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  1. #111
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    ( 3 . (1 4 . . . . . . . 1 5 3 3 digits . . . . . 9)(1 1 . . . . . The last 9 1 1 positions . . . . . 6 6 6)


    The first completed occurrence of 6 6 6 in Pi,

    is position 2 4 4 4, position 1 and 2 is, 3 and .

    1 5 3 3 + 9 1 1 = 2 4 4 4

    The first occurrence of 9 1 1 starts at digit 1 5 3 3

    So the first three digits of the last 9 1 1 to reach the completion

    of the first occurrence of 6 6 6, which is position 2 4 4 4,

    are 9, 1, and 1


    3 .(1 4 . . . . . . . . . . . . . . 3 1 4 + 1 5 9 0 . . . . . . . . . . . . . . . . . . . .}digit # 1 9 0 4

    3 .(1 4 . . . . . 9 9 3 . . . . . 2 1 6)(4 2 0 1 9 . . . . . 9 1 1 . . . . . . . . }digit # 1 9 0 4

    Digit # 1 9 0 4{ . . . . . . . . . . . . 2 4 2 4 + 5 4 1 . . . . . . . . . . . . . 1 5 9 0)

    2 4 2 4 5 4 1 has been explained in several post's..


    More on 911 in post #'s 104, 105, 110 | 2 4 2 4 5 4 1, post # 70, page 7, page 4, post # 40

    I counted the digits from the first 2 1 6's completion, to the completion of my name 1 5 9 0,

    and removed 1 5 6 from the center, and it was flanked with 1 8 6 0, and then 2 days later i find this,

    3 . 1 4 . . . . . . . . . . 2 1 6( . . . . . . . 1 8 6 0 + 1 5 6 . . . . . . )(0 9 5 1 . . . . 1 8 6 0 . . . . 1 5 9 0)

    3 . 1 4 . . . . . . . . . . 2 1 6( . . . . . . . 2 0 2 0 . . . . . . . . . . . . 0 9 5 1)


    5 7 + 1 5 6 + 1 5 9 0 + 5 7 = 1 8 6 0

    1 8 6 + One Hundred Eighty Six = 1 5 9 0

    1 8 6 + 3 6 + 6 6 6 = 8 8 8 ( + 3 6 + 6 6 6 = 1 5 9 0



    3 .(1 4 . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . . . . 1 5 9 0)


    3 1 4 ^ + 9 1 1 + 9 1 1 + 9 1 1 + 9 1 1 = 2 3 6 8 + 1 5 9 0
    Last edited by Scott; 02-18-2020 at 06:58 PM.

  2. #112
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    ^ 1 8 6 0 + One Thousand Eight Hundred Sixty = 1 5 9 0 + 2 4 0 6

    January First Nineteen Sixty Three = 2 4 0 6
    November Seventh Twenty Twenty = 2 4 0 6



    I counted my days of life, for 9 /1 1 / 2 0 1 9, which was

    6 + 6 + 6 years after THE 9 1 1,

    2 0 7 0 8 days,

    2 2 x 9 1 1 + 6 6 6 = 2 0 7 0 8



    3 .(1 4 . . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . . . . . . 1 5 9 0)


    This will be the 2 0 th 9 / 1 1, from, and including THE 9 1 1

    9 + 1 1 = 2 0

    ==================================================

    I don't know if it means anything or not, but if you look for the first occurrence of 2 0 2 0 in Pi,
    you will see it occurring in, and with tomorrows date, 2 / 2 0 / 2 0 2 0,

    2 2 0 2 0 2 0
    Last edited by Scott; 02-19-2020 at 06:26 PM.

  3. #113
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    A number that resembles todays date, 2 / 2 0 / 2 0 2 0, occurs for the first time,

    with the first occurrence of 2 0 2 0{and it's combined with its 2nd,...emphasis on 2 0 2 0)

    If the digits of Pi are not laid out by intelligent thought, then, its by chance that the numbers surrounding

    2 0 2 0' first occurrence, create a sequence that looks like it was intended to be a date associated

    with the year 2 0 2 0's first occurrence, and it just happened to be a 2 and a 2 0 at each end to make the only date

    you can with the combination you have to work with.

