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Thread: 9 1 1

  1. #131
    Join Date
    Aug 2013
    Posts
    390
    Almost 6 month's after starting this thread and giving it the title 9 1 1, because i believed

    that God{1 5 6) was giving me a revelation concerning 9 1 1 of 2 0 1 9

    or 2 0 2 0, he then led me to see this when i punched in my name followed by this year,

    after realizing this year will be 9 + 1 1, 9 1 1's

    1 5 9 0 2 0 2 0 9 1 1


    And when i switched them around i found them at the end of this cluster of digits,

    over 32 million digits after the decimal point,

    2 0 2 0 7 2 1 2 1 1 2 0 1 9 0 8 7 6 1 1 2 0 2 0 1 5 9 0



    From the first digit of the first occurrence of 9 1 1,

    to the first digit of the first occurrence of my name, 1 5 9 0, is,

    1 5 9 0 + 1 5 6 + 1 5 9 0 digits.
    Last edited by Scott; 03-15-2020 at 11:07 PM.

  2. #132
    Join Date
    Aug 2013
    Posts
    390
    "The last Fifty Seven day's"

    If i saw those words written somewhere, or heard them spoken,

    i would instantly think of the 5 7 days from 9 / 1 1 / 2 0 2 0,

    to what i believe stands a very good chance of being the Rapture date,

    1 1 / 0 7 / 2 0 2 0

    "The last Fifty Seven day's" = 1 5 9 0

    9 1 1 begins at digit # 1 5 3 3

    1 5 3 3 + 5 7 = 1 5 9 0



    The Coronavirus disease = 1 5 0 0

    When 2 0 2 0 1 5 0 0 first occurs, its followed by 2 7 2 4 5 4 7 3 6 0 1 2 7 3 0 1 5 9 0

    2 7 2 4 = November Seventh Two Thousand Twenty

    8 6 + 2 3 6 8 = 2 4 5 4

    The Coronavirus = 1 1 2 8, and just 6 digits{months) after its first occurrence, a 9 1 1 occurs.

    1 1 2 8 first occurs starting at digit # 1 4 7 1 8

    6 6 6 first occurs at digit # 2 4 4 0 and completes at digit # 2 4 4 2 *

    6 x 2 4 4 2 + 6 6 = 1 4 7 1 8


    I counted the occurrences of 6 6 6 without going over 1 4 7 2 1 digits because thats

    where 1 1 2 8 completes its first occurrence,

    There are 1 0 occurrences( 1 1 would put us at digit 1 5 8 8 8, and its completed at digit # 1 5 8 9 0)

    The 1 0 th occurrence starts at digit # 1 3 5 9 4

    digit # 1 3 5 9 3 + 1 1 2 8 digits(that begin with 6 6 6) = 1 4 7 2 1 digits that end with digits 1 1 2 8

    1 1 2 8 digits beginning with number 6 6 6 and ending with the number 1 1 2 8,

    and that 1 1 2 8 begins after 1 1 2 4 digits, and 1 1 2 4 + 1 3 1 8 = 2 4 4 2 *


    1 0 x 6 6 6 = 6 6 6 0


    9 / 1 1 / 2 0 2 0
    September Eleventh Two Thousand Twenty = 2 7 6 6

    3 . 1 4 . . . . . . . . 8 6( . . . . . . 9 x 9 1 1 + 6 6 6 . . . . . . 2)7 6 6

    3rd segment of post # 116, p.12 ^

    3 .(1 4 . . . . . 1 5 3 5 . . . . 9 1 1)( . . . . . . . 1 3 + 1 8 + 6 6 6 . . . . . . . . }digit # 2 2 3 2

    Nine Eleven Two Thousand Twenty = 2 2 3 2
    Last edited by Scott; 03-17-2020 at 05:42 PM.

