# Thread: 9 1 1

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Correction in the last post,

I just added todays date after finding this in Pi, should have been,

1 5 9 0 2 0 2 0 9 1 1

God pointed out to me,

that last year i was 2 2 x 9 1 1 + 6 6 6 days old on 9 / 1 1

On March 27th 1991, God led me to discover "The 4 5 0 and 6 6 6 Code" = 1 5 9 0

and i quickly noticed that what i had done, had divided the 9 numbers into a group of

3, 2, 1 and 3 whichs creates the number

3, 2 1 3

and the very next thing God had me do, was to find a larger number than

Enoch's Rapture year, 9 8 7, that had digits performing the same 3 features as 9 8 7,

and the only number that does, is 1 9 9 5,

and when i learned of increments of 6 gematria and discovered my name was

1 5 9 0, i remembered back 1 8 yrs earlier

when i counted 1 9 9 5 and subtracted the answer from 1 9 9 5

just as i had done with 6 6 6, and the answer was 1 5 9 0

Heres the location God chose for my name to occur after the decimal point,

3 .(1 4 . . . . . . . 6 6 6 + 3 2 1 3 + 9 8 7 . . . . . . . . 1)5 9 0

3 . 1 4 . . . . . . . . . . . (2 1 6 . . . . . . 6 6 6 + 3 2 1 3 . . . . . . 1 5 9 0)
Last edited by Scott; 03-01-2020 at 11:03 AM.

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1 5 9 0 + 1 2 3 + 4 5 + 6 6 6 + 7 8 9 = 3 2 1 3

Count the number of the beast = 1 6 8 0

Here's the measurement's in digits, from the first occurrence of 6 6 6,

to the first occurrence of 1 6 8 0,

3 . 1 4 . . . . . . (6 6 6 . . . . 1 6 8 0 + 6 6 6 + 6 6 6 6 + 6 6 6 + 1 6 8 0 . . . . )1 6 8 0

Had i included one more digit, the 1 from the 1 6 8 0,

7 5 6 + [ 1 5 9 0 + 8 2 5 6 ] + 7 5 6{post #'s 94, 95)

6 6 6 6 + 1 5 9 0 = 8 2 5 6{post # 116)

Increments of 6 is the correct English gematria method,

its in perfect harmony with the digits of Pi.

In terms of Pi, digit # 8 2 5 6 occurs 1 5 9 0 + 3 2 1 3 + 3 3 7 8 digits

after the first occurrence of 8 6{ELOHIM),

Saturday November Seventh Two Thousand Twenty = 3 3 7 8

<><><><><><><><><><><><><><><><><><>

1 5 9 0 + 1 3 1 8 = 2 3 6 7 + 5 4 1 or, 2 3 6 8 + 5 4 0

ISRAEL = 5 4 1, shares the same space so to speak, with the 2 3 6 8 th, JESUS CHRIST
Post # 119
Last edited by Scott; 03-02-2020 at 11:52 AM.

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I checked to see what was starting to occur, or completing, at digit # 5 7,

which is, my years of age as of Jan.1st 2020.

The number 2 0 9 7 4 is completed at digit # 5 7

Thats my age in days on June 4th 2020, which is day 1 5 6

of the year this year, because its a leap year.

1 5 6 days after June 4th 2020, is Nov.7th 2020

I'll be 5 7 years, 1 5 6 + 1 5 6 days old on Nov.7th 2020

<><><><><><><><><><><><><><><><><>

1 5 8 9 + 6 6 6 + 9 1 1 + 2 7 2 4 = 5 8 9 0

The first occurrence of 666 looks like this,

6 6 6 7

so i looked for the first occurrence of this,

7 6 6 6

and found it completed at digit # 1 5 8 9 0

<><><><><><><><><><><><><><><><><>

9 1 1 begins to occur at digit # 1 5 3 3

1 5 3 3 + 5 7 = 1 5 9 0

My name = 1 5 9 0, i'm 5 7 for the year 2 0 2 0, and God is giving me a revelation about 9 1 1

So i looked up the first occurrence of 1 5 9 0 2 0 2 0, it occurred starting at digit # 97,682,187

and the 3 digits that followed were 9 1 1

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3 .(1 4 . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . . 1 5 9 0)
Last edited by Scott; 03-03-2020 at 02:59 PM.

