9 1 1

[Scott]

3 . 1 4 . . .(1 5 9 0 . . .{4 5 0 digits} . . .1 3 1 8)(. . .{2 1 6 + 2 7 2 4 digits}. . )digit 8 2 5 6

Rev. 1 3 : 1 8,
Here is the wisdom,who has understanding,let him count the number of the beast,
it is the number of a man,his number is Six Hundred Sixty Six
__________________________________________________ ________________= 8 2 5 6

6 x 6 x 6 = 2 1 6

6 6 6 - 2 1 6 = 4 5 0
__________________________________________________ ________________

123 {3
45{2
6 . .{1
789{3
0

3 . 1 4 . . 8 6( . . {6 6 6 + 2 1 6 digits} . . )( . . . {1 5 9 0 + 6 6 6 digits} . . . . . [digit 3 2 1 3]

(3 . 1 4 . . {7 7 7 + 7 7 7 + 7 7 7 positions} . 1 5 6)( . {6 6 6 + 2 1 6 positions} . [P. 3 2 1 3]

3 . 1 4 . . (8 6 . . { 1 5 9 0 + 6 6 6 digits } . . 1 5 6)


3 . 1 4 . . 8(6 . . . . . . . {2 3 6 8} . . . . . . . . . . . .6 6 6)


1 5 9 0 + 1 2 3 + 4 5 + 6 6 6 + 7 8 9 = 3 2 1 3

123 456 789 0

" 1 5 9 0 know's the date of The Rapture " = 3 3 7 8 ?



The factor's of the number 1 5 9 0 are, 2 x 3 x 5 x 5 3
2 3 5 5 3 - 1 5 9 0 = 2 1 9 6 3 { d.o.b Jan.1st 1 9 6 3
These are the years of age that divide evenly into the sum of my full name,

7 9 5 x 2 yrs of age
5 3 0 x 3
3 1 8 x 5
2 6 5 x 6
1 5 9 x 1 0
1 0 6 x 1 5
5 3 x 30
3 0 x 5 3
+____________
6 6 6 + 1 5 9 0 is the sum
of the numbers in the left column,
1 5 9 0 + 6 6 6 + 1 5 9 0
if i had included 1 yr of age, but thats a given for any number.
1 0 6 would have been the next year of age that divides
evenly into 1 5 9 0,
then, 1 5 9, 2 6 5, 3 1 8, 5 3 0, and 7 9 5

As you can see, the 6 6 6 digits starting with the first
digit of my name(top of the page) hinges at 4 5 0 and 2 1 6
right at the completion of the 1st occurrence of 1 3 1 8 which
leaves a number of digits that match Nov.7th 2020's gematria sum, to reach digit 8 2 5 6
which is the sum of the words in Rev. 1 3:1 8

[Scott]

3 .(1 4 . . . . . {4 8 6 5} . . . . . )(1 5 9 0 . . . {4 5 0} . . . 1 3 1 8)( . . . . {2 1 6 + 2 7 2 4} . . . . )|digit 8 2 5 6


That's the 1st occurrence of, 1 5 9 0^ and 1 3 1 8^

6 6 6 digits starting from the first digit of my names 1st occurrence,
divided at 4 5 0/2 1 6 at the End of 1 3 1 8's 1st occurrence
is not a coincidence, and i don't believe the 2 7 2 4 digits that close
the gap to reach digit 8 2 5 6 is either!


A person might say these numbers this way, as a faster way to say them,

"One Thousand Five Ninety" = 1 5 9 0
or,
"One Thousand Three Eighteen" = 1 5 9 0


Six times Six times Six equals Two Hundred Sixteen

= [ G O D + 6 6 6 + 2 7 2 4 ]

G O D + [ 1 5 9 0 + G O D + 6 6 6 ] + G O D = 2 7 2 4

[Scott]

When 2 0 2 0 1st occurs, it is meshed with its 2nd occurrence, and the two of them are completed
at digit 7 2 9 0,

