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  1. #191
    Join Date
    Aug 2013
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    361
    3 .(1 4 . . . . 3 5 5 2 + 1 3 1 8 . . . . 7 5( 1 5 9 0 6 ) . . . 4 5 0 . . . . 1 3 1 8 ) . . . 2 1 6 . . .|

    1 9 6 2 + 1 5 9 0 = 3 5 5 2
    Last edited by Scott; 06-13-2020 at 06:35 PM.

  2. #192
    Join Date
    Aug 2013
    Posts
    361
    The words in Panin's Rev. 1 3 : 1 8 have 8 6 5 8 for their sum.


    Elohim = 8 6 in Hebrew

    God = 1 5 6 in English

    1 5 6 completes its first occurrence at digit # 2 3 2 9

    Jesus Christ = 7 5 4 in Hebrew.

    Jesus Christ = 2 3 6 8 in Greek.

    7 5 4 < 1 6 1 3 > 2 3 6 8



    3 .(1 4 . . . . . . . . . . . . . 2 3 2 9 . . . . . . . . . . . . . 1 5 6)


    3 . 1 4 . . . .(8 6 . . . . . 1 5 9 0 + 6 6 6 . . . . . . . . . 1 5 6)


    3 . 1 4 . . . . . . . . . 7 5 4( . . . . . . . . . . . . 6 3 2 5 . . . . . . . . . . )2 3 6 8


    3 .(1 4 . . . . . . . . . . . . . . 2 3 2 9 + 6 3 2 9 . . . . . . . . . . . . . . . . . . . .} digit # 8 6 5 8


    6 3 2 5 - [ 7 5 4 + 1 5 9 0 + 2 3 6 8 ] = 1 6 1 3



    My name 1 5 9 0 occurs first right after digit # 4 8 6 5,

    4 8 6 5 + 6 6 6 + 1 1 0 7 + 2 0 2 0 = 8 6 5 8
    Last edited by Scott; 06-14-2020 at 10:46 PM.

  3. #193
    Join Date
    Aug 2013
    Posts
    361
    God knew he was going to inspire me to find that!
    The number of digits separating 7 5 4 and 2 3 6 8's
    first occurrence's in Pi by chance many would say, will
    accomodate the two numbers it separates in Pi themselve's,
    the number that separates them in the natural order of numbers, 1 6 1 3,
    and also, the gematria sum of my name 1 5 9 0.
    There are many examples of this in what i've posted
    these last 10 months.
    Last edited by Scott; 06-18-2020 at 09:58 AM.

  4. #194
    Join Date
    Aug 2013
    Posts
    361
    First occurrence's of,
    my birth year 1 9 6 3{Jan.1st 1963),
    1 9 6 2,
    and my name,
    1 5 9 0,
    that consists of 7, 5, and 6 letters.


    1 9 6 3 begins right after digit # 4 8 0 4,

    1 9 6 2 ends at digit # 9 0 8 0,

    1 5 9 0 begins right after digit # 4 8 6 5,



    3 . 1 4 . . . .(1 9 6 3 . . . . . . . . 1 5 9 0 + 6 6 6 + 2 0 2 0 digits . . . . . . . . . . . . . . . . . . . . . . . . 1 9 6 2)


    3 . 1 4 . . . . .1 9 6 3( . . . 5 7 digits . . . 7 5)1 5 9 0 6


    3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . (7 5 1 5 9 0 6 . . . . 1 9 6 2 + 1 5 9 0 + 6 6 5 digits . . . . 1 9 6 2)


    Here's the first occurrence of 6 6 6 and 1 9 6 3,

    3 . 1 4 . . . . . . . 6(6 6 . . . . . 2 3 6 8 digits . . . . . 1 9 6 3)


    1 9 6 3 + 5 7 = 2 0 2 0


    The First occurrences of 8 6 and 1 5 6{Elohim in Hebrew and God in English),

    cover a span of 1 5 9 0 + 6 6 6 digits.

