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  1. #261
    Join Date
    Aug 2013
    Posts
    446
    The sum of my name 1 5 9 0 completes its first

    occurrence at digit # 4 8 6 9

    The first 1 5 1 2 digits end with Enoch's Rapture year,

    9 8 7{p.11,post # 102)

    The last 1 5 1 2 digits begin with 1 9 8 4,

    or, 1 3 1 8 + 6 6 6


    The number of digits between those 2 groups of 1 5 1 2, are,

    6 6 6 + 1 1 7 9


    1 1 7 9 + 6 6 6 + 1 1 7 9 + 6 6 6 + 1 1 7 9 = 4 8 6 9

    1179, p.21, bottom of post # 202

    The number 1 5 1 2 completes its first occurrence at digit # 5 2 2 3

    9 + 2 3 + 2 0 1 7 + 1 1 7 9 + 1 9 9 5 = 5 2 2 3
    Last edited by Scott; 10-19-2020 at 04:16 PM.

  2. #262
    Join Date
    Aug 2013
    Posts
    446
    First occurrence's of 1 4 8 0, 1 9 4 7, and 8 8 8,

    3 . 1 4 . . . 1 4 8 0(. . .1947. . .)(1 9 4 7 . . .86 + 666 + 1948. . . 8 8 8)

    1 9 4 7 + 8 6 + 6 6 6 + 1 9 4 8 digits

    from completion of Christ to completion of Jesus,

    with the first occurrence of 1 9 4 7 starting 1 9 4 7 digits

    after the first occurrence of Christ.

    In Greek,

    Jesus = 8 8 8{Amos 9:15 is the last verse of Bible chapter 8 8 8)
    +
    Christ = 1 4 8 0

    = 2 3 6 8


    3 . 1 4 . . . . 8(6 . . . .2 3 6 8. . . . . 6 6 6)
    Last edited by Scott; Yesterday at 01:19 PM.

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