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  1. #34
    Join Date
    Aug 2013
    Posts
    358
    The 9th + 11th occurrence of 9 1 1 in Pi, begins to occur at digit # 2 3 1 1 4

    1 3 1 8 + 6 6 6 + 2 1 1 3 0{my days,11/7/20) = 2 3 1 1 4

    It was the instructions of Rev. 1 3 : 1 8 to

    count 6 6 6 that led me to Nov.7th 2020.


    The first 9 1 1 begins to occur at digit # 1 5 3 3,

    and 1 5 3 3 begins first at digit # 9 1 1 + 1 1 9

    The first occurrence of number 1 5 3 2, is preceded by 9 1 1 9

    1 5 x 1 5 3 3 + 1 1 9 = 2 3 1 1 4



    9 1 1 + 9 + 1 + 1 + Nine Hundred Eleven + Nine + One + One = [ 1 5 6 + 1 5 9 0 + 9 1 0 ]

    [ 1 5 6 + 1 5 9 0 + 9 1 0 ] + Nine Eleven = [ 9 1 1 + 1 5 9 0 + 6 6 6 + 1 1 9 ]

    3 .(1 4 . . . . . 9 1 1 + 1 1 9 . . . . . . 1)(5 3 3 . . . . . . 1 5 9 0 + 6 6 6 . . . . . )

    9 1 1 + 1 1 9 + 1 5 9 0 + 6 6 6 = [ 7 3 + 3 2 1 3 ]
    3 .(1 4 . . . . . 7 3 . . . . )(8 6 . . . . . . . 3 2 1 3 . . . . . )


    3 .(1 4 . . . . . . . . 8 6 + 1 1 0 7 + 2 0 2 0 digits . . . . . . . . }digit # 3 2 1 3


    ( 3 2 1 3, post #'s 121, 122 )


    3 . 1 4 . . . . . . . . . . . (9 1 1 . . . . . . . . 9 1 0 digits . . . . . . . 6 6 6)
    Last edited by Scott; 03-29-2020 at 10:09 AM.

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