    Counting that first occurrence of 8 6 as digit 1 and 2 of 2 3 6 8{JC/Grk.) digits,

    lands us at the middle 6 of the first occurrence of 6 6 6




    Digit # 1 5 3 3{1st occurrence of the number 9 1 1 begins) + 5 7 digits = digit # 1 5 9 0

    Here's what i found at the first occurrence of 1 5 9 0 2 0 2 0, after realizing 2 0 2 0 will be,

    9 + 1 1,.....9 1 1's, including THE 9 1 1.

    3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 5 9 0 2 0 2 0 9 1 1


    Here are the number of digits to the completion of the first occurrence of my name,


    3 .(1 4 . . . . . . . . . 2 3 6 8 + 1 5 9 0 + 9 1 1 digits . . . . . . . . . 7 5 1 5 9 0)6


    Here again are the first occurrence's of 9 1 1 and 6 6 6,


    3 .(1 4 . . . . 1 5 3 1 digits . . . . )(9 9 1 1 9 . . . . . 9 1 1 digits . . . . . 6 6 6)

    Digit # 1 5 3 3 is the first digit of 9 1 1's first occurrence.

    Here's the first occurrence of number 1 5 3 3,

    3 .(1 4 . . . . . 9 1 1 + 1 1 9 digits . . . . . 1)5 3 3
    Last edited by Scott; 06-21-2020 at 12:32 PM.

  5. #195
    Join Date
    Aug 2013
    Posts
    361
    Panin proved that the Seventy Week's of years began 3 5 1 6 years after Adam was created,

    "in" the year 3 5 1 7,

    and that 6 9 x 7 years(4 8 3 yrs) later Jesus Christ was born "in" the year 4 0 0 0,

    and crucified "in" the year 4 0 3 3!

    The 70th week is still to come,...don't let anyone tell you different!!

    3 5 1 6 + 5 1 6 = 4 0 3 2

    The number 5 1 6 occurs first in Pi starting at digit # 3 5 1 5,

    Digit # 3 5 1 6 is the 1 in 5 1 6's first occurrence.

    Digit # 3 5 1 7 is the 6 in 5 1 6's first occurrence.

    3 .(1 4 . . . . . . . 3 5 1 7 . . . . . . . 5 1 6)



    We're at 6 0 2 2 years now, so i took a look at the first 6 0 2 1 digits of Pi all blended together and i pulled them apart,

    3 .(1 4 . . . . 7 5 . . . . 8 6)( . . . . 5 1 6 + [ 5 1 6 + 3 5 1 6 ] + 5 1 6 + [ 6 6 6 + 2 1 6 ] . . . .} digit # 6 0 2 1

    6 0 2 1, Page 9 post # 82

    3 .(1 4 . . . . 7 5 . . . . 8 6)( . . . . 1 5 9 0 + 2 3 6 8{digit#4033) + 1 9 8 9 digits . . . . . . . . } digit # 6 0 2 2



    Here's what remains when we measure into 3 5 1 7 with 6 6 6,

    6 6 6 + 4 8 3 + 2 3 6 8 = 3 5 1 7

    3 5 1 7 is no doubt the first year of the 6 9 week's (4 8 3) of years

    leading to the birth of 2 3 6 8


    8 6 + 1 5 6 + 2 3 6 8 + 9 0 6 = 3 5 1 6
    Last edited by Scott; 06-22-2020 at 04:15 PM.

  6. #196
    Join Date
    Aug 2013
    Posts
    361
    The Flood ended at the 1 6 5 7 year mark, plus 2 3 6 8 plus 1 9 9 5 years

    is the same year of Israel's 70th year,..end of the generation. {p.11, post 102)

    The Bread of God = 1 9 9 5 in Greek.


    7 x 9 x 8 = 5 0 4

    7 9 8 - 5 0 4 = 2 9 4


    9 x 8 x 7 = 5 0 4

    Enoch Raptured 9 8 7 years after Adam's creation.

    9 8 7 - 5 0 4 = 4 8 3{6 9 x 7)


    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0


    2 9 4 + 4 8 3 = 7 7 7 ( + 1 5 9 0 = 2 3 6 7

    1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]


    2 3 6 8 + 6 9 + 1 9 9 5 + 1 5 9 0 = 6 0 2 2
    Last edited by Scott; 06-22-2020 at 06:48 PM.