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Here's where God decided the first occurrence of number 1 5 3 3 would be located,

Digit # 1 5 3 3 is where the first 9 1 1 is located and begins.

3 .(1 4 . . . . . . . 1 1 9 + 9 1 1 . . . . . . 1)5 3 3

The first 1 5 3 3 is starting to occur at digit # [ 1 1 9 + 9 1 1 ]

The first 9 1 1 is starting to occur at digit # 1 5 3 3

3 .(1 4 . . . . . . . . 1 5 3 3 . . . . . . . . 9)1 1

1 5 3 3 + 5 7 = 1 5 9 0

God chose to show me these 9 1 1 designs at the age of 5 7, in the year 2 0 2 0,

and chose digit # 1 5 3 3, for the first occurrence of 9 1 1 to begin,.....for that reason!

1 5 3 3 + 2 0 2 0 = 1 9 6 3 + 1 5 9 0

Thats why the first occurrence of my name followed by the present year, is followed by 9 1 1,

3 . 1 4 . . . . . . . . . . . . . . . . . . 1 5 9 0 2 0 2 0 9 1 1

Simple, but, "designed and planned mathematics", to show me it was
HIS plan that i make these 9 1 1 discoveries!

<><><><><><><><><><><><><><><><><><>

3 . 1 4 . . . . . . . . (9 1 1 . . . . . . .9 1 1 . . . . . . 6 6 6 7)
Last edited by Scott; 03-04-2020 at 04:40 PM.

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Backing up 5 7 years from 2 0 2 0 puts us at 1 9 6 3, my birth year.

If we back up 3 5 groups of 5 7 years, we are at the year 2 5​,

which is
3 2 years shy of being the 3 6 th group of 5 7.

Starting from 0, 3 5 x 5 7 years = 1 9 9 5

1 9 9 5 + 2 5 = 2 0 2 0
(post # 101 ^)

1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8
(post # 102 ^)

That's why 5 7 digits are separating the first occurrence of 1 9 6 3,

from the first occurrence of 1 5 9 0,

3 . 1 4 . . . . . . . . . . . . 1 9 6 3( . . . . . 5 7 . . . . . . )1 5 9 0

<><><><><><><><><><><><><><><><><><><><><><><><>

3 .(1 4 . . . . . 9 9 0 . . . . . . )(2 1 6 . . . . . . 1 1 9 + 9 1 1 . . . . . .}digit # 2 0 2 0

9 9 0 + 1 1 9 = 1 1 0 9 ( + 9 1 1 = 2 0 2 0

9 1 1 begins it's first occurrence at digit # 1 5 3 3

1 5 3 3 begins it's first occurrence at digit # 1 1 9 + 9 1 1

<><><><><><><><><><><><><><><><><><><><><><><><>

September Eleventh Two Thousand Twenty = 2 7 6 6

3 . 1 4 . . . . . . . . . . . (8 6 . . . . . . . . . 8 8 6 6 . . . . . )2 7 6 6

9 x 9 1 1 + 6 6 7 = 8 8 6 6

Here again, is the first occurrence of 9 1 1 and 6 6 6,

3 . 1 4 . . . . . . . . . . . 9(9 1 1 . . . . . . . . . 9 1 1 . . . . . . . . . 6 6 6 7)
Last edited by Scott; 03-06-2020 at 11:27 PM.

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The factors of 1 5 9 0,

2 x 3 x 5 x 5 3 = 1 5 9 0

2 3 5 5 3 - 1 1 9 6 3 = 1 1 5 9 0

digit # 1 1 9 6 3 + 9 1 1 0 = digit # 2 1 0 7 3

I will be 2 1 0 7 3 days old on 9 / 1 1 / 2 0 2 0

Last year i was 2 2 x 9 1 1 + 6 6 6 days old on 9 / 1 1

3 . 1 4 . . . . . . . (2 1 6 . . . . . 2 0 1 9 . . . . . . . . . . . . )0 9 5 1

This is what follows that first 2 1 6,

2 1 6 (4(2 0 1 9 8 9 . . . . . . . 2 0 1 9 or 2 0 2 0 . . . . . . 0 9 5 1)

We have completed 1 9 8 9 years from the Crucifixion.

That's the 3rd occurrence of 2 0 1 9, and the 2nd is meshed with 1 9 9 5's 1st

2 0 1 9 9 5
Last edited by Scott; 03-07-2020 at 04:07 PM.

