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Thread: 9 1 1

  1. #121
    Join Date
    Aug 2013
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    334
    Correction in the last post,

    I just added todays date after finding this in Pi, should have been,

    1 5 9 0 2 0 2 0 9 1 1

    God pointed out to me,

    that last year i was 2 2 x 9 1 1 + 6 6 6 days old on 9 / 1 1



    On March 27th 1991, God led me to discover "The 4 5 0 and 6 6 6 Code" = 1 5 9 0

    and i quickly noticed that what i had done, had divided the 9 numbers into a group of

    3, 2, 1 and 3 whichs creates the number

    3, 2 1 3

    and the very next thing God had me do, was to find a larger number than

    Enoch's Rapture year, 9 8 7, that had digits performing the same 3 features as 9 8 7,

    and the only number that does, is 1 9 9 5,

    and when i learned of increments of 6 gematria and discovered my name was

    1 5 9 0, i remembered back 1 8 yrs earlier

    when i counted 1 9 9 5 and subtracted the answer from 1 9 9 5

    just as i had done with 6 6 6, and the answer was 1 5 9 0

    Heres the location God chose for my name to occur after the decimal point,

    3 .(1 4 . . . . . . . 6 6 6 + 3 2 1 3 + 9 8 7 . . . . . . . . 1)5 9 0

    3 . 1 4 . . . . . . . . . . . (2 1 6 . . . . . . 6 6 6 + 3 2 1 3 . . . . . . 1 5 9 0)
    Last edited by Scott; 03-01-2020 at 11:03 AM.

  2. #122
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    334
    1 5 9 0 + 1 2 3 + 4 5 + 6 6 6 + 7 8 9 = 3 2 1 3



    Count the number of the beast = 1 6 8 0

    Here's the measurement's in digits, from the first occurrence of 6 6 6,

    to the first occurrence of 1 6 8 0,


    3 . 1 4 . . . . . . (6 6 6 . . . . 1 6 8 0 + 6 6 6 + 6 6 6 6 + 6 6 6 + 1 6 8 0 . . . . )1 6 8 0

    Had i included one more digit, the 1 from the 1 6 8 0,

    7 5 6 + [ 1 5 9 0 + 8 2 5 6 ] + 7 5 6{post #'s 94, 95)

    6 6 6 6 + 1 5 9 0 = 8 2 5 6{post # 116)

    Increments of 6 is the correct English gematria method,

    its in perfect harmony with the digits of Pi.

    In terms of Pi, digit # 8 2 5 6 occurs 1 5 9 0 + 3 2 1 3 + 3 3 7 8 digits

    after the first occurrence of 8 6{ELOHIM),

    Saturday November Seventh Two Thousand Twenty = 3 3 7 8

    <><><><><><><><><><><><><><><><><><>

    1 5 9 0 + 1 3 1 8 = 2 3 6 7 + 5 4 1 or, 2 3 6 8 + 5 4 0

    ISRAEL = 5 4 1, shares the same space so to speak, with the 2 3 6 8 th, JESUS CHRIST
    Post # 119
    Last edited by Scott; 03-02-2020 at 11:52 AM.

  3. #123
    Join Date
    Aug 2013
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    334
    I checked to see what was starting to occur, or completing, at digit # 5 7,

    which is, my years of age as of Jan.1st 2020.

    The number 2 0 9 7 4 is completed at digit # 5 7

    Thats my age in days on June 4th 2020, which is day 1 5 6

    of the year this year, because its a leap year.

    1 5 6 days after June 4th 2020, is Nov.7th 2020



    I'll be 5 7 years, 1 5 6 + 1 5 6 days old on Nov.7th 2020

    <><><><><><><><><><><><><><><><><>


    1 5 8 9 + 6 6 6 + 9 1 1 + 2 7 2 4 = 5 8 9 0

    The first occurrence of 666 looks like this,

    6 6 6 7

    so i looked for the first occurrence of this,

    7 6 6 6

    and found it completed at digit # 1 5 8 9 0

    <><><><><><><><><><><><><><><><><>

    9 1 1 begins to occur at digit # 1 5 3 3

    1 5 3 3 + 5 7 = 1 5 9 0

    My name = 1 5 9 0, i'm 5 7 for the year 2 0 2 0, and God is giving me a revelation about 9 1 1

    So i looked up the first occurrence of 1 5 9 0 2 0 2 0, it occurred starting at digit # 97,682,187

    and the 3 digits that followed were 9 1 1

    <><><><><><><><><><><><><><><><><>

    3 .(1 4 . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 . . . . . . 1 5 9 0)
    Last edited by Scott; 03-03-2020 at 02:59 PM.

