 2nd occurrence of 8 6 5 8 starting at digit # 1 9 7 2,

the first was digit # 8 6 9.

[Scott]

2 1 6 is the result of counting 6 6 6, so i looked for

a 2 1 6 leading into a 6 6 6, like a chain connected

by its link's,

2 1 6 6 6

That ^ string of digits begin at digit # 2 3 5 0 9

1 0 x 1 5 9 0 = 1 5 9 0 0

(9 x 1 5 9 0) + [ 5 4 1 + 8 6 5 8 ] = 2 3 5 0 9



In the year 1 9 4 8 only the first 2 0 3 7{11+7+2019) digits of Pi were known,

...no one knew yet that the first 6 6 6 completes its occurrence at digit # 2 4 4 2


The first 3 6 0{degree's) digits of Pi, end with the number 3 6 0

The first digit of that number 3 6 0 is Position # 3 6 0 with 3 . included.

The first digit of that number 3 6 0 is also 1 5 9 0 digits short of reaching digit # 1 9 4 8

[Scott]

ISRAEL = 5 4 1 in Hebrew

End of May 14th 1948 + 2 6 4 7 6 days, is the end of Nov.7th 2020

3 6 x 5 4 1 + [ 4 8 6 9 + 1 5 9 0 + 5 4 1 ] = 2 6 4 7 6



Ivan Panin's translation has "the" preceding "wisdom",

Here is the wisdom, = 1 0 8 0

1 5 6 + 1 5 9 0 = 1 7 4 6

1 0 8 0 + 6 6 6 = 1 7 4 6



By counting, 6 x 6 x 6 = 2 1 6,

it created the number 3 2 1 3 with the number set, and then i set out to

find the number/s that matched Enoch's 9 8 7,...there is only 1 number

larger that does i discovered,....1 9 9 5, and then 2 8 yrs later in 2 0 1 9

i find my name, 1 5 9 0, occurring in Pi at digit # 4 8 6 6.

6 6 6 + 3 2 1 3 + 9 8 7 = 4 8 6 6

6 6 6 + 2 1 6 + 2 3 6 8 + 2 6 + 1 5 9 0 = 4 8 6 6

Nov.7th of 1 9 9 5 was the first of the 2 6 Nov.7th's.

1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]

2 3 x 6 8 + 2 6 = 1 5 9 0

[Scott]

4 8 3{6 9 weeks of years, 1st advent

4 0 5 + 4 8 3 = 8 8 8{Jesus / Grk.)


4 8 3 + [ 1 3 x 6 6 6 ] = [ 8 6 5 8 + 4 8 3 ]

8 6 5 8 + 4 8 3 + [ 1 8 x 6 6 6 ] = 2 1 1 2 9

2 1 1 2 9 is how many days old i will be at the start of Nov.7th 2020.



1 5 9 0 <7 7 7> 2 3 6 8

Digit # 1 5 9 0 is the center 7 in the first occurrence of 7 7 7,

which is also the first occurrence of 7 7 7 7

7 7 7 6 + 6 6 6 + 2 1 6 = 8 6 5 8{the sum of Rev. 13:18's words/Panin's)


Here's the sum when the older style of English is slightly changed, making it more straight to the point,

Here is the wisdom, who has understanding, let him count the number of the beast,
it is the number of a man, his number is(=6 6 0 6) + Six hundred sixty six

= 6 6 6 6 + 1 5 9 0


1 5 9 0 completes its first occurrence at digit # 4 8 6 9

4 8 6 9 + 1 5 9 0 + 1 3 1 8 = digit # 7 7 7 7

[Scott]

January First Nineteen Sixty Three = 2 4 0 6

2 4 0 6 + 1 5 9 0 + 7 9 8 + 9 8 7 + 1 9 9 5 = 7 7 7 6


When i looked for this string of digits, 3 1 5 9 0 6,

it was in the middle of this, 3 7 8 0,

3 7 3 1 5 9 0 6 8 0

7 9 8 + 9 8 7 + 1 9 9 5 = 3 7 8 0


1 5 9 0 occurs first starting at digit # 4 8 6 6,

digit # 4 8 6 5 + 5 9 + 2 7 2 4 digits, is the completion

of the first occurrence of the number 3 7 8 0

digit # 3 7 8 0 - [ 5 9 + 2 7 2 4] = 9 9 7, and digit # 9 9 7 is the first digit

of the first occurrence of the number 1 9 9 5,

2 1 6 4 2 0 1)9 9 5


I was born almost 5 7 and a half years ago,

but i've existed just over 5 8 years since conception, and im in my 5 9th year,

and 2 7 2 4 mean's Nov. 7th 2020 to me.