  3. #133
    Join Date
    Aug 2013
    Posts
    390
    9 1 1 + Nine Eleven + 9 + 1 1 + Nine + One + One + 9 + 1 + 1 = 2 2 3 2

    -------------------------------- Nine Eleven Two Thousand Twenty = 2 2 3 2


    Nobody really says the number like this anymore when they see it, but its really 9 1 1 in word form,

    Nine Hundred Eleven = 1 0 7 4

    --- Count the number = 1 0 7 4

    2 2 3 2 + 1 0 7 4 = 1 5 9 0 + 6 6 6 + 1 0 5 0{our host)


    Count the number Six hundred sixty six = November Seventh Two Thousand Twenty{ 2 7 2 4 )
    Page 10, post # 100
    Count the number Six hundred sixty six to reveal the date of The Rapture = 4 6 0 8*

    My name, 1 5 9 0, completes it first occurrence at digit # 4 8 6 9

    At digit # 2 6 1,

    2 3 4 6, which is, "Count the number of the beast{1 6 8 0) + 6 6 6,

    begins to make it's first occurrence.

    2 6 1 + 4 6 0 8* = 4 8 6 9

    A=6 B=12 C=18 D=24 . . . . . Z = 1 5 6 | G O D = 1 5 6

    ELOHIM{GOD) = 8 6 in Hebrew


    3 .(1 4 . . . . . 4 7 7 digits . . . . . . . . 2)7 2 4

    3 .(1 4 . . . . 7 5 digits . . . . 8 6)( . . . . . 4 7 7 + 2 7 2 4 + 1 5 9 0 digits . . . . . 1)5 9 0

    1 5 9 0 + 1 5 9 0 + 1 5 9 0 = 4 7 7 0

    God led me to the date of 2 7 2 4 !
    Last edited by Scott; 03-18-2020 at 12:43 PM.

  4. #134
    Join Date
    Aug 2013
    Posts
    390
    The number 9 1 1 first occurs starting at digit # 1 5 3 3

    3 .(1 4 . . . . . . . . . . . . . . 1 5 3 3 . . . . . . . . . . . . . 9)1 1


    The number 1 5 3 3 first occurs starting at digit # [ 1 1 9 + 9 1 1 ]

    3 .(1 4 . . . . . . . 1 1 9 + 9 1 1 . . . . . 1)5 3 3



    3 . 1 4 . . . . . . . . . . . . . . . . . (2 1 6 . . . . . . . 1 1 9 + 9 1 1 . . . . . . . . }digit # 2 0 2 0



    6 x 6 x 6 = 2 1 6

    6 6 6 - 2 1 6 = 4 5 0

    After the first 1 7 6 verses, The 4 5 0 foot long ARK is LIFT UP,
    and the instruction's to count 6 6 6 begin the last 1 7 6 verses.

    1 7 6 + 3 1 4 + 1 7 6 = 6 6 6


    Heres the first occurrence of 2 0 2 0,

    3 .(1 4 . . . . 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 0 7 . . . . . . . .)2 0 2 0

    May 14 / 2 0 1 8 plus 9 0 7 days, is Nov.7 / 2 0 2 0

    3 .(1 4 . . . . 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 . . . . . . . . . 2 0 2 0)

    The 9th + 11th,....9 1 1, including THE 9 1 1, is 9 / 1 1 / 2 0 2 0

    My name, 1 5 9 0, completes its first occurrence at digit # 4 8 6 9

    3 .(1 4 . . . . . . 1 5 9 0 + 2 3 6 8 + 9 1 1 . . . . . . . . . 1 5 9 0)

    When 1 5 9 0 followed by 2 0 2 0 first occur, they are followed by 9 1 1,

    1 5 9 0 2 0 2 0 9 1 1



    2 0 2 0 1 5 0 0 2 7 2 4

    The Coronavirus disease = 1 5 0 0
    November Seventh Two Thousand Twenty = 2 7 2 4
    That's the first occurrence of 20201500 that i looked for,
    and it was followed by the gematria sum of the date that i was
    previously led to. {post # 132)


    Coronavirus disease = 1 3 0 2

    It first occurs immediately after the 3rd occurrence of 2 0 1 9,

    2 0 1 9 1 3 0 2
    Last edited by Scott; 03-20-2020 at 08:57 AM.

