I've subtracted 6 6 6 + 2 1 6 from my name value 1 5 9 0, once i knew it was, many times, but could never figure out

what the 7 0 8 was that remained...until now, when i applied my name to the digits of Pi, at the age

of 5 6

3 . (1 4 . . . . . . . . . { 7 0 8 digits } . . . . . . . 2 0 1 9 9 5 6) . . . . . . . . . . . . { 6 6 6 + 2 1 6 digits } . . . . . . . . . [ digit 1 5 9 0 ]

That's the 2nd occurrence of 2 0 1 9 and 1 9 9 5's 1st

THE FLOOD End's + 2 3 6 8 yrs. + 1 9 9 5{matches 9 8 7,Enoch) yrs. = 2 0 1 8/1 9, which is 6 0 2 0/2 1 from Adam

and very likely there may only be a certain number of days remaining!.

"The Bread of God(is J.C.)" = 1 9 9 5 {Greek)

1 6 5 6 yrs, THE FLOOD Begins, this is the 4 digit number that follows the 1st occurrence of 1 6 5 6 in Pi,

3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . .1 6 5 6)6 1 3 9

This is the 4 digit number you see begin at digit 6 1 3 9,

3 . (1 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . { 6 1 3 9 digits } . . . . . . . . . . . . . . . . . . . . . 6)0 2 0 ^

year 1 6 5 6 when it occurs, is followed by digits 6 1 3 9

year 6 0 2 0 occurs at digit 6 1 3 9

ELOHIM}86 1590 666 156{GOD

3 . 1 4 . . . . . . . . . . . . ( 8 6 . . . . . . . . . { 1 5 9 0 + 6 6 6 digits } . . . . . . . .1 5 6 )

86 2368 666

3 . 1 4 . . . . . . . . . . . . . 8(6 . . . . . . . . . . . . { 2 3 6 8 digits } . . . . . . . . . . . . . . . . .6 6 6 )

1963 + 1995 = 1590 + 2368 = 6 6 5 + 3 2 9 3 {3 9 5 8 total

The 1st occurrence of 3 9 5 8 ends at digit 1 8 7 2 4

Digit 1 8 7 2 4 + [ November Seventh Twenty Twenty = 2 4 0 6 digits ] = digit 2 1 1 3 0 which are exactly my day's on Nov.7th 2020 ?

My birth} January First Nineteen Sixty Three = 2 4 0 6

1 + 2 + 3 + 4 . . . . . . .+ 3 6 = 6 6 6

Rev.}1, 3 : 1 8 + 6 6 6 + 3 6 = 2 0 2 0

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