  4. #124
    Join Date
    Aug 2013
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    334
    Here's where God decided the first occurrence of number 1 5 3 3 would be located,

    Digit # 1 5 3 3 is where the first 9 1 1 is located and begins.

    3 .(1 4 . . . . . . . 1 1 9 + 9 1 1 . . . . . . 1)5 3 3


    The first 1 5 3 3 is starting to occur at digit # [ 1 1 9 + 9 1 1 ]

    The first 9 1 1 is starting to occur at digit # 1 5 3 3


    3 .(1 4 . . . . . . . . 1 5 3 3 . . . . . . . . 9)1 1



    1 5 3 3 + 5 7 = 1 5 9 0

    God chose to show me these 9 1 1 designs at the age of 5 7, in the year 2 0 2 0,

    and chose digit # 1 5 3 3, for the first occurrence of 9 1 1 to begin,.....for that reason!

    1 5 3 3 + 2 0 2 0 = 1 9 6 3 + 1 5 9 0

    Thats why the first occurrence of my name followed by the present year, is followed by 9 1 1,

    3 . 1 4 . . . . . . . . . . . . . . . . . . 1 5 9 0 2 0 2 0 9 1 1


    Simple, but, "designed and planned mathematics", to show me it was
    HIS plan that i make these 9 1 1 discoveries!

    <><><><><><><><><><><><><><><><><><>


    3 . 1 4 . . . . . . . . (9 1 1 . . . . . . .9 1 1 . . . . . . 6 6 6 7)
    Last edited by Scott; 03-04-2020 at 04:40 PM.

  5. #125
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    Aug 2013
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    334
    Backing up 5 7 years from 2 0 2 0 puts us at 1 9 6 3, my birth year.

    If we back up 3 5 groups of 5 7 years, we are at the year 2 5​,

    which is
    3 2 years shy of being the 3 6 th group of 5 7.

    Starting from 0, 3 5 x 5 7 years = 1 9 9 5

    1 9 9 5 + 2 5 = 2 0 2 0
    (post # 101 ^)

    1 9 6 3 + 1 9 9 5 = 1 5 9 0 + 2 3 6 8
    (post # 102 ^)

    That's why 5 7 digits are separating the first occurrence of 1 9 6 3,

    from the first occurrence of 1 5 9 0,

    3 . 1 4 . . . . . . . . . . . . 1 9 6 3( . . . . . 5 7 . . . . . . )1 5 9 0

    <><><><><><><><><><><><><><><><><><><><><><><><>


    3 .(1 4 . . . . . 9 9 0 . . . . . . )(2 1 6 . . . . . . 1 1 9 + 9 1 1 . . . . . .}digit # 2 0 2 0

    9 9 0 + 1 1 9 = 1 1 0 9 ( + 9 1 1 = 2 0 2 0

    9 1 1 begins it's first occurrence at digit # 1 5 3 3

    1 5 3 3 begins it's first occurrence at digit # 1 1 9 + 9 1 1


    <><><><><><><><><><><><><><><><><><><><><><><><>

    September Eleventh Two Thousand Twenty = 2 7 6 6

    3 . 1 4 . . . . . . . . . . . (8 6 . . . . . . . . . 8 8 6 6 . . . . . )2 7 6 6

    9 x 9 1 1 + 6 6 7 = 8 8 6 6

    Here again, is the first occurrence of 9 1 1 and 6 6 6,

    3 . 1 4 . . . . . . . . . . . 9(9 1 1 . . . . . . . . . 9 1 1 . . . . . . . . . 6 6 6 7)
    Last edited by Scott; 03-06-2020 at 11:27 PM.

  6. #126
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    Aug 2013
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    334
    The factors of 1 5 9 0,

    2 x 3 x 5 x 5 3 = 1 5 9 0

    2 3 5 5 3 - 1 1 9 6 3 = 1 1 5 9 0

    digit # 1 1 9 6 3 + 9 1 1 0 = digit # 2 1 0 7 3

    I will be 2 1 0 7 3 days old on 9 / 1 1 / 2 0 2 0

    Last year i was 2 2 x 9 1 1 + 6 6 6 days old on 9 / 1 1


    3 . 1 4 . . . . . . . (2 1 6 . . . . . 2 0 1 9 . . . . . . . . . . . . )0 9 5 1

    This is what follows that first 2 1 6,

    2 1 6 (4(2 0 1 9 8 9 . . . . . . . 2 0 1 9 or 2 0 2 0 . . . . . . 0 9 5 1)

    We have completed 1 9 8 9 years from the Crucifixion.

