### Bible Wheel Book

1. Senior Member
Join Date
Aug 2013
Posts
273
i was born at the start of the 1st day of 1 9 6 3, and i will be 2 0 7 6 6 days on Nov.7th's end, because of

being just a few months away from gaining a full leap year day, and

the number 2 0 7 6 6 completes its 1st occurrence at digit 9 1 3 5 in Pi.

When i counted from the start of the 1st occurrence of 1 9 6 3, to the completion of 2 0 7 6 6 at digit 9 1 3 5

i counted 1 9 6 3 digits, plus another 2 3 6 8 digits, and i landed right on digit 9 1 3 5

so the first 4 digits of the 1 9 6 3 digits are 1, 9, 6, and 3

3 . 1 4 . . . . . . . . . ( 1 9 6 3 . . . . . . . . { 1 9 6 3 + 2 3 6 8 digits } . . . . . . . 2 0 7 6 6 )

1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ] = [ 6 6 5 {666) + (3294} 3 2 9 3 ]

My name, 1 5 9 0, begins at digit 4 8 6 6,

3 . 1 4 . . . . . . . . . . . . ( 1 5 9 0 . . . . . . . { 1 5 9 0 0 digits } . . . . . . to reach . . . . . . . [ digit 2 0 7 6 6 ]

and the 1 5 9 0 0 digits begin with a 1, 5, 9, and 0

At the time i turned 5 7 years from conception, God showed me that my birth year occurs

very close to my name.....separated by 5 7 digits

3 . 1 4 . . . . . . . . . . . 1 9 6 3 }. . . . . . . [ 5 7 digits ] . . . . . . { 1 5 9 0

1 5 9 0 counted the number of the beast = 3 3 2 4

In terms of Pi, if we subtract the first 9 9 3 digits,..because the result of counting 6 6 6 (2 1 6) completes at digit 9 9 3,

2 3 3 1 digits are left to reach digit 3 3 2 4,

and "position" 2 3 3 1 (3 and . are position 1 and 2) G O D = 1 5 6 completes its first occurrence.

1 5 6 + *2 0 1 9 + 1 5 6 = 2 3 3 1
1 5 6 + *1 1 7 + 1 5 9 0 + 1 5 6 = 2 0 1 9

and,

3 . 1 4 . . . . . . . . . . ( 8 6 . . . . . . . . [ 1 5 9 0 + 6 6 6 digits ] . . . . . . . . . . . 1 5 6 )

ELOHIM in Hebrew is 8 6
G O D in English is 1 5 6

I checked the measurement in digits between my wifes maiden name gematria sum, 9 1 8,

and my name 1 5 9 0, and found that from the first digit of her name, to the last digit of my name

is this many digits,

3 . 1 4 . . . . . . . . . . . . . . . 9}1 8 . . . . . . . . [ 6 6 6 + 1 3 1 8 + 6 6 6 digits ] . . . . . . . . . 7 5 1 5 9 0 6 )

If we include the first digit of her name as digit 1, and include the 6, of the 7 5 6 that 1 5 9 0 is tucked into,

then the amount of digits are,

G O D(1 5 6) + JESUS CHRIST(9 0 6) + 1 5 9 0 digits
Last edited by Scott; 10-30-2019 at 01:26 PM.

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