  5. #135
    Join Date
    Aug 2013
    Posts
    390
    1 5 6 + 9 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 = 3 5 3 4

    3 5 3 4 first occurs starting at digit # 2 3 6 8

    9 1 1 first occurs at digit # 1 5 3 3

    The number 1 5 3 3 completes its first occurrence at digit # 1 0 3 3

    digit # 1 0 3 3 + 1 5 9 0 + 9 1 1 = digit # 3 5 3 4


    1 3 0 2 + 2 2 3 2{post 133) = 3 5 3 4, which first occurs

    at digit # Jesus Christ{2 3 6 8)
    Last edited by Scott; 03-20-2020 at 04:19 PM.

  6. #136
    Join Date
    Aug 2013
    Posts
    390
    2 0 1 9 1 3 0 2{first occurrence of 1 3 0 2)

    Coronavirus + Disease + Coronavirus

    = Nine Eleven Two Thousand Twenty{2 2 3 2)Post # 133


    The last normal 9 1 1 before THE 9 1 1, that was the

    First of, 9 + 1 1,...9 1 1's, was,

    Nine Eleven Two Thousand = 1 5 9 0


    When my name 1 5 9 0 and 2 0 2 0 first occur

    together in that order,

    1 5 9 0 2 0 2 0 9 1 1


    Nine Eleven Two Thousand One = 6 6 6 + 2 1 6 + 9 1 2

    Only even number results with this system of gematria,

    so the answer HE chose was 9 1 2 instead of 9 1 0.

    A fully completed number 9 1 1, puts us in the threshold of 9 1 2,

    1 2 3 + 6 6 6 = 7 8 9
    1 2 3 + 7 8 9 = 9 1 2
    Last edited by Scott; 03-22-2020 at 11:50 AM.

  7. #137
    Join Date
    Aug 2013
    Posts
    390
    The Coronavirus disease = 1 5 0 0
    The Coronavirus = 1 1 2 8

    Here's the first occurrence of 1 5 9 0 followed by 1 5 0 0, and the numbers

    that follow,

    1 5 9 0 1 5 0 0 3 4 4 1 0 7 6 2 1 0 0 1 1 9 1 1 2 8)

    1 5 9 0 1 5 0 0 3, is, 9 digits, and 1 1 more digits brings us to this digit, 1)1 9 1 1 2 8

    1 1 9 1 1{ post # 134)

    The first occurrence of 1 1 2 8 also has a 9 1 1 occurring shortly after (7 digits).
    Last edited by Scott; 03-23-2020 at 03:34 PM.

  8. #138
    Join Date
    Aug 2013
    Posts
    390
    1 5 9 0 + 7 9 8 + 9 8 7 + 1 9 9 5 = 5 3 7 0{post # 102)

    5 3 7 0 completes its first occurrence at digit 2 8 8 6,

    3 . 1 4 . . . . . . . . . 5 3 7 0(. . . . . . . 1 3 1 8 + 6 6 6 digits . . . . . 7 5 1 5 9 0 6) {post # 114)




    3 . 1 4 . . . . . . . . (1 5 9 0 . . . . . 4 5 0 digits . . . . 1 3 1 8)( . . . . . . 2 1 6 digits . . . . )



    6 6 6 digits, starting with the first occurrence of the four digits in Pi that are the gematria sum of my name,

    will split at 4 5 0 and 2 1 6 right at the 8 of the first occurrence of 1 3 1 8 {post #'s 94, 95, 134)

    Being born Jan.1st 1963 puts me at 5 7 years of age this year.
    Heres where God placed 1963 and 1590's first occurrence,

    3 . 1 4 . . . . . . . . . . . 1 9 6 3( . . . . . . . 5 7 digits . . . . . . )1 5 9 0


    In the year Two Thousand = 1 5 9 0 = Nine Eleven Two Thousand{Post # 136)

    In the year Two Thousand One = 6 6 6 + 2 1 6 + 9 1 2 = Nine Eleven Two Thousand One

    In the year Two Thousand Twenty = 2 2 3 2 = Nine Eleven Two Thousand Twenty{Post # 136)
    Last edited by Scott; 03-25-2020 at 11:37 AM.