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Ivan Panins rendering of Rev. 1 3 : 1 8, only slightly modified

to sound like todays modern English,

Here is the wisdom, who has understanding, let him count the

number of the beast, it is the number of a man, his number

is Six hundred sixty six

= [ 2 7 6 6 + 2 7 2 4 + 2 7 6 6 ]

Could that be the 9 1 1 of 2 0 2 0 leading up to

the 1 1 7 of 2 0 2 0 ?

September Eleventh Two Thousand Twenty = 2 7 6 6

November Seventh Two Thousand Twenty = 2 7 2 4
=======================================

7 / 1 1 + 1 1 9 day's = 1 1 / 7

=======================================

3 2 1 3 - 1 6 8 0{Count the number of the beast) = 1 5 3 3

Digit # 1 5 3 3 is where 9 1 1 {preceded by a 9) begins its first occurrence.

The reverse of 3 2 1 3,

3 1 2 3 - 1 5 9 0 = 1 5 3 3

3 . 1 4 . . . . . . . . . (9 9 1 1 . . . . . . . .9 1 1 . . . . . . . . 6 6 6)

Digit # 1 5 3 3{9 1 1 begin's) + 1 6 8 0 = 3 2 1 3 digits

=======================================

The sum of the letters in the English alphabet = 2 1 0 6

1 5 9 0 + 7 5 6 = 1 6 8 0 + 6 6 6

1 5 x 9 0 + 7 5 6 = 2 1 0 6
1 6 x 9 0 + 6 6 6 = 2 1 0 6
756 post # 69

3 2 1 3 - 2 1 0 6 = 1 1 0 7

8 6 + 1 1 0 7 + 2 0 2 0 = 3 2 1 3 { post #'s 64, 107)
Last edited by Scott; 03-09-2020 at 11:56 AM.

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3 2 1 3 - 1 1 0 7 = 2 1 0 6{sum of the alphabet)

2 1 0 6 - 2 0 2 0 = 8 6

3 2 1 3 - 2 0 2 0 = [ 6 6 6 + 2 1 6 + 3 1 1 ]

3 1 1 days of 2 0 2 0 completed, is the beginning of 1 1 / 0 7

The 3 1 1 tells me that the 1 1 0 7 and 2 0 2 0 is in fact the date that

is the measurement from digit # ELOHIM = 8 6, to, digit # 3 2 1 3

3 of every 4 yrs 11 / 0 7 is day 3 1 1 of the year.

In terms of the positions of Pi{ 3 and . are position 1 and 2),

GOD = 1 5 6 completes at position 2 3 3 1 { 7 7 7 + 7 7 7 + 7 7 7 }

2 3 3 1 + 6 6 6 + 2 1 6 = position 3 2 1 3

2 3 3 1 - 3 1 1 = 2 0 2 0

All the positions after position 1 of Pi, the 3, are 3 1 1 + 2 0 1 9 positions beginning

with the decimal point where the change takes place as position 1, instead of the 3 preceding the

decimal point.

God began giving me this 9 1 1 revelation after i turned 5 7 yrs from conception.

1 5 9 0 - 5 7 = 1 5 3 3{ 9 1 1 first occurs starting at this digit # )

The number that was instrumental in helping me bring this whole thing into focus, was the 5 4 1 that God

shed light on for me 5 4 1 days after the Rev. 1 2 Sign on 9 / 2 3 /2 0 1 7, at 5 6 yrs of age,

by showing me that ISRAEL = 5 4 1, and that 5 4 1's first occurrence follows the first occurrence

of May Fourteenth Two Thousand Eighteen{=2 4 2 4) in Pi's digits. { post # 1 1 9 )

5 6 + 3 1 4 {Pi) + 5 4 1 = 9 1 1

If we back up 5 4 1 digits from the completion of the first 9 1 1,

we are at digit # 9 9 5, and the 3rd occurrence of 2 0 1 9 starts at digit # 9 9 5

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My name 1 5 9 0 completes its first occurrence at digit # 4 8 6 9

The number 4 8 6 9 begins its first occurrence at digit # 2 2 5 0 6

6 6 6 + 1 5 9 0 = 2 2 5 6

6 6 0 6 + 1 5 9 0 0 = 2 2 5 0 6

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Elohim(=86)

allowed, in his timing,

Jesus Christ(=2 3 6 8, and a placement value of 8 7 among the letters of the Greek alphabet)

to be crucified year 4 0 3 2 from Adam,

8 7 + 2 3 6 8 + 6 6 6 + 9 1 1 = 4 0 3 2
Last edited by Scott; 03-11-2020 at 08:05 AM.