    That's the 3rd occurrence of 2 0 1 9, and the 2nd is meshed with 1 9 9 5's 1st

    2 0 1 9 9 5
    Last edited by Scott; 03-07-2020 at 04:07 PM.

  7. #127
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    Aug 2013
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    334
    Ivan Panins rendering of Rev. 1 3 : 1 8, only slightly modified

    to sound like todays modern English,

    Here is the wisdom, who has understanding, let him count the

    number of the beast, it is the number of a man, his number

    is Six hundred sixty six

    = [ 2 7 6 6 + 2 7 2 4 + 2 7 6 6 ]

    Could that be the 9 1 1 of 2 0 2 0 leading up to

    the 1 1 7 of 2 0 2 0 ?


    September Eleventh Two Thousand Twenty = 2 7 6 6

    November Seventh Two Thousand Twenty = 2 7 2 4
    =======================================

    7 / 1 1 + 1 1 9 day's = 1 1 / 7

    =======================================

    3 2 1 3 - 1 6 8 0{Count the number of the beast) = 1 5 3 3

    Digit # 1 5 3 3 is where 9 1 1 {preceded by a 9) begins its first occurrence.

    The reverse of 3 2 1 3,

    3 1 2 3 - 1 5 9 0 = 1 5 3 3

    3 . 1 4 . . . . . . . . . (9 9 1 1 . . . . . . . .9 1 1 . . . . . . . . 6 6 6)

    Digit # 1 5 3 3{9 1 1 begin's) + 1 6 8 0 = 3 2 1 3 digits

    =======================================

    The sum of the letters in the English alphabet = 2 1 0 6

    1 5 9 0 + 7 5 6 = 1 6 8 0 + 6 6 6

    1 5 x 9 0 + 7 5 6 = 2 1 0 6
    1 6 x 9 0 + 6 6 6 = 2 1 0 6
    756 post # 69

    3 2 1 3 - 2 1 0 6 = 1 1 0 7

    8 6 + 1 1 0 7 + 2 0 2 0 = 3 2 1 3 { post #'s 64, 107)
    Last edited by Scott; 03-09-2020 at 11:56 AM.

  8. #128
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    334
    3 2 1 3 - 1 1 0 7 = 2 1 0 6{sum of the alphabet)

    2 1 0 6 - 2 0 2 0 = 8 6


    3 2 1 3 - 2 0 2 0 = [ 6 6 6 + 2 1 6 + 3 1 1 ]

    3 1 1 days of 2 0 2 0 completed, is the beginning of 1 1 / 0 7

    The 3 1 1 tells me that the 1 1 0 7 and 2 0 2 0 is in fact the date that

    is the measurement from digit # ELOHIM = 8 6, to, digit # 3 2 1 3

    3 of every 4 yrs 11 / 0 7 is day 3 1 1 of the year.

    In terms of the positions of Pi{ 3 and . are position 1 and 2),

    GOD = 1 5 6 completes at position 2 3 3 1 { 7 7 7 + 7 7 7 + 7 7 7 }

    2 3 3 1 + 6 6 6 + 2 1 6 = position 3 2 1 3

    2 3 3 1 - 3 1 1 = 2 0 2 0

    All the positions after position 1 of Pi, the 3, are 3 1 1 + 2 0 1 9 positions beginning

    with the decimal point where the change takes place as position 1, instead of the 3 preceding the

    decimal point.

    God began giving me this 9 1 1 revelation after i turned 5 7 yrs from conception.

    1 5 9 0 - 5 7 = 1 5 3 3{ 9 1 1 first occurs starting at this digit # )

    The number that was instrumental in helping me bring this whole thing into focus, was the 5 4 1 that God

    shed light on for me 5 4 1 days after the Rev. 1 2 Sign on 9 / 2 3 /2 0 1 7, at 5 6 yrs of age,

    by showing me that ISRAEL = 5 4 1, and that 5 4 1's first occurrence follows the first occurrence

    of May Fourteenth Two Thousand Eighteen{=2 4 2 4) in Pi's digits. { post # 1 1 9 )

    5 6 + 3 1 4 {Pi) + 5 4 1 = 9 1 1

    If we back up 5 4 1 digits from the completion of the first 9 1 1,

    we are at digit # 9 9 5, and the 3rd occurrence of 2 0 1 9 starts at digit # 9 9 5

    <><><><><><><><><><><><><><><><><><><><>

    My name 1 5 9 0 completes its first occurrence at digit # 4 8 6 9

    The number 4 8 6 9 begins its first occurrence at digit # 2 2 5 0 6

    6 6 6 + 1 5 9 0 = 2 2 5 6

    6 6 0 6 + 1 5 9 0 0 = 2 2 5 0 6

    <><><><><><><><><><><><><><><><><><><><><>

    Elohim(=86)

    allowed, in his timing,

    Jesus Christ(=2 3 6 8, and a placement value of 8 7 among the letters of the Greek alphabet)

    to be crucified year 4 0 3 2 from Adam,

    8 7 + 2 3 6 8 + 6 6 6 + 9 1 1 = 4 0 3 2
    Last edited by Scott; 03-11-2020 at 08:05 AM.