  7. #197
    Join Date
    Aug 2013
    Posts
    361
    Digit # 1 9 6 2 is preceded by the first occurrence of 5 7 5 7

    The first occurrence's of 1 9 6 3 and 1 5 9 0

    are separated with 5 7 digits.


    3 . 1 4 . . . . . . . . . . 1 9 6 3( . . . . 5 7 . . . . )1 5 9 0


    (Jan.1st}1 9 6 3 + 5 7 = 2 0 2 0

    1 9 6 3 + 2 0 2 0 = 3 9 8 3

    so i looked to see where 3 9 8 3 first occurs, and it

    just happens to occur starting at digit # 2 0 2 0

    My name 1 5 9 0 first occurs right after digit # 4 8 6 5

    4 8 6 5 - [ 6 6 6 + 2 1 6 ] = 3 9 8 3

    9 / 1 1 / 2 0 2 0 + 5 7 days, is 1 1 / 0 7 / 2 0 2 0

    The number 9 1 1 occurs first starting at digit # 1 5 3 3

    1 5 3 3 + 5 7 = 1 5 9 0

    The first occurrence of the number 5 7 completes at digit # 4 0 5

    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0




    i got the notion to look for tomorrows date in Pi, 06/24/2020, because
    it might be a very significant day for me, and this is what i saw,

    3 . 1 4 . . . . . . . . . . . . . . . . . . . 1 5 9 0 0 6 2 4 2 0 2 0

    I'd be willing to bet thats the only date of this year, found in the first
    200 million digits of Pi, that has my name making an occurrence right before it!


    6 + 2 4 + 2 0 2 0 = 2 0 5 0

    When 2 0 5 0 first occurs in Pi,

    3 . 1 4 . . . . . . . . . 2 0 5 0 1 1 0 7 9 8 7
    Last edited by Scott; 06-24-2020 at 08:25 AM.

  8. #198
    Join Date
    Aug 2013
    Posts
    361
    The Seventieth Week = 1 2 2 4

    (3 . 1 4 . . . . . . . . 6 6 5 position's . . . . . . . . 1 2 2 4)

    3 .(1 4 . . . . . . . . . 6 6 3 digits . . . . . . . . . . 1 2 2 4)

    ==================================

    The first occurrence of 4 5 0,

    3 .(1 4 . . . . . 1 5 6 digits . . . . . . 1 1 1 7)4 5 0

    The Body of Jesus Christ = 1 5 0 6

    1 5 0 6 completes its first occurrence at digit # 1 1 1 7

    6 6 6 + 4 5 0 = 1 1 1 6
    Last edited by Scott; 06-28-2020 at 10:25 AM.

  9. #199
    Join Date
    Aug 2013
    Posts
    361
    The first occurrence of 9 9 9 is also the first occurrence of 9 9 9 9 9 9

    "Count the number of the beast" = 1 6 8 0


    3 . 1 4 . . . . . . . . . . . . . . 9(9 9 9 9 9 . . . . . . . 1 6 8 0 digits . . . . . . . 6 6 6)


    3 . 1 4 . . . . . . . . . . . . . . 9 9 9 9 9(9. . . . . 8 6 + 1 5 9 0 digits . . . . . . 6 6 6)





    Elohim = 8 6 / Hebrew

    God = 1 5 6 / English


    3 . 1 4 . . . . . . . (8 6 . . . . . . 1 5 9 0 + 6 6 6 digits . . . . . . 1 5 6)


    3 . 1 4 . . . . . . . .8(6 . . . . . . . . . . . . . . 2 3 6 8 digits . . . . . . . . . . . . .6 6 6)




    8 6 + 6 6 6 + 1 5 9 0 + 2 6 = 2 3 6 8

    2 3 x 6 8 + 2 6 = 1 5 9 0

    This will be the 2 6 th Nov.7th including the Nov.7th of 1 9 9 5

    That first occurrence of 1 5 6 is completed at position [ 7 7 7 + 7 7 7 + 7 7 7 ]