3 . 1 4 . . . . .(8(6 . . . . . . { 2 0 1 9/2 0 + 1 5 9 0 + 6 6 6 + 2 1 6 + 2 7 2 4 } . . . . . . . . . . . . . 2 0 2 0 2 0)

or,

(8 6 . . .{ 1 5 9 0 + 6 6 6 + 2 1 6 + 2 7 2 4 + 2 0 2 0 digits to cap off the completion of 2 0 2 0 2 0's 1st occurrence)



3 . (1 4 . . . {2 4 4 2} . . . . 6 6 6)( . . . . {2 4 2 4} . . . .1)(5 9 0 . . . {2 4 2 4} . . . . . . . . . . . . 2 0 2 0 2 0)


Position's,
(3 . 1 4 . . . {2 4 4 2} . . . . 6)(6 6. . . {2 4 2 4} . . . 7)(5 1 5 9 0 6 . . . {2 4 2 4} . . . . . . . .2 0 2 0)2 0

More about 7 5 6 in Post #69

More about 2 4 2 4 in Post #70

3 . 1 4 . . . . . . . 7 5 1 5 9 0(6 . . . . . . { G O D + 1 5 9 0 + 6 6 6 } . . . . . . . .1 5 5 9 0)7 4 2 2 0 2 0 2 0


3 . 1 4 . . . . . . 2(7 2 4 . . . . . { 2 3 6 8 + 2 0 2 0 }. . . . . )1 5 9 0

3 . 1 4 . . . . . . 2 7 2 4( . . . . .{ 2 3 6 8 + 2 0 1 7 } . . . . .)1 5 9 0

2 0 1 7 was the year of the Revelation 12 Sign in Bible Chapter 1 1 7 9, and i discovered this...and knew,

September Twenty Third Two Thousand Seventeen = [ 9 + 2 3 + 2 0 1 7 + 1 1 7 9 ]


A=6, B=12, C=18, D=24,.......... Z= 1 5 6

[Scott]

On the date that the instructions of Rev. 1 3 : 1 8 have now led me to,
The 2 6th Nov.7th starting with 1 9 9 5's
i will be 2 1 1 3 0 days old.

1 9 6 3 + 1 9 9 5 = 2 3 6 8 + 1 5 9 0
2 3 x 6 8 + 2 6 = 1 5 9 0


This is what happens at the 5th and 6th group of days i lived that match the sum of my name, 1 5 9 0.
but only with Nov.7th 2020 as the cut off date to count to!

I'm 5 6 years, 3 5 3 days old today, and any connection with 5 6 ends for me Jan.1st 2 0 2 0, and Nov.7th
is 3 1 1 days(leap year) after the connection ends, with 5 6 days left till my precise connection with 5 7.


[ 5 x 1 5 9 0 ] + 1 3 1 8 0 = 2 1 1 3 0
[ 6 x 1 5 9 0 ] + 1 1 5 9 0 = 2 1 1 3 0

2 1 1 3 first occurs right after the first 7 5 6 digits of Pi, starting at digit 7 5 7.

Born Jan.1st 1 9 6 3,

3 . 1 4 . . . . . . . 1 9 6 3( . . . . { 5 7 } . . . . 7 5)1 5 9 0 6

I will enter day 2 1 1 3 1, and when i looked for 2 1 1 3 1 in Pi these are the digits preceding it,

8 8 2 3 6 9 8 6|2 1 1 3 1

8 8 2 is 6 6 6 + 2 1 6

2 3 6 9 is neighbor number to 2 3 6 8 {Jesus Christ /Grk.)

9 8 6 is neighbor number to Enoch's Rapture year, 9 8 7

8 6 is the sum of the Hebrew spelling of ELOHIM

__________________________________________________ ______________________________________

3 . (1 4 . . . . { 1 1 0 7 digits } . . . . )(2 4 2 4 5 4 1 . . . . { 1 5 6 + 6 6 6 + 2 1 6 + 2 7 2 4 } . . . . 1 5 9 0)

Ive explained many times now the 2 4 2 4 5 4 1 in Pi,
2 4 2 4 {May 14th 2018) + 5 4 1 days = Nov.7th 2019
this is what you see when you look for the first occurrence
of 2 4 2 4 and 5 4 1,