  9. #129
    Join Date
    Aug 2013
    Posts
    334
    9 1 1 and 1 1 2, are the world's standard emergency numbers,

    3 .(1 4 . . . . . 7 1 1 . . . . 1 1 2| . . . . . . . 1 5 6 + 6 6 6 . . . . . . 9)1 1

    ================================================== ===

    The man that started this site has 1 0 5 0 for the sum of his name,

    and when i backed up 3 1 4{3.14) digits, with the 6 of 2 1 6's

    first occurrence as digit 1 of the 3 1 4 digits,...counting backwards, digit 3 1 4 was the first

    digit of the first occurrence of his name.

    These numbers follow the first 2 1 6,
    4 2 0 1 9 9 5


    This is what shows up at the first occurrence of 1 0 5 0 1 5 9 0

    starting at digit # 4 2, 3 6 4, 1 9 5

    1 0 5 0 1 5 9 0 0 2 0 2 0 3 6 7

    1 0 x 1 0 5 0 + 1 = 1 0 5 0 1
    ___ 1 0 x 1 5 9 0 = 1 5 9 0 0
    ________________ 2 0 2 0 3 6 7

    The 4 digit number that 1 0 5 0 1 5 9 0 sits in the middle of, is, 3 7 0 2

    1 5 6 + 1 0 5 0 + 1 5 9 0 + 9 0 6 = 3 7 0 2

    I came on this site to show him and other's, what i thought was compelling evidence

    for 2 0 1 9 or 2 0 2 0 being the year of the return of 2 3 6 8

    for his Bride.

    I believe now, that i was to show him, that following the instructions of Rev. 1 3:1 8

    reveals the time of 2 3 6 8's Return,

    1 0 5 0 + 1 3 1 8 = 2 3 6 8



    3 .(1 4 . . . . . 6 1 2 + 6 6 6 + 1 0 5 0 . . . . . . 1 5)(6 . . . . . . 1 0 5 0 . . . . . }digit # 3 3 7 8{Sat. 11/7/20)

    3 .(1 4 . . . . . 6 6 6 + 2 1 6 + 1 0 5 0 + 1 0 5 0 . . . . . . . . . . . . . . . }digit # [ 9 8 7 + 1 9 9 5 ]

    The first occurrence of 8 6 1 0 5 0, has this 4 digit number precede it,

    6 6 6 7 8 6 1 0 5 0

    6 6 6 7 is seen at the first occurrence of 6 6 6, 4 6 1, 2 3 6 digits back

    completing at digit 2 4 4 3, which is 9 1 1 digits from the start of the first occurrence of 9 1 1

    This first occurrence, 9 1 1, and this first, 6 6 6 7,

    cover a span of exactly 9 1 1 digits, and the first 3 are, 9 1 1
    Last edited by Scott; 03-12-2020 at 10:32 AM.

  10. #130
    Join Date
    Aug 2013
    Posts
    334
    1 7 6 + 3 1 4 + 1 7 6 = 6 6 6

    After the first 1 7 6 verses of The Bible, the 4 5 0 foot long Ark is Lift Up above the earth

    At the start of the last 1 7 6 verses, instructions are given to count 6 6 6

    1 2 3 + 6 6 6 = 7 8 9

    4, 5 and 0 have not been utilized yet,

    6 x 6 x 6 = 2 1 6

    6 6 6 - 2 1 6 = 4 5 0

    ==================================================

    3 . 1 4 . . . . . . . . . . . . . (1 0 5 0 . . . . . . . . . . 3 1 4 . . . . . . . . . 2 1 6 4)2 0 1 9 9 5

    3 . 1 4 . . . . . . . . . . . . . 1 0 5 0( . . . . . . . . . . . 3 1 4 . . . . . . . . . . . . . . 2 0 1 9)9 5

    3 .(1 4 . . . . . . . . . . . . . . . . . 1 0 5 0 + 1 3 1 8 digits . . . . . . . . . . . . . . . . . . }digit # 2 3 6 8

    1 5 6 + 9 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 = 3 5 3 4

    3 5 3 4 begins its first occurrence at digit # 2 3 6 8
    Last edited by Scott; 03-13-2020 at 08:42 AM.

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