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Thread: 9 1 1

  1. #201
    Join Date
    Aug 2013
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    387
    The 4 digit number that completes its first occurrence at digit # 6 6 6, is, 4 9 5 3,

    Here is, not the number itself, but digit # 4 9 5 3 in Pi,

    3(1 4 . . . 7 5 digits . . . 8 6)(. . . 2 4 0 6 + 1 5 9 0 + 6 6 6 + 2 1 6 digits . . .}digit # 4 9 5 3

    January First Nineteen Sixty Three = 2 4 0 6



    A=6 , B=12 , C=18 , D=2 4 , . . . . . . Z=1 5 6

    ===========================================

    Seven hundred ninety eight = 1 6 5 0 = Six hundred sixty six


    Seven hundred ninety eight,
    Nine hundred eighty seven,
    and, One thousand nine hundred ninety five


    = [ 1 9 9 5 + 1 5 9 0 + 1 9 9 5 ] or, [ 3 2 1 3 + 2 3 6 7 ]


    Post # 200, 1 9 9 5

    3 2 1 3,

    1 2 3 ---- 4 5 ---- 6 ---- 7 8 9
    Last edited by Scott; 07-01-2020 at 10:16 PM.

  2. #202
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    1 5 9 0 + 1 2 3 + 4 5 + 6 6 6 + 7 8 9 = 3 2 1 3

    5 4 1 + [ 1 5 9 0 + 5 4 1 ] + 5 4 1 = 3 2 1 3
    ===========================================

    We had sign's in the Sun, Moon, and Star's, and then

    the 7 0 year generation was completed on,

    May Fourteenth Two Thousand Eighteen = 2 4 2 4

    What i'm showing next was shown to me 5 4 1 days after

    The Revelation 1 2 Sign that took place 9 / 2 3 / 2 0 1 7,

    ISRAEL = 5 4 1 in Hebrew

    5 4 1 days after 5 / 1 4 / 2 0 1 8, is 1 1 / 0 7 / 2 0 1 9

    2 4 2 4 5 4 1 is what you see at the first occurrence's of 2 4 2 4 and 5 4 1,

    and that string of digits first occurs right after the first 1 1 0 7 digits of Pi.



    1 1 /0 7 /2 0 2 0 will be 9 0 7 days after 5 / 1 4 / 2 0 1 8

    The number 9 0 7 first occurs right after the first 5 4 1 digits of Pi.

    The first occurrence of 5 4 1 begins at digit # 1 1 1 2

    Digit # 1 1 1 2 + 9 0 7 digits = digit # 2 0 1 9
    Digit # 1 1 1 3 + 9 0 7 digits = digit # 2 0 2 0


    Here are the first occurrence's of the number's 9 0 7 and 2 4 2 4 5 4 1,

    3 .(1 4 . . . . 5 4 1 digits . . . . )9 0 7 . . . . . . . . . . . . . 2 4 2 4 5 4 1

    The underlined 4 is digit # 1 1 1 3


    The Revelation 1 2 Sign that John wrote about in the 1 1 7 9 th chapter

    of The Bible, took place on,

    9 / 2 3 / 2 0 1 7

    September Twenty Third Two Thousand Seventeen = [ 9 + 2 3 + 2 0 1 7 + 1 1 7 9 ]


    The Bible consists of a total of 1 1 8 9 chapters, which is 1 1 7 9 short

    of matching the Greek gematria sum of JESUS CHRIST = 2 3 6 8
    Last edited by Scott; 07-02-2020 at 02:18 PM.

  3. #203
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    3 .(1 4 . . . 5 4 1 . . .)9 0 7 . . . . . . 2 4 2 4 5 4(1 . . . 9 0 7 . . . }digit # 2 0 2 0

    A total of 1 1 0 7 digits precede the 2 4 2 4 5 4 1



    2 4 2 4 5 4 1( . . . . . . . 9 0 6 . . . . . . . .}digit # 2 0 2 0



    That's also the first occurrence of,

    8 6 + 2 3 6 8 = 2 4 5 4



    Coronavirus disease = 1 3 0 2

    First occurrence of 1 3 0 2,

    2 0 1 9 1 3 0 2




    9 / 2 3 / 2 0 1 7 + 1 1 4 1 days = 1 1 / 0 7 / 2 0 2 0

    November / Seventh / Two Thousand Twenty = 2 7 2 4

    The actual number 1 1 4 1 occurs first starting at digit # 2 7 2 4

    2 7 2 4 completes its first occurrence at digit # 4 8 0{The beast = 4 8 0 )

    Digit # 4 7 6 + 6 6 5 digits = digit # 1 1 4 1
    Last edited by Scott; 07-04-2020 at 12:05 AM.