2 4 2 4 5 4 1

This Nov.7th 2 0 2 0{ = 2 7 2 4) is 9 0 6 days after 2 4 2 4

8 6 + 2 3 6 8 = 2 4 5 4
The 1st occurrence of 2 4 5 4 is meshed with the end of 2 4 2 4's 1st, followed by 1 5 0 6
"The Body of Jesus Christ" = 1 5 0 6

2 4 2 4 5 4 1 5 0 6

[Scott]

3 . 1 4 . . . . . . (8 6 . . . . . . . . . { 2 3 6 8 } . . . . . . . . 6 6)6


3 . 1 4 . . . . . . . . . . . . . . 6 6(6 . . . . . . . { 1 0 5 9 0 } . . . . . . . . . 2 4 7 2){ 1st occurrence)


3 . 1 4 . . . . . . (8 6 . . . . . . { 1 5 9 0 + 6 6 6 } . . . . . . 1 5 6)

1 5 9 0 + 6 6 6 + 2 1 6 = 2 4 7 2

6 6 6 + 2 1 6 = 8 8 2

3 . 1 4 . . . . . . . . . . (8 8 2 . . . . . . .{ 1 5 9 0 + 1 3 1 8 + 1 5 9 0 } . . . . . . 1 5 9 0)

8 8 8 + 1 4 8 0 is 2 3 6 8{Jesus Christ/Grk.),
and if we hinge 8 8 8 and 1 4 8 0 on the first digit of 2 1 6, the first occurrence
of the result of counting 6 6 6, the first 8 8 8 digits begin with the first occurrence of 1 4 8 0, and end at 2)1 6,
which leaves 1 4 8 0 digits to reach digit 2 4 7 2

3 . 1 4 . . . . . . . . . . (1 4 8 0 . . . . . . .8 8 8 . . . . .2)(1 6 . . . . . . 1 4 8 0 . . . . .)[ digit 2 4 7 2 ]


8 6 + 2 3 6 8 + 1 5 9 0 = [ 6 6 6 + 3 3 7 8 { Sat.Nov.7th 2020?) ]

"Count the number of the beast...so you will know the date of The Rapture" = [ 6 6 6 + 2 1 6 + 3 3 7 8 ]

"You counted the number of the beast" = [ 9 9 3 + 1 1 0 7 ]

3 . 1 4 . . . . . { 9 9 3 digits } . . . . 2 1 6)( . . . . . . { 1 1 0 7 digits } . . . . )

__________________________________________________ ________

I did the same with the 3 numbers that are uniquely connected{Enoch,987), as i did with 6 6 6,

7 x 9 x 8 = 5 0 4 / 7 9 8 - 5 0 4 = 2 9 4

9 x 8 x 7 = 5 0 4 / 9 8 7 - 5 0 4 = 4 8 3 {69 wks of yrs { 4 8 3 + 1 1 0 7 = 1 5 9 0

1 x 9 x 9 x 5 = 4 0 5 / 1 9 9 5 - 4 0 5 = 1 5 9 0


2 9 4 + 4 8 3 = 7 7 7 ( + 1 5 9 0 = 2 3 6 7

1 5 9 0 < 7 7 7 > 2 3 6 8

1 5 9 0 - [ 2 9 4 + 4 8 3 ] = 7 7 7 + 3 6

1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8 (- 4 0 5 = 1 9 6 3

7 9 8 + 9 8 7 + 1 9 9 5 = [ 7 1 6 + [ 1 5 6 + 1 5 9 0 ] + 1 3 1 8

1 7 6 verses Forward is Gen. 7:1 6 completed, and 1 7 6 verses Backwards is the start of Rev. 1 3 : 1 8

The 4 5 0 ft. long Ark is "LIFT UP" starting at Gen.7:1 7

1 2 3 - 4 5 - 6 . . - 7 8 9 - 0

__________________________________________________ __________________________________

"Chapter Six Hundred Sixty Seven verse One" = 1 9 9 5 + 7 7 7 { Post #70 )
"Who is as the wise man, and who knoweth the interpretation of a thing" = 2 4 2 4 + 1 5 9 0, or 4 0 1 4,