    The numbers at each end did not occur by chance, they would just be looking like a date by chance, when in fact, God

    would have a different reason for their location,.....but im sure he see's what im seeing!

    The date completes its first occurrence at digit # 7 2 9 0

    I couldn't shake the feeling that God may be telling me, that it is a date, and that it has "some sort of meaning", so i did this,

    8 6 completes its first occurrence at digit # 7 5


    3 .(1 4 . . . 7 5 . . . 8 6)( . . . . . 7 5 x 7 5 + 1 5 9 0 . . . . . 2 2 0 2 0 2 0){ 7 2 9 0 digits)

    The first occurrence of 2 0 2 0 completes at digit # 7 2 8 8

    I took the gematria of todays date, 2 9 2 2, from 7 2 8 8, and, 6 6 6 + 6 6 6 + 6 6 6 + 2 3 6 8 was left,
    so of course, i broke down the sum of the date,

    February Twentieth Two Thousand Twenty = 6 6 6 + 1 5 9 0 + 6 6 6
    Last edited by Scott; 02-20-2020 at 02:11 PM.

  4. #114
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    This string of digits, 7 5 1 5 9 0 6) , my name, 1 5 9 0, tucked inside of 7 5 6,

    that i've explained in several posts, finishes its first occurrence at digit # 4 8 7 0.

    My birth date, "January First Nineteen Sixty Three" = 2 4 0 6 .

    I'm 5 7 years old, i'm in my 5 8 th year, and about to turn 5 8 years from conception.


    3 . 1 4 . . . . . . . . . . 1 9 6 3( . . . . . 5 7 . . . . . )1 5 9 0



    2 4 0 6 + 2 4 0 6 + 5 8 = 4 8 7 0



    2 digits, which are 7 and 4, occur before what appears to resemble yesterdays

    date with 2 0 2 0's first occurrence, and the 7 and 4 have this number preceding them,

    1 5 5 9 0|7 4|2 2 0 2 0 2 0

    This number 1 5 5 9 0, is i'm sure...for one reason at least,

    there to make me think of my name! Quite the thing to appear and complete 2 digits before

    what i thought just in time, looked like a date!

    It begins its first occurrence right after the first 7 2 7 6 digits,



    2 4 0 6 + 2 4 0 6 + 2 4 0 6 + 5 8 = 7 2 7 6



    These 2 digits, 5 8, occur right before 1 5 5 9 0,

    5 8 1 5 5 9 0

    The 5 8 digits closing the gap to reach the 1 5 5 9 0,

    end with a 5 and 8


    4 8 7 0 + 2 4 0 6 = 7 2 7 6 digits|1 5 5 9 0 begins at digit # 7 2 7 7



    3 . 1 4 . . . . . 7 5(1 5 9 0 6 . . . . 1 5 6 + 1 5 9 0 + 6 6 6 . . . . 1)5 5 9 0 7 4 2 2 0 2 0 2 0

    "You have counted the number correctly" = 2 4 2 4

    3 . 1 4 . . . . . 6 6 6( . . . . 2 4 2 4 . . . 1)(5 9 0 6 . . . . 2 4 2 4 . . . . . . . . . . 2 2 0 2 0 2 0)



    The name God chose for himself in the O.T. is "ELOHIM" = 8 6{in Hebrew
    The name God chose for his Son is "JESUS CHRIST" = 2 3 6 8{in Greek
    The only number God gives instructions to count, is 6 6 6

    3 . 1 4 . . . . . . . . . (8 6 . . . . . . . 2 3 6 8 . . . . . 6 6)6

    That's the first occurrence of 8 6 and 6 6 6,

    so, if The Bible is a made up story by human authors, and the digits of Pi are all happening

    by chance, then how did that happen?

    The first 6 6 6 completes at digit # 2 4 4 2.

    In 1 9 4 9, the first 2 0 3 7 digits of Pi were revealed,...this was the record at the time.

    I wouldn't have been doing then, what i'm doing now had i lived at that time!

    "The Pi-Search Page"

    ==================================================

    6 6 6 digits starting with the first digit of the first occurrence

    of my name 1 5 9 0, splits at 4 5 0 and 2 1 6,

    right at the 8 of the first occurrence of this number,

    1 3 1 8{ Rev. 1 3:1 8


    1 2 3 + 6 6 6 = 7 8 9

    6 x 6 x 6 = 2 1 6

    6 6 6 - 2 1 6 = 4 5 0, The length in feet of Noah's Ark,

    which is LIFT UP above the earth after the first 1 7 6 verses.

