9 1 1

[Scott]

7 7 7 + 3 6 + 7 7 7 = 1 5 9 0

7 + 7 + 7 x 3 6 + 7 + 7 + 7 = 7 7 7

==========================

At digit # 3 6 + 6 6 6{702) the number

2 0 1 9 begins its 2nd occurrence.

3 6 + 6 6 5 + 1 3 1 8 digits puts us at digit # 2 0 1 9

3 6 + 6 6 6 + 1 3 1 8 digits = digit # 2 0 2 0


The first occurrence of 2 0 2 1,

2 0 2(1 . . . . . .1107 + 2021. . . . .{digit # 2 3 6 8

November Seventh Two Thousand Twenty One = 2 9 2 8,

so i counted 2 9 2 8 digits using the 1 in 2 0 2 1's first occurrence

as digit #1 of the 2 9 2 8 digits, and it brought me to the

last digit of the first occurrence of 1 5 5 9 0,

which is closely followed by the first and second occurrence

of 2 0 2 0,

2 0 2(1 . . . . . . 2928. . . . . . 1 5 5 9 0)7 4 2 2 0 2 0 2 0

1 5 5 9 0 occurs first starting at digit # 7 2 7 7

[Scott]

I looked for my birth date thats coming up, 0 1/0 1/2 0 2 1, and it

doesn't make its first occurrence until well over 141 million digits, but

sure enough the number 6 6 6 makes an occurrence

almost immediately after,

3 .(1 4 1 5 9 . . . . . . .141,346,377 . . . . . . . .)0 1 0 1 2 0 2 1 4 6 6 6

4 0 0 0 + 6 6 6 = 4 6 6 6

The 3rd occurrence of 6 6 6 starts at digit # 4 0 0 0

The first Advent was in year 3 9 9 9.

4 6 6 6 is what you see at the first occurrence

of 6 6 6 which completes at digit # 2 4 4 2



January First = 9 7 2

1 5 9 0 + 9 7 2 = 2 5 6 2

0 1 0 1 begins its first occurrence after the decimal point

at digit # 2 5 6 2.

I was born Jan. 1 / 1 9 6 3, right after the completion of the year 1 9 6 2.

1 9 6 2 completes its first occurrence at digit # 9 0 8 0

2 5 6 1 + 1 5 9 0 + 2 3 6 8 + 2 5 6 1 = 9 0 8 0


3 .(1 4 1 5 9 . . . .2561 + 1590 + 2368 + 2561. . . . 1 9 6 2)


1 9 6 3 + 1 9 9 5 = [1 5 9 0 + 2 3 6 8]

[Scott]

The night i first read what Panin claimed about numerics

declaring not only the year, but even the blessed day and hour,

and felt it had something to do with the number 6 6 6 being intelligently

structured into the core of the number set so to speak, and believed

that Jesus Christ(2 3 6 8) was preparing to show me something,

communicating with me in fact, i was 1 0 3 1 0 days old.

1 5 9 0 makes its first occurrence right after

.digit # 4 8 6 5


===============================
If i add the segments of what has been my family phone number for just

over 50 yrs, the sum is 3 7 2 7

3 7 2 7 + 1 5 9 0 + 6 6 6 + 2 1 6 digits = digit # 6 1 9 9

The 4 digit # that occurs for the first time starting digit # 6 1 9 9,

is 3 7 2 7

Count the number of the beast (= 1 6 8 0 ) + 6 6 6 = 2 3 4 6

2 3 4 6 begins first at digit # 2 6 0

2 6 0 + 6 6 6 + 2 1 6 + 3 7 2 7 digits = digit # 4 8 6 9,

Digit # 4 8 6 9 is the completion of number 1 5 9 0.

As ive shown many times now, my name 1 5 9 0 which

consists of 7 , 5 , and 6 letters, is tucked inside 7 5 6

when it first occurs,

7 5 1 5 9 0 6

7 5 6 + 1 5 9 0 = 2 3 4 6

Digit # 4 8 7 0 + 6 6 6 + 6 6 6 digits = digit # 6 2 0 2

Digit # 6 2 0 2 is the last digit of the first occurrence of number 3 7 2 7
================================


.Digit # 4 8 6 5 + 2 3 6 8 + 4 8 6 5 digits = digit # 1 2 0 9 8

the number 1 0 3 1 0 makes its first occurrence right after digit # 1 2 0 9 8

2 nights later he showed me that only 1 number larger than 9 8 7{Enoch)

had the same features as 9 8 7,

1 9 9 5

1 x 9 x 9 x 5 = 4 0 5

5 7 makes its first occurrence at digit #'s 4 0 4 and 4 0 5

The number 1 9 6 3 has 5 7 digits standing between it and

the number 1 5 9 0's first occurrence's.