  4. #204
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    Ivan Panin's translation,

    Here is the wisdom, who hath understanding, let him
    count the number of the beast, for it is the number
    of a man, and his number is Six hundred sixty six

    = 8 6 5 8


    3 . 1 4 . . . . . . . . . . . . . (8 6 5 8 . . . . . . . . 3 9 9 7 digits . . . . . .)1 5 9 0


    January First Nineteen Sixty Three + 1 5 9 0 = 3 9 9 6


    My first, middle, and last name consist of 7, 5, and 6 letter's, adding to 1 5 9 0

    7 5 6 + "Represent's" = 1 5 9 0

    When 1 5 9 0 first occurs, its settled between the 5 and 6 of the number 7 5 6

    Here are the measurements in the digits from the first occurrence of 7 5 6
    to the first occurrence of 7 5 1 5 9 0 6


    3 .(1 4 . . . 2 0 8 . . .)(7 5 6 . . . 6 6 5 . . . 8 6 5 8 7)(5 . . . 3 9 9 6 . . . 7 5 1 5 9 0 6)


    3 9 9 6 + 6 6 6 + 3 9 9 6 = 8 6 5 8

    8 6 5 8 - "Count the number of the beast" = [ 3 9 9 6 + 9 8 7 + 1 9 9 5 ]



    3 . 1 4 . . . . (7 5 1 5 9 0 . . . . . 1 5 9 0 + 6 6 6 + 2 1 6 + 1 9 9 5 . . . . 3 6 7)3 6 7 2

    That was the first occurrence of 3 6 7 2

    "...., let him, 1 5 9 0, count the number of the beast" = 3 6 7 2
    Last edited by Scott; 07-06-2020 at 11:42 AM.

  5. #205
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    7 5 6 + 1 5 9 0 = [ Count the number of the beast{1680) + 6 6 6 ]


    7 5 6 + 7 + 5 + 6 + Seven hundred fifty six + Seven + Five + Six

    =
    [ 1 6 8 0 + 1 5 9 0 ]


    6 6 6 + 6 + 6 + 6 + Six hundred sixty six + Six + Six + Six

    = [ 1 6 8 0 + 1 5 9 0 ]


    S i x H u n d r e d S i x t y S i x
    114 54 144 48 126 84, 24 108 30 24 114 54, 144 120 150 114 54 144 = 1 6 5 0

    A=6 B=12 C=18 D=24 . . .
    Last edited by Scott; 07-07-2020 at 02:31 PM.

  6. #206
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    7 x 9 x 8 = 5 0 4

    9 x 8 x 7 = 5 0 4


    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0
    p.11, post # 102



    5 0 4 + 5 + 4 + Five hundred four + Five + Zero + Four = 2 5 6 5

    2 5 6 5 has been the last 4 digits of our family's phone # for just over 50 yrs.



    4 0 5 + 4 + 5 + Four hundred five + Four + Zero + Five

    = [ 2 1 0 + 6 6 6 + 1 5 9 0 ] or 2 4 6 6

    3 . 1 4 . . . . 2 1 0 digits. . . . 7 5)(6 . . . . . 6 6 6 + 1 5 9 0 digits . . . .}digit # 2 4 6 6



    The first occurrence's of 1 9 9 5 and 1 5 9 0,

    3 . 1 4 . . . . . . 1(9 9 5 . . . . 1 5 6 + 6 6 6 + 2 1 6 + 1 1 0 7 + 2 0 2 0 . . . . 1 5 9 0)


    One thousand five ninety = 1 5 9 0

    One thousand three eighteen = 1 5 9 0
    Last edited by Scott; 07-08-2020 at 03:59 PM.

  7. #207
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    Aug 2013
    Posts
    387
    Starting from the first digit of the first occurrence of number 7 5 6 and counting 1 3 8 0 digits,

    is digit # 1 5 8 9,

    3 . 1 4 . . . . . . . 7(5 6 . . . . . . . 1 3 8 0 digits . . . . . . )( digit # 1 5 9 0 )

    1 3 8 0 is my Son's name, and he has my first name{5 8 2) for his middle.