    Instructions are given to count the number 6 6 6 at the start of the last 1 7 6 verses
    Last edited by Scott; 02-22-2020 at 12:05 PM.

  5. #115
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    3 . 1 4 . . . . . . . . . . . . . . 6 6(6 . . . . . . . . . 1 0 5 9 0 . . . . . . . . 2 4 7 2)

    First occurrence of 6 6 6 and 2 4 7 2

    1 5 9 0 + 6 6 6 + 2 1 6 = 2 4 7 2

    4 x 2 4 7 2 + 6 6 6 + 2 1 6 = 1 0 5 9 0


    1 7 6 + 3 1 4 + 1 7 6 = 6 6 6

    ==========================================

    There are 6 6 6 + 2 1 6 digits

    separating the first occurrence of 1 9 9 5{post 102,109), and digit # 1 5 9 0


    3 . 1 4 . . . . . . . . . . . . . 1 9 9 5( . . . . . . . . 6 6 6 + 2 1 6 . . . . . . . )digit # 1 5 9 0



    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0

    The first book of the N.T. has 1 0 7 1 verses.

    The last book has 4 0 4,

    4 0 4< 6 6 6 >1 0 7 1



    Count the number of the beast = 1 6 8 0 (+ 6 6 6 = 2 3 4 6

    From the completion of the first occurrence of 2 3 4 6

    to digit # [ 1 5 9 0 + 6 6 6 ] {2 2 5 6

    is 1 9 9 5 digits,


    3 . 1 4 . . . . . . . . . . . . . . 2 3 4 6( . . . . . . . 1 9 9 5 . . . . . . .}digit # 2 2 5 6
    Last edited by Scott; 02-23-2020 at 07:51 AM.

  6. #116
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    Count the number of the beast = 1 6 8 0

    The first 6 6 6 is completed at digit # 2 4 4 2

    From the start of 6 6 6 to the start of 1 6 8 0 is,

    1 6 8 0 + 6 6 6 + 6 6 6 6 + 1 6 8 0 + 6 6 6 digits,

    or,

    4 x 2 4 4 2 + 1 5 9 0 digits,

    3 . 1 4 . . . . . . . . (6 6 6 . . . . . . 2 4 4 2 + 2 4 4 2 + 2 4 4 2 + 2 4 4 2 + 1 5 9 0 . . . . . )1 6 8 0


    3 . 1 4 . . . . . . . . . 6 6 6( . . . . . . 2 4 4 2 + 2 4 4 2 + 2 4 4 2 + 2 4 4 2 + 1 5 9 0 . . . . . 1 6 8)0


    6 6 6 6 + 1 5 9 0 = 8 2 5 6

    Ivan Panin's N.T.,

    "Here is the wisdom. who hath understanding, let him count
    the number of the beast, for it is the number of a man,
    and his number is Six hundred sixty six"

    = 8 6 5 8

    Now here's the same translation with old English removed,

    "Here is the wisdom, who has understanding, let him count
    the number of the beast, it is the number of a man, his number
    is { = 6 6 0 6 ] Six hundred sixty six"

    = 8 2 5 6

    8 2 5 6 minus 6 6 6 and the gematria of the date i

    think it leads to 2 7 2 4 = 4 8 6 6, and digit 4 8 6 6 is

    where my name 1 5 9 0 begins its first occurrence.

    8 2 5 6 - [ 1 6 8 0 + 6 6 6 + 2 1 6 ]

    = [ my name, 1 5 9 0 + my son's name, 1 3 8 0 + 2 7 2 4 ]


    ==================================================


    My first, middle, and last name, consist of 7 , 5, and 6 letters. (post #'s 69, 76)

    When my name 1 5 9 0 occurs in Pi, this is what you see,

    7 5 1 5 9 0 6

    My birth date, "January First Nineteen Sixty Three" = 2 4 0 6

    Here's the measurement in digits from the start of the first occurrence of 7 5 6,

    to the completion of the first occurrence of 7 5 1 5 9 0 6,

    3 . 1 4 . . . . . . . . . . (7 5 6 . . . . . . . . 2 4 0 6 + 1 5 9 0 + 6 6 6 . . . . . . . . 7 5 1 5 9 0 6)