3 . 1 4 . . . . . . . . . (2 1 6 . . . . . . { 1 5 9 0 + 1 4 3 4 } . . . . . [digit 4 0 1 4])

Nineteen Sixty Three = 1 4 3 4

"1 5 9 0, You have counted the number correctly" = 4 0 1 4

2 3 6 8 + 1 5 9 0 + 5 6 = 4 0 1 4
2 0 1 9 + 1 9 9 5 = 4 0 1 4

"Who is like the wise man, and who knows the interpretation of a thing" = 4 0 3 2, or 1 5 9 0 + 2 4 4 2{ 6 6 6
completes its first occurrence at digit 2 4 4 2

Counting 6 6 6 digits starting with the first digit of my name as digit 1, the 6 6 6 digits at the 4 5 0 mark,
are landing on the 8 of the 1st occurrence of the number 1 3 1 8 that
represents Rev. 1 3 : 1 8,
with 2 1 6 digits left to complete the 6 6 6 digits, which leaves 2 7 2 4 digits
to digit 8 2 5 6{ top of post #71)

The 2 6th letter of the alphabet has 1 5 6 for its sum,...G O D = 1 5 6.

The sum of all the letters = 2 1 0 6
1 5 x 9 0 + 7 5 6 = 2 1 0 6
1 6 x 9 0 + 6 6 6 = 2 1 0 6

[Scott]

The 1st occurrence of 7 5 6 and the 1st occurrence of my name that is tucked into the tail end of a 7 5|6 {post#69),

7 5 1 5 9 0 6, cover a span of this many digits,

3 . 1 4 . . . . . . . (7 5 6 . . . . . . { 2 4 0 6 + 1 5 9 0 + 6 6 6 } . . . . . . 7 5 1 5 9 0 6)

January First Nineteen Sixty Three = 2 4 0 6
November Seventh Twenty Twenty = 2 4 0 6

"Count the number of the beast, 6 6 6" = [ 1 5 9 0 + 7 5 6 ]

The 2 6 letters of the alphabet average a sum of 8 1, and Z has a value of 1 5 6,
1 5 6 - 8 1 = 7 5, and the first occurrence of 8 6{Elohim) ends
at digit 7 5


3 and . is position 1 and 2

8 6 , 2 3 6 8 , and 1 3 1 8 positions
after position 1 brings us to the completion of the 1st occurrence of 2 0 3 8 { 1 1 + 7 + 2 0 2 0 )


3 .(1 4 . . . . 7 5 . . . . 8 6)( . . . . . . . . . 1 1 0 7 + 2 0 2 0 . . . . . . [ digit 3 2 1 3 ] ) { 123 45 6 . . 789 )

8 6 + 2 0 2 0 = 2 1 0 6 { A + B + C . . . + Z = 2 1 0 6 )

[Scott]

Correction, those last measurements in Pi's digits should have looked like this,

3 .(1 4 . . . . . 8 6 . . . . .)( . . . . . 1 1 0 7 + 2 0 2 0 . . . . }[ digit 3 2 1 3 ]

[Scott]

6 6 6 plus the answer it's digits multiply to, 2 1 6 = 8 8 2

8 8 2 completes its 1st occurrence at digit 3 7 4

My name, 1 5 9 0 begins to occur at digit 4 8 6 6, so i checked to see how
many digits there are to reach digit 4 8 6 6 from digit 3 7 4,


3 . 1 4 . . . . . . . . . . 8 8 2( . . . . . . 1 5 9 0 + 6 6 6 + 2 1 6 + 2 0 2 0 . . . . . . 7 5 1)5 9 0 6

I just turned 5 7 at the completion of 2 0 1 9{Jan.1st 2 0 2 0), and this is how
many digits separate 1 9 6 3 from 1 5 9 0, shown to me in the spring of 2 0 1 9, 5 7 yrs after i was conceived,

3 . 1 4 . . . . . . . 1 9 6 3( . . . . . . 5 7 . . . . . . . )1 5 9 0

6 6 6 + 1 5 9 0 + 6 6 6 digits after the decimal point,
brought me to the last digit in this string's 1st occurrence,