  9. #139
    Join Date
    Aug 2013
    Posts
    390
    Midnight of the end of May 14th 1948 + 2 6 4 1 9 days, brings us to the end of 9 / 1 1 / 2 0 2 0

    The leap years 1948 and 2020, and all the leap years in between are 19 in total{1 + 6+6+6)
    The first one, is before May 14th 1948

    Israel is 2 9 x 9 1 1 days old at the end of 9 / 1 1 / 2 0 2 0

    2 9 x 9 1 1 = 2 6 4 1 9

    2 9 + 6 6 6 + 2 1 6 = 9 1 1

    6 6 6 completes its first occurrence at digit # 2 4 4 2

    2 4 4 2 + (3 6 x 6 6 6) digits = 2 6 4 1 8

    It will still be 2 6 4 1 8 days in the morning of 9 / 1 1 / 2 0 2 0


    ISRAEL = 5 4 1{Hebrew)

    1 5 6 + 2 9 + 5 4 1 + 2 9 + 1 5 6 = 9 1 1

    <><><><><><><><><><><><><><><><><><><>

    123 - 456 - 789 - 0


    123 - 45 - 6 - 789 - 0

    1 4 6 7 0 + 1 5 9 0 + 4 8 7 0 = 2 1 1 3 0

    7 5 1 5 9 0 6 completes its first occurrence at digit # 4 8 7 0.

    I will have lived 2 1 1 3 0 days{post # 74, p.8) on Nov.7th 2020

    This experience began just as i was turning 1 0, 3 1 1 days old on day 8 6 of 1 9 9 1.

    1 0, 3 1 1 + 1 9 9 1 + 2 3 6 8 = 1 4 6 7 0 (+ 1 5 9 0 + 4 8 7 0 = 2 1 1 3 0
    Last edited by Scott; 03-26-2020 at 11:19 AM.

  10. #140
    Join Date
    Aug 2013
    Posts
    390
    First occurrence of, Elohim = 8 6

    First occurrence of, 0 9 1 1 0 1 { 0 9 / 1 1 / 0 1 ),

    First occurrence also of, 9 1 1 0 1


    3 . 1 4 . . . . . . (8 6 . . . . . . . . . . 9 x 9 1 1 digits . . . . . . . . . . . . . . 0 9 1 1 0 1)


    3 .(1 4 . . . . . . . . . . . . . . . . . . . . 8 x 9 1 1 digits . . . . . . . . 2 0 2 0){ first occurrence )


    3 . 1 4 . . . . . . (8 6 . . . . . . . . 2 3 6 8 digits . . . . . . . 6 6 6




    First occurrence of 9 1 1 and 6 6 6,


    3 . 1 4 . . . . . . (9 9 1 1 . . . . . . 9 1 1 digits . . . . . . 6 6 6)


    9 1 1 first begins to occur at digit # 1 5 3 3

    1 5 3 3 first begins to occur at digit # [ 1 1 9 + 9 1 1 ]




    3 . 1 4 . . . . . . . . (8 6 . . . . . . . 6 6 6 + [ 4 x 2 2 5 6 ] digits . . . . . . 2 2 5 6)

    1 5 9 0 + 6 6 6 = 2 2 5 6



    3 . 1 4 . . . . . . . . (8 6 . . . . . . 6 6 6 + 1 5 9 0 digits . . . . . . 1 5 6)


    3 . 1 4 . . . . . . . . . . . . . . . .(9 0 6 . . . . . 1 3 1 8 + 4 8 7 0 digits . . . . . )2 3 6 8


    3 .(1 4 . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 digits . . . . . . . 7 5 1 5 9 0)6{ digit # 4 8 7 0 )




    When i punched in the first occurrence of 1 5 9 0 2 0 2 0, 9 1 1 followed!

    9 / 1 1 / 2 0 2 0 will be 9 + 1 1, . . . 9 1 1's including the first 9 1 1


    Last year on 9 1 1 , i was 22 x 9 1 1 + 6 6 6 days old.{entering day 2 0 7 0 9 at the completion of

    the day.

    2 0 7 0 9 makes its first occurrence right before the first occurrence

    of 2 2 3 2{Nine Eleven Two Thousand Twenty)
    Last edited by Scott; 03-27-2020 at 10:14 PM.

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