    3 . 1 4 . . . . . . . . . . (7 5 6 . . . . . . . . 1 9 6 3 + 1 5 9 0 + 1 1 0 4 . . . . . . . 7 5)1 5 9 0 6

    "Number 6 6 6" = 1 1 0 4

    "Count 6 6 6" = 1 1 0 4


    ===============================================

    The first occurrence's of 9 1 1 and 6 6 6,

    3 . 1 4 . . . . . . . . (9 1 1 . . . . . . . 9 1 1 . . . . . . . . 6 6 6 7)

    3 . 1 4 . . . . . . .(9 9 1 1 . . . . . . . 9 1 1 . . . . . . . . 6 6 6)

    Immediately after showing me that, HE shows me this,

    3 .(1 4 . . . . . . . . . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . . . . . . . . . . . . . . 1 5 9 0)


    6 6 6 6 + 1 5 9 0 = 8 2 5 6

    6 6 6 7 would be number 1 of 1 5 9 0

    ===========================================

    ELOHIM = 8 6{Hebrew sum

    When my wife's maiden name 9 1 8 first occurs,

    3 . 1 4 . . . . . . 8 6( . . . . 1 5 9 0 + 5 5 9 . . . . . . . . . 5 5 9 9 1 8 5 5 9)

    3 . 1 4 . . . . . . . . . . . . . 9(1 8 . . . . . . . . . . 6 6 6 + 1 3 1 8 + 6 6 6 . . . . . . . . . 1 5 9 0)

    3 . 1 4 . . . . . . . . . . . . .(9 1 8 . . . . . . . . . . 1 5 6 + 9 0 6 + 1 5 9 0 . . . . . . . . . . 1 5 9 0)

    GOD = 1 5 6
    JESUS CHRIST = 9 0 6
    Last edited by Scott; 02-24-2020 at 12:29 PM.

  7. #117
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    My name is 1 5 9 0, i was 1 0 3 1 2 days old when this experience began.

    My Son's name is 1 3 8 0,

    3 . 1 4 . . . . . . . . . . . . 8 6( . . . . . . . . . 1 5 9 0 + 1 0 3 1 2 . . . . . . . . 1)3 8 0

    When my name followed by my Wife's occur for the first time, this is what you see,

    3 . 1 4 . . . . . . . . . . . . . . . . . . 1 5 9 0 9 1 8 3 0 8 0

    I see numbers in place to make me think of 1 3 8 0,....stemming from inside my Wife's name!

    That's the closest it gets to this, 1 5 9 0 9 1 8 1 3 8 0, in the first 200 million digits, thats as high as the Pi Seacher i use counts, but

    i was just looking for my name and my wifes , and a strong hint of his name showed up with ours.



    Correction in the 3rd set of measurements in Pi, in the previous post, bottom segment, it should have looked like this,

    3 . 1 4 . . . . . . . . . . . . . . . (9 1 8 . . . . . . . . 1 5 6 + 9 0 6 + 1 5 9 0 . . . . . . . . 7 5 1 5 9 0 6)

    =============================================

    "January First, One Thousand Nine Hundred Sixty Three,...1 5 9 0"

    = 4 9 9 2

    4 9 9 2 begins its first occurrence at digit # 8 7 4 4

    with X O {kiss and a hug i like to think) appearing beneath in the text version corresponding with the digits of Pi

    8 6 + 8 6 5 8 = 8 7 4 4

    ELOHIM = 8 6, and 8 6 5 8 is the

    sum of the word's in Ivan Panin's translation of Rev. 1 3:1 8
    Last edited by Scott; 02-25-2020 at 11:02 AM.