    I noticed that if i backed up 5 8 2 from 1 9 6 2, it put me at the

    year 1 3 8 0


    <><><><><><><><><><><><><><><><><><><><><><>


    I began this work, counting 6 6 6, in March of 1 9 9 1,

    and here's the first occurrence of my name followed by 1 9 9 1,

    3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . . 1 1 9 1 5 9 0 1 9 9 1



    Now here i am 2 9 yrs later posting this 9 1 1 thread, and here's the first occurrence of my name followed by 2 0 2 0,

    3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 5 9 0 2 0 2 0 9 1 1 7



    9 1 1 occurs first starting at digit # 1 5 3 3.

    Digit # 1 5 3 3 + 5 7 = digit # 1 5 9 0,....i'm 5 7 this year,

    and in Pi, 5 7 digits separate the first occurrence of my birth year, 1 9 6 3, from

    the first occurrence of my name, 1 5 9 0

    9 / 1 1 + 5 7 days, is 1 1 / 0 7

    The actual number 1 5 3 3 begins to occur first at digit # [ 1 1 9 + 9 1 1 ]

    The first 9 1 1 is Sept.11th 2 0 0 1

    The 9th + 11th 9 1 1 is Sept. 11th 2 0 2 0

    6 6 6 + 2 1 6 + 2 9 = 9 1 1


    Here are the first occurrence's of 9 1 1 and 6 6 6,

    3 . 1 4 . . . . . . . . . . . . . (9 9 1 1 . . . . . . . 9 1 1 digits . . . . . . . . 6 6 6)


    And again. here are the first occurrence's of the Hebrew sum of Elohim{God) = 8 6

    and the only number he gives instructions to count, 6 6 6,

    3 . 1 4 . . . . . . . 8(6 . . . . . . . . . . . . . 2 3 6 8 . . . . . . . . . . . . . . 6 6 6)

    2 3 6 8 is the Greek sum Elohim chose for his Son's name.
    Last edited by Scott; 07-10-2020 at 10:55 AM.

  8. #208
    Join Date
    Aug 2013
    Posts
    387
    The 2 dates that i have my eye on for this year, occur combined,
    following the first occurrence of my name and 2 0 2 0

    1 5 9 0 2 0 2 0 9 1 1 7


    My name, 1 5 9 0, completes its first occurrence at digit # 4 8 6 9

    2 3 6 8 + 1 5 9 0 + 9 1 1 = 4 8 6 9


    On the Last 9 / 1 1, i was 2 2 x 9 1 1 + 6 6 6 days old.
    Last edited by Scott; 07-11-2020 at 07:56 AM.

  9. #209
    Join Date
    Aug 2013
    Posts
    387
    Rev. 1 3 : 1 8, "Count 6 6 6",

    is 1 verse out of the 4 0 4 in the book of Rev.

    2 9 yrs ago i found this,

    1 2 3 4 5 6 7 8 9 0

    1 2 3 + 6 6 6 = 7 8 9

    6 x 6 x 6 = 2 1 6

    6 6 6 - 2 1 6 = 4 5 0 {length in feet of Noah's Ark)

    And now 2 9 yrs later i find this in Pi,


    When counting the first occurrence of my name, 1 5 9 0,

    as the first 4 digits of 6 6 6 digits,

    the 6 6 6 digits split at 4 5 0 and 2 1 6 right at

    the 8 in the first occurrence of the number 1 3 1 8


    1 5 9 0 begins right after digit # 4 8 6 5, and 1 3 1 8 completes

    at digit # 5 3 1 5

    The first occurrence of 6 6 6 starts right after digit # 2 4 3 9

    Digit # 2 4 3 9 + 4 0 4 + 1 5 9 0 + 6 6 6 + 2 1 6 digits = digit # 5 3 1 5


    6 6 6 completes at digit # 2 4 4 2

    4 0 4 + 1 1 + 7 + 2 0 2 0 = 2 4 4 2


    The first book of the N.T. has 1 0 7 1 verses,

    The Last book has 4 0 4

    4 0 4 < 6 6 6 > 1 0 7 1

    4 0 4 + 1 = 4 0 5,

    and in the natural order of numbers the 4 0 5 is # 1 of the 6 6 6

    to reach the number 1 0 7 0

    <><><><><><><><><><><><><><><><>

    1 + 2 + 3 + 4 . . . . + 1 7 = 1 5 3 {Fish, John 21:11)

    The number 1 7 completes its first occurrence at digit # 9 6

    1 5 3 completes its first occurrence at digit # 3 4 6

    Digit # 3 4 5, is 1 digit short of the completion of 1 5 3's first occurrence in Pi,