3 . 1 4 . . . . . . . . . . . 1 9 6 3( . . . . . 5 7 . . . . . )1 5 9 0

[Scott]

1 5 9 0 followed the instructions of Rev.1 3 : 1 8 by counting

6 x 6 x 6 = 2 1 6, just over 2 9 years ago.

123 + 666 = 789

123 - 45 - 6 . . - 789 { 3213 )


1 5 9 0 + 6 6 6 + 2 1 6 = 2 4 7 2


3 . 1 4 . . . . . .(8 6 . . . . . . . 1 3 + 1 8 + 2 3 6 8 . . . . . . }digit # 2 4 7 2

3 . 1 4 . . . . . . .8 6( . . . . . . . 2 9 + 2 3 6 8 . . . . . . . . . }digit # 2 4 7 2

3 . 1 4 . . . . . . .8(6 . . . . . . . 2 3 6 8 . . . . . . 6 6 6){digit # 2 4 4 2


The number 8 6 completes its first occurrence at digit # 7 5.

Starting at digit # 8 6 and counting 1 1 0 7 + 2 0 2 0 digits, is a total of 3 2 1 3 digits after the decimal point.

[Scott]

The Hebrew sum of Elohim, and Greek sum of Jesus Christ, combined with the English

sum's of God and Jesus Christ, equal 3 5 1 6, and 3 5 1 6, derived from

scripture as Panin proved, are the years from the beginning of Adam and Eve,

to the Start of the 7 0 week's of years, and we have been waiting for # 7 0.


Digit # 3 5 1 6, is the 1, in the first occurrence of the number 5 1 6,

which is preceded by the 3rd occurrence of the sum of the words in Panin's

rendering of Rev. 1 3 : 1 8,

8 6 5 8 5 1 6

8 6 5 8 is preceded by an occurrence of number 9 9 0.

The first occurrence of 2 1 6 starts right after digit # 9 9 0.


Digit # 3 5 1 6 + 5 1 6 = 4 0 3 2{Crucifixion year) digits.

So the 5 1 6 digits after digit # 3 5 1 6, begin with the 6 of 5 1 6's first occurrence.

[Scott]

3 . 1 4 . . . . . . 6 0 2 1 3(9 . . . . . . 2 3 6 8 + 2 3 6 8 + 2 3 6 8 . . . . . . 3)9 4 0 3 2

6 0 2 1{2020), post # 82, page 9

4 0 3 2 begins to occur first at digit # 7 6 3 2


God = 1 5 6

1 5 6 completes its first occurrence at digit # 2 3 2 9,

digit # 2 3 2 9 + 3 9 digits = digit # 2 3 6 8

The first occurrence of 3 5 3 4 starts at digit # 2 3 6 8


1 5 6 + 9 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 = 3 5 3 4

3 5 3 4 + 1 5 9 0 + 3 5 3 4 = 8 6 5 8


From the completion of the first occurrence of 1 5 6{God/English) at digit # 2 3 2 9, to

digit # 8 6 5 8, is 6 3 2 9 digits, which is the same amount of digits God

chose to cover the span from the completion of the first occurrence of 7 5 4{Jesus Christ/Hebrew),

to the completion of the first occurrence of 2 3 6 8{Jesus Christ/Greek),

and 6 3 2 5 digits stand between them,

2 3 6 8 + 1 5 9 0 + 2 3 6 7 = 6 3 2 5


ELOHIM = 8 6 in Hebrew, and the first occurrence of this number completes at digit # 7 5,

and digit # 7 5 has 2 3 6 8 + 1 5 9 0 + 6 6 6 + 1 5 9 0 + 2 3 6 8 digits

between it and digit # 8 6 5 8




ISRAEL = 5 4 1 in Hebrew

7 7 7 7 - (9 x 5 4 1) = [ 1 5 9 0 + 1 3 1 8 ]