  8. #118
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    "January First Nineteen Sixty Three,...1 5 9 0"

    = 3 9 9 6


    3 .(1 4 . . . . . 8 6 9 digits . . . . . 8)(6 5 8 . . . . . . . . . 3 9 9 6 digits . . . . . . )1 5 9 0


    First occurrence of 8 6 5 8 and 1 5 9 0


    <><><><><><><><><><><><><><><><><><><><><>


    "January First One Thousand Nine Hundred Sixty Three,...1 5 9 0"

    = 4 9 9 2



    3 .(1 4 . . . . . . . 8 6 digits . . . . . )( . . . . . . . . . . 8 6 5 8 digits. . . . . . . 4)9 9 2


    That was the first occurrence of 4 9 9 2


    If God said this out loud to me, we would both know it to be true,

    "You were, "THE" North Dade County New Year's baby, for the year Nineteen Sixty Three"

    = 4 9 9 2


    <><><><><><><><><><><><><><><><><><><><><>



    January First = 9 7 2

    I found the following string of digits first occurring starting at 1 5 9 0 + 9 7 2 digits,

    0 1 0 1


    3 . 1 4 . . . . . (0 1 0 1 . . . . . 1 5 9 0 + 7 1 7 digits . . . . 7 1 1 9 6 3 7 7 . . . . . . 1 5 9 0)

    Genesis 7 : 1 7 is verse 1 7 7, The 4 5 0 ft long Ark is LIFT UP

    The first occurrence of 1 9 6 3 is inside a 7 1 7 and a 1 7 7

    The first occurrence of 1 9 6 3 and 1 5 9 0

    are separated by 5 7{my present age) digits.

    7 1 7 + 1 5 6 + 7 1 7 = 1 5 9 0

    Nineteen Sixty Three{=1434) + 1 5 6 = 1 5 9 0

    7 1 7 7 begins to appear first at digit # 8 8 8{ 186 + 36 + 666 = 888 + 36 + 666 = 1 5 9 0

    1 8 6 + One Hundred Eighty Six = 1 5 9 0


    The factors of 1 5 9 0 are 2 x 3 x 5 x 5 3{post 71)

    2 3 5 5 3 - 1 1 5 9 0 = 1 1 9 6 3

    and thats exactly what you see at the first occurrence of 1 9 6 3,...and its all inside of 7 7 7


    <><><><><><><><><><><><><><><><><><><><><>


    3 .(1 4 . . . . . . 8 6 digits . . . . . )( . . . . . 1 1 0 7 + 2 0 2 0 digits . . . . .}. digit 3 2 1 3


    3 123 2 45 1 6 3 789
    Last edited by Scott; 02-26-2020 at 01:19 PM.

  9. #119
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    7 0 years a nation and generation completed on,

    May Fourteenth Two Thousand Eighteen = 2 4 2 4

    "ISRAEL" = 5 4 1 in Hebrew.

    God brought that to my attention 5 4 1 days after The Rev. 1 2 Sign

    that took place on Sept. 23rd 2 0 1 7, that John wrote about in the 1 1 7 9 th

    chapter of the Bible,

    9 / 2 3 / 2 0 1 7

    September Twenty Third Two Thousand Seventeen

    = [ 9 + 2 3 + 2 0 1 7 + 1 1 7 9 ]
    ,

    and also brought this to my attention the same day,

    May 14th 2 0 1 8 + 5 4 1 days, is Nov.7th 2 0 1 9

    The first occurrence of 2 4 2 4{after the first 1 1 0 7 digits of Pi), is followed by

    the first occurrence of 5 4 1,

    2 4 2 4 5 4 1

    This Nov.7th 2 0 2 0, will be 9 0 7 days after 2 4 2 4,

    9 0 6 days if it wasn't a leap year.

    JESUS CHRIST = 9 0 6 { A=6, B=12, C=18, D=24........Z=1 5 6/ GOD = 1 5 6

    The number 9 0 7 begins its first occurrence right after the first 5 4 1 digits of Pi.

    By placing it in that location, God is showing clearly, the connection with the 5 4 1

    days following the 2 4 2 4 date, and, the first occurrence of 2 4 2 4 5 4 1 in the digits of Pi.

    The first occurrence of 2 4 2 4 9 0 6 looks like this, 2 4 2 4 9 0 6 6 6

    The 9 0 6 days that the 5 4 1 should have become by the start of Nov.7th 2 0 2 0,

    is 9 0 7 instead because of 2 0 2 0 being a leap year.

    This is why God placed the first 9 0 7 immediately after the first 5 4 1 digits of Pi !