1 9 6 6[3]

The only visible sighting of these 3 numbers occurring in the first 200 million digits, 1 5 9 0 6 6 6 2 1 6,
right next to each other, but not necessarily in that order, is this,

1 5 9 0 2 1 6 6 6
and to the left of that 1 5 9 0 is this,
6 6 1 1 7 6 1 5 9 0 2 1 6 6 6

"You counted the number of the beast" = 9 9 3 + 1 1 0 7

3 .(1 4 . . . . . . 9 9 3 . . . . 2 1 6)( . . . . . . . 1 1 0 7 . . . . . )

I believe thats representing the 2 6 th Nov.7th since the 1st one in the year 1 9 9 5

2 3 x 6 8 + 2 6 = 1 5 9 0

2 3 6 8 - [ 6 2 x 2 6 ] = 7 5 6 {post #69)

2 3 6 8 + 1 5 9 0 = [ 6 2 x 2 6 + Count the number of the beast{ 1 6 8 0 ) + 6 6 6 ]

1 6 8 0 + 6 6 6 = [ 1 5 9 0 + 7 5 6 ]


4 1 x 2 6 + 4 1 = 1 1 0 7

6 7 x 2 6 + 6 2 6 = 2 3 6 8

6 7 - 2 6 = 4 1

1 3 1 8 + 6 6 6 + 3 6 = 2 0 2 0

1 3 1 8 + 2 6 + [ 2 6 x 2 6 ] = 2 0 2 0

[Scott]

All of these 2 6 designs coming into light for me,
between 5 7 years from conception, and 5 7 from birth,
and finding just around the 5 7 year mark from conception,
that 5 7 digits are separating the 1st occurrence's of 1 9 6 3, and 1 5 9 0 !!

1 3 + 1 8 + 2 6 = 5 7 yrs. from birth on 01/01/2020

[ 6 x 2 6 ] + [ 6 x 2 6 ] + [ 6 x 2 6 ] + [ 1 5 9 0 + 6 6 6 ]

= 2 7 2 4 { November Seventh Two Thousand Twenty )


2 6 + 2 + 6 + Twenty Six + 2 + 6 = [ 1 5 9 0 + 5 8 ]


The gematria system i use only produces even number results, and 5 6 would not be enough
to cover my age, because i'm in my 5 8 th year.


When the years from Adam that The Flood began, 1 6 5 6, 1st occurs in Pi,
it's followed by the number 6 1 3 9's 2nd,
and at digit number 6 1 3 9 the number 6 0 2 0{years passed from Adam, yr.2019/20) begins it's 1st occurrence.
We completed 6 0 2 0 yrs in spring of 2 0 1 9, and entered 6 0 2 1.

3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .1 6 5 6 6 1 3 9

3 . 1 4 . . . . . 6 1 3 9 digits . . . . .6)0 2 0

6 0 2 0 occurs before 1 6 5 6, and the 2 numbers are separated by 6 8 6 6 digits

Because of what i discovered, i entered these numbers into those digits to see how they fit,

1 5 9 0 + 5 8 + 6 6 6 + 2 1 6 + 9 1 8 + 1 3 8 0 + 1 1 + 7 + 2 0 2 0 = 6 8 6 6

9 1 8 and 1 3 8 0 are my Wife and Son's name.

[Scott]

1 5 9 0 + 1 3 + 1 8 + 6 6 6 + 2 1 6 + 2 3 6 8 + 1 9 9 5 = 6 8 6 6

The Flood ended 1 6 5 7 years after Adam's creation,

1 6 5 7 + 2 3 6 8 + 1 9 9 5 = 6 0 2 0


When 2 3 6 8 1st occurs, its has 5 4 and 2 8 flanking it,

The number 5 4 2 8 - 2 3 6 8 from each end, leaves 6 6 6 and 2 6 in the middle.

2 6 1st occurs at digits 6, 7,{ 6 7 x 2 6 + 6 2 6 = 2 3 6 8 )

followed by the 1st 5 3 5 8{post #62, P.7

Three point one four one five nine two six = 1 5 9 0 + 1 1 2 2{November Seventh)