    9 6 + 1 5 3 + 9 6 = 3 4 5


    This is what you see at the first occurrence of 1 5 3,

    9 1 7 1 5 3


    9 x 1 7 = 1 5 3

    5 x 1 5 3 + 1 5 2 = 9 1 7


    The first 1 7 digits of Pi end with 9 3 2 3

    9 1 7 0 + 1 5 3 = 9 3 2 3

    9 1 7 0 - 1 5 3 = 9 0 1 7


    1 7 + 1 5 6 + 1 7 + 1 5 6 = 3 4 6

    I know its God helping me find these things, so after finding that i did this,

    1 5 9 0 - [ 1 6 x 1 7 ] = 1 3 1 8

    The 1 7 th 1 7 is in the 1 3 1 8


    My first, middle, and last name,

    5 8 2 + 4 6 2 + 5 4 6 = 1 5 9 0

    Factors of 5 4 6: 2 x 3 x 7 x 1 3

    3 .(1 4 . . . . 9 9 3 . . . . 2 1 6)( . . . . . . 1 5 9 0 + 2 1 1 3 0 . . . . . } digit # 2 3 7 1 3

    Come Nov.7th i will have lived 2 1 1 3 0 day's

    <><><><><><><><><><><><><><><><>


    The second 7 in this first occurrence of 7 7 7 and 7 7 7 7 is digit # 1 5 9 0

    1 0 5 0 is the sum of Richard's name.

    The small numbers are the number of digits between the brackets,

    and this is the 4th occurrence of the number 9 0 9


    The first 9 0 9 occurs connected to the first occurrence of 2 0 1 9,

    2 0 1 9 0 9,

    and the 2nd 9 0 9 occurs right after digit # 9 8 7{p.11,post 102), and completes

    right before the first occurrence of 2 1 6, which is followed by 4 2 0 1 9 8 9,

    and the 3rd 9 0 9 occurs right after the first 1 4 8 0{Christ/Grk.) digits.



    3 . 1 4 . . . . . . (1 0 5 0 . . . 9 0 9 . . . 9 0 9 7)(7 7 7 . . . . . . 9 0 9 + 2 3 6 8 . . . . 1)5 9 0

    A 9 1 1 design exists in that as well if you extend it to the completion of 1 5 9 0 from

    the start of the first occurrence of 1 0 5 0,

    3 . 1 4 . . . . . . (1 0 5 0 . . . . . . . . . 9 1 1 + 2 3 6 8 + 9 1 1 . . . . . . . . . . . . . . . 7 5 1 5 9 0 6)

    (7 5 6, post # 204)

    Believing that Jesus Christ wanted me to start this 9 1 1 thread on Richards{1 0 5 0) website

    has, almost 1 year later, become even more real to me after finding that!!

    My name 1 5 9 0 completes at digit # 4 8 6 9

    1 5 9 0 + 2 3 6 8 + 9 1 1 = 4 8 6 9
    Last edited by Scott; 07-13-2020 at 03:01 PM.

  10. #210
    Join Date
    Aug 2013
    Posts
    387
    3 .(1 4 . . . . . 7 5 6 . . . . . )(2 1 1 3 . . . . 1 5 6 + 2 3 6 8 + 1 5 9 0 . . . . 7 5 1 5 9 0 6)

    Thats the first occurrence of 2 1 1 3, and 7 5 1 5 9 0 6

    2 1 1 3 0 days of life for me come Nov.7th 2020

    3 . 1 4 . . . . . . 8 6( . . . . . 1 1 + 7 + 2 0 2 0 . . . . . }digit # 2 1 1 3

    Starting at digit # 2 1 1 3 and completing at digit # 2 1 1 6, is the first

    occurrence of the number 3 9 9 6,

    and the first 3 9 9 6{6 x 666) digits of Pi end with this string of digits, 2 1 1 1 6 6

    January First Nineteen Sixty Three + 1 5 9 0 = 3 9 9 6


    God= 1 5 6/ English

    Jesus Christ = 2 3 6 8/Greek

    Elohim = 8 6/Hebrew

    Jesus Christ = 9 0 6/English

    <><><><><><><><><><><><><><><><><><><>


    Counting 1 3 1 8 digits from the completion of the first

    occurrence of 1 0 5 0{R.A.M), puts us at digit # 2 3 6 8

    The 4 digit number starting at digit # 2 3 6 8 is 3 5 3 4

    6 6 6 + 2 1 6 + 1 5 6 + 9 0 6 + 1 5 9 0 = 3 5 3 4
    Last edited by Scott; 07-15-2020 at 07:29 AM.

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