    8 6 + 2 3 6 8 = 2 4 5 4, and this is where 2 4 5 4 first occurs,

    2 4 2 4 5 4 1


    < . >< . >< . ><><><><><><.><.><><><><><>< . >< . ><. >


    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0

    I'm 5 7 now,

    3 .(1 4 . . . . . . 4 0 5 . . . . . . 5 7) . . . . . . . . . 1 9 6 3( . . . . . . 5 7 . . . . . )1 5 9 0

    3 .(1 4 . . . . . . . 8 6 + 1 9 9 5 + 2 7 2 4 . . . . . . . 1)9 6 3

    1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8

    My Son' name, 1 3 8 0,

    3 . 1 4 . . . . 1(9 9 5 . . . . 1 3 8 0 + 2 7 2 4 . . . . 1 9 6 3)

    Post # 102 ^
    Last edited by Scott; 02-27-2020 at 08:56 PM.

  10. #120
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    January First Nineteen Sixty Three= 2 4 0 6


    3 .(1 4 . . . . . . 2 4 0 6 + 2 4 0 6 + 5 7 . . . . . . . . . . . . 1 5 9 0)

    3 . 1 4 . . . . . . . . . . . . . . 1 9 6 3( . . . . . . 5 7 . . . . .)1 5 9 0



    The factors of 1 5 9 0{post # 71),

    2 x 3 x 5 x 5 3 = 1 5 9 0


    2 3 5 5 3 - 1 1 9 6 3 {which is what you see at the 1st occurrence of 1963) = 1 1 5 9 0


    Right after the first 2 3 5 5 3 digits of Pi, the number 8 8 2 which

    is 6 6 6 + 2 1 6 appears next.


    The number 1 1 9 6 3 completes its first occurrence at digit # 4 8 0 8
    The number 1 1 5 9 0 completes its first occurrence at digit # 5 1 6 4 8, and the next digit is a 3,

    Counting backwards from this 3,

    2 x 2 3 5 5 3 digits, brings us back to digit # 4 5 4 3



    3 .(1 4 . . . . . . . 9 9 0 + . . . . . . )(2 1 6 . . . . . . 1 9 6 3 + 1 5 9 0 = . . . . . . . }digit # 4 5 4 3

    3 . 1 4 . . . . . . . . . digit # 4 5 4 3( . . . + . . . 1 1 9 6 3 + 1 1 5 9 0 = . . . . . . . .}digit # 5 1 6 4 8



    9 9 0 + 1 1 9 6 3 + 1 9 6 3 + 1 5 9 0 + 1 1 5 9 0 = 5 1 6 4 9



    Here's the first occurrence of, my name 1 5 9 0 followed by 2 0 2 0 9 1 1

    3 .(1 4 . . . . . . 9 7,6 8 2,1 8 7 digits . . . . . . . . . 1 5 9 0 2 0 2 0 9 1 1)

    I was looking for 1 5 9 0 2 0 2 0 and the 9 1 1 came with it...

    Including THE 9 1 1 and the 9 1 1 of 2 0 2 0,

    thats 9 + 1 1,...9 1 1's


    3 . 1 4 . . . . . . . . . (9 9 1 1 . . . . . . . . 9 1 1 . . . . . 6 6 6)


    Here's the first occurrence of my name completing at digit # 4 8 6 9

    3 .(1 4 . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . 1 5 9 0)
    Post # 1 1 0 ^



    Here are the 2 0 digits leading up to the first occurrence of 2 0 2 0 1 5 9 0 at digit # 3 2, 2 1 2, 3 5 7 ,

    2 0 2 0 7 2 1 2 1 1 2 0 1 9 0 8 7 6 1 1 2 0 2 0 1 5 9 0

    I just added todays date, after finding this in Pi, 2 0 2 0 1 5 9 0 9 1 1

    February Twenty Nineth Two Thousand Twenty = Six Hundred Sixty Six + 1 5 9 0

    or, 2 3 2 9 + 9 1 1

    Digit # 2 3 2 9 is where the first occurrence of 1 5 6 is completed.

    February Twenty Nineth Twenty Twenty = 6 6 6 + 1 5 9 0 + 6 6 6
    Last edited by Scott; 02-29-2020 at 01:57 AM.

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