7 7 7 7 - 5 4 1 0 = 2 3 6 7

7 7 7 6 + 6 6 6 + 2 1 6 = 8 6 5 8

777, post # 165
7777, post # 174


The first occurrence of 6 6 6 9 8 7, begins at digit # 4 8 6 6 5 8

[Scott]

Rev. 1 3 : 1 8 say's, "count the number 6 6 6"

1 2 3 4 5 6 7 8 9 0

1 2 3 + 6 6 6 = 7 8 9 { the 4 5 and 0 of the set are not utilized yet),

6 x 6 x 6 = 2 1 6

6 6 6 - 2 1 6 = 4 5 0

6 6 6 + 2 1 6 = 8 8 2

1 5 9 0 + 1 3 8 0 + 1 5 9 0 = [4 5 6 0] + 1 5 9 0 + 9 1 8 + 1 5 9 0 = [8 6 5 8]

My Son's name is 1 3 8 0, My wife's name is 9 1 8



Here's how many digits are covered by the first occurrence of 8 8 2

and the first occurrence of my name, 1 5 9 0

3 . 1 4 . . . . . . . . . (8 8 2 . . . . . . 1 5 9 0 + 1 3 1 8 + 1 5 9 0 . . . . . . 1 5 9 0)


4 5 0 + 2 1 6 = 6 6 6


6 6 6 digits, that begin with the 4 digits of my name's first occurrence,

divide at 4 5 0 and 2 1 6 on the last digit of the first occurrence of 1 3 1 8

3 . 1 4 . . . . 1 5 6 . . . . (1 5 9 0 . . . . 4 5 0 . . . . 1 3 1 8| . . . . 2 1 6 . . . . 2 3 2 7 8)

Digit # 2 3 2 7 is the first digit of the first occurrence of 1 5 6 {God)

3 2 7 8 is, 9 1 1 paired with 2 3 6 7


First occurrence of 8 6 and 1 5 6,

3 . 1 4 . . . . .(8 6 . . . . 1 5 9 0 + 6 6 6 . . . . . 1 5 6)


First occurrence of 8 6 and 6 6 6,

3 . 1 4 . . . . .(8 6 . . . . . . . . 2 3 6 8 . . . . . . . . . 6 6)6


First occurrence of 6 6 6, 1 9 6 3 and 1 5 9 0,

3 . 1 4 . . . . . . . . . . (6 6 6 . . . . . 2 3 6 8 . . . . . 1 9 6 3)( . . . . 5 7 . . . . )1 5 9 0

I was born 5 7 yrs ago on Jan.1st 1 9 6 3

Elohim = 8 6 { Hebrew
God = 1 5 6 { English
Jesus Christ = 2 3 6 8 { Greek
Jesus Christ = 9 0 6 { English / A=6 B=12 C=18 . . . Z=1 5 6

[Scott]

4 0 3 2 completed years beginning with Adam and Eve, in the year 4 0 3 3, the year

Jesus Christ was crucified, raised back to life, assured us he would return, then ascended into Heaven,

1 5 3{Fish) + 6 6 6 + 3 2 1 3 = 4 0 3 2



My birth date,

January First Nineteen Sixty Three = 2 4 0 6 ) + 1 5 9 0 = 3 9 9 6

1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8

1 + 2 + 3 + 4 . . . . . + 3 6 = 6 6 6

3 6 + 3 9 9 6 = 4 0 3 2



6 6 6 completes its first occurrence at digit # 2 4 4 2

2 4 4 2 + 1 5 9 0 = 4 0 3 2



1 9 9 5 + 1 1 + 7 + 2 0 1 9 = 4 0 3 2

9 0 6 + 1 1 0 7 + 2 0 1 9 = 4 0 3 2

1 x 9 x 9 x 5 = 4 0 5{page 11, post # 102)

4 0 3 2 - 1 9 9 5 (+ 4 0 5 = 2 4 4 2

Rev. 1 3 : 1 8 is verse 2 2 9 of the 4 0 4 verses in the last book.

The first book of the New Testament, Matthew, has 1 0 7 1 verses.

4 0 4 + 6 6 6 = 1 0 7 0

4 0 4 < 6 6 6 > 1 0 7 1