1 9 9 5 - 4 0 5 = 1 5 9 0

First that same night, he showed me this,

6 x 6 x 6 = 2 1 6

6 6 6 - 2 1 6 = 4 5 0

[Scott]

First occurrence of 1 3 1 8,

(3 . 1 4 . . . . . .3 7 2 7 + 1 5 9 0 positions. . . . . . . 1 3 1 8)


Counting 6 6 6 digits and using the first occurrence

of my name as the first 4, the 6 6 6 digits will

divide into 4 5 0 and 2 1 6 right at

the 8 in the first occurrence of the number 1 3 1 8

3 . 1 4 . . . . . . . . (1 5 9 0 . . . . .4 5 0. . . . . 1 3 1 8)
==================================

3 .(1 4 . . . . .4869. . . .1 5 9 0)(. . . .1590 + 1 3 1 8. . . ..{digit # 7 7 7 7
post #'s 218,219,220


4 8 3 {6 9 x 7)

First occurrence of 1 5 9 0 and 4 8 3,

1 5 9 0(. . . . .1318 + 2368. . . . . 4 8 3)

4 9 0 occurs first right after digit # 9 0 6

4(9 0 . . . . .2368 + 1590. . . . .)1 5 9 0

8 8 8 - 4 8 3 = 4 0 5

[Scott]

First occurrence of 1947 and 2018,

(1 9 4 7 . . . . . . .2018. . . . . . . 2 0 1 8)


Using English gematria,

May Fourteenth Two thousand Eighteen = 2 4 2 4{70th anniversary of Israel)

Israel = 5 4 1 in Hebrew


When we look for the first occurrence of either 2 4 2 4 or 5 4 1, we see this,

2 4 2 4 5 4 1

==============================

Count the number of the beast = 1 6 8 0

1 6 8 0 + 6 6 6 = 2 3 4 6

1 5 9 0 + 7 5 6 = 2 3 4 6


3 . 1 4 . . . . . . . 2 3 4 6(. . . . .2346 + 1590 + 666. . . . . .)1 5 9 0

3 . 1 4 . . . . . . . 2 3 4 6(. . .666 + 1590 + 1680 + 666. . . .)1 5 9 0

[Scott]

First occurrence of 8 6 and 1 5 6,

3 . 1 4 . . . . .(8 6 . . . .1590 + 6 6 6. . . . . 1 5 6)

First occurrence of 1 5 6 and 2 0 2 1

3 . 1 4 . . . . . . . . . . 1 5 6(. . . .2021. . . . .)2 0 2 1

[Scott]

5 4 1 days after The Revelation 12 Sign, God showed me

that "ISRAEL" = 5 4 1 in Hebrew, and that The 70th

anniversary date for Israel adds to 2 4 2 4 using English Gematria,

and that its first occurrence in Pi is immediately followed by the first

occurrence of 5 4 1, and, that 5 4 1 days after 2 4 2 4 was Nov.7th 2019.

Page 17 post # 164
Page 21 post # 202



Nov.7th 2020 was 9 0 7 days after 2 4 2 4.

There is no 2 4 2 4 9 0 7 in the first 200 million digits of Pi,

but, the number 9 0 7 occurs first right after the first

5 4 1 digits of Pi.

1 5 0 6 days after The Revelation 12 Sign{Sept.23rd 2017)

is Nov.7th 2021, and 1 5 0 6 occurs first with the first

occurrence's of 2 4 2 4 and 5 4 1, and is connected to 5 4 1,

2 4 2 4 5 4 1 5 0 6

"The Body of Jesus Christ" = 1 5 0 6

This string, 2 4 2 4 9 0 6 does occur in the first 200 million digits of Pi,

2 4 2 4 9 0 6 6 6


7 7 7 + 5 4 1 = 1 3 1 8

[Scott]

If we look for the First occurrence of 2 3 6 8 {Jesus Christ/Greek)

followed by 1 1 1 0 {Donald John Trump/English), we see thats its followed by,

whether we like it or not,...an occurrence of 2 0 1 7, his year of Inauguration!

What could this mean if it's not happening by chance?

I have a feeling we're about to find out!


3 .(1 4 . . . . . .7 5,8 6 6,0 7 7. . . . . .)2 3 6 8 1 1 1 0 2 0 1 7

[Scott]

3 . 1 4 . . . . .8 6(. . .666 + 450 + 3675 digits. . . . . 3 6 7 5 1)5 9 0 6

3 . 1 4 . . . . .8(6 . . .666 + 450 + 3675 digits. . . . . 3 6 7 5)1 5 9 0
6


The number 1 9 9 4 completes its first occurrence at digit # 3 6 7 5


My name 1 5 9 0 completes its first occurrence at digit # 4 8 6 9

4 8 6 9 + 5 4 1 = 5 4 1 0

123 + 666 = 789
6 x 6 x 6 = 216
666 - 216 = 450

123 - 45 - 6 - 789 { 3 2 1 3 )

5 4 1 + [5 4 1 + 1 5 9 0] + 5 4 1 = 3 2 1 3

[Scott]

"Count the number of the beast"{= 1 6 8 0/English)
+
1 9 9 5

= 3 6 7 5