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9 1 1 and 1 1 2, are the world's standard emergency numbers,

3 .(1 4 . . . . . 7 1 1 . . . . 1 1 2| . . . . . . . 1 5 6 + 6 6 6 . . . . . . 9)1 1

================================================== ===

The man that started this site has 1 0 5 0 for the sum of his name,

and when i backed up 3 1 4{3.14) digits, with the 6 of 2 1 6's

first occurrence as digit 1 of the 3 1 4 digits,...counting backwards, digit 3 1 4 was the first

digit of the first occurrence of his name.

These numbers follow the first 2 1 6,
4 2 0 1 9 9 5

This is what shows up at the first occurrence of 1 0 5 0 1 5 9 0

starting at digit # 4 2, 3 6 4, 1 9 5

1 0 5 0 1 5 9 0 0 2 0 2 0 3 6 7

1 0 x 1 0 5 0 + 1 = 1 0 5 0 1
___ 1 0 x 1 5 9 0 = 1 5 9 0 0
________________ 2 0 2 0 3 6 7

The 4 digit number that 1 0 5 0 1 5 9 0 sits in the middle of, is, 3 7 0 2

1 5 6 + 1 0 5 0 + 1 5 9 0 + 9 0 6 = 3 7 0 2

I came on this site to show him and other's, what i thought was compelling evidence

for 2 0 1 9 or 2 0 2 0 being the year of the return of 2 3 6 8

for his Bride.

I believe now, that i was to show him, that following the instructions of Rev. 1 3:1 8

reveals the time of 2 3 6 8's Return,

1 0 5 0 + 1 3 1 8 = 2 3 6 8

3 .(1 4 . . . . . 6 1 2 + 6 6 6 + 1 0 5 0 . . . . . . 1 5)(6 . . . . . . 1 0 5 0 . . . . . }digit # 3 3 7 8{Sat. 11/7/20)

3 .(1 4 . . . . . 6 6 6 + 2 1 6 + 1 0 5 0 + 1 0 5 0 . . . . . . . . . . . . . . . }digit # [ 9 8 7 + 1 9 9 5 ]

The first occurrence of 8 6 1 0 5 0, has this 4 digit number precede it,

6 6 6 7 8 6 1 0 5 0

6 6 6 7 is seen at the first occurrence of 6 6 6, 4 6 1, 2 3 6 digits back

completing at digit 2 4 4 3, which is 9 1 1 digits from the start of the first occurrence of 9 1 1

This first occurrence, 9 1 1, and this first, 6 6 6 7,

cover a span of exactly 9 1 1 digits, and the first 3 are, 9 1 1
Last edited by Scott; 03-12-2020 at 10:32 AM.

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1 7 6 + 3 1 4 + 1 7 6 = 6 6 6

After the first 1 7 6 verses of The Bible, the 4 5 0 foot long Ark is Lift Up above the earth

At the start of the last 1 7 6 verses, instructions are given to count 6 6 6

1 2 3 + 6 6 6 = 7 8 9

4, 5 and 0 have not been utilized yet,

6 x 6 x 6 = 2 1 6

6 6 6 - 2 1 6 = 4 5 0

==================================================

3 . 1 4 . . . . . . . . . . . . . (1 0 5 0 . . . . . . . . . . 3 1 4 . . . . . . . . . 2 1 6 4)2 0 1 9 9 5

3 . 1 4 . . . . . . . . . . . . . 1 0 5 0( . . . . . . . . . . . 3 1 4 . . . . . . . . . . . . . . 2 0 1 9)9 5

3 .(1 4 . . . . . . . . . . . . . . . . . 1 0 5 0 + 1 3 1 8 digits . . . . . . . . . . . . . . . . . . }digit # 2 3 6 8

1 5 6 + 9 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 = 3 5 3 4

3 5 3 4 begins its first occurrence at digit # 2 3 6 8
Last edited by Scott; 03-13-2020 at 08:42 AM.

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