    The first occurrence of 7 7 7 is also the first occurrence of 7 7 7 7

    Digit # 1 5 9 0 is the second 7 {7 7 7 7

    The actual number of my name, 1 5 9 0, completes its first occurrence at digit # 4 8 6 9

    1 5 9 0 + 4 8 6 9 + 1 3 1 8 = 7 7 7 7

    7 7 7 + 3 6 + 7 7 7 = 1 5 9 0

    7 + 7 + 7 x 3 6 + 7 + 7 + 7 = 7 7 7

    7 x 7 x 7 = 3 4 3

    3 4 3 occurs first starting at digit # 6 6 6

    1 5 9 0 + 7 7 8 = 2 3 6 8

    1 5 9 0 < 7 7 7 > 2 3 6 8

    1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]


    I started with this, 6 x 6 x 6 = 2 1 6, 2 9 years ago.

    6 6 6 + 2 1 6 = 8 8 2

    8 8 2 + 2 9 = 9 1 1


    8 6 completes its first occurrence at digit # 7 5

    7 5 x 7 5 = digit # [ 1 5 9 0 + 6 6 6 + 2 1 6 + 2 6 + 1 1 0 7 + 2 0 2 0 ]
    Last edited by Scott; 06-28-2020 at 10:38 PM.

  10. #200
    Join Date
    Aug 2013
    Posts
    361
    These two 4 digit numbers 3 6 7 5 and 6 7 3 5, are flanking my names first occurrence,

    3 6 7 5 1 5 9 0 6 7 3 5

    The same 4 digits arranged into 2 numbers.


    3 6 7 5 + 3 0 6 0 = 6 7 3 5

    3 0 6 0 will accomodate the words, "Saturday November Seventh Twenty Twenty"

    3 6 7 5 + 6 7 3 5 = [ 1 5 9 0 + 8 8 2 0 ]

    ================================================

    My wife has 5 5 9 flanking her maiden names gematria sum when it first occurs,

    3 . 1 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5 5 9 9 1 8 5 5 9

    Counting the digits after the first occurrence of 8 6, to the last digit of that second 5 5 9,

    is 1 5 9 0{my name) digits + 5 5 9 digits,

    3 . 1 4 . . . . . . . . . 8 6( . . . . . . . . 1 5 9 0 + 5 5 9 digits . . . . . 5 5 9 9 1 8 5 5 9)



    3 . 1 4 . . . . . . . . . . . 5 5 9 9(1 8 5 5 9 . . . . 6 6 6 + 1 3 1 8 + 6 6 6 digits . . . . . . 7 5 1 5 9 0)6

    3 . 1 4 . . . . . . . . . . . 5 5 9(9 1 8 5 5 9 . . . . . 1 5 6 + 9 0 6 + 1 5 9 0 digits . . . . . 7 5 1 5 9 0 6)

    God = 1 5 6 , Jesus Christ = 9 0 6

    =================================================

    1 + 2 + 3 + 4 . . . . . + 3 6 = 6 6 6

    The first occurrence's of 3 6 and 6 6 6,

    3 .(1 4 . . . . . 2 8 4 digits . . . . . )(3 6 . . . . . . 2 8 4 + [ 1 5 9 0 + 2 8 4 ] + 2 8 4 digits . . . . . . 6 6 6)


    3 6 completes its first occurrence at digit # 2 8 6,

    and the first occurrence of number 2 8 6 is also the first occurrence of 8 6

    =================================================

    I was supernaturally led to find the number 1 9 9 5's comparison's with 9 8 7 {P.11, post 102)

    3 .(1 4 . . . . . 1 5 1 0 digits . . . . . . 9)(8 7 . . . . 9 8 7 + 2 3 6 8 digits . . . . )1 5 9 0

    1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]

    "Nine hundred eighty seven,
    and,
    One thousand nine hundred ninety five,
    are connected
    "

    = [ 9 8 7 + 1 9 9 5 + 1 5 9 0 ]


    3 . 1 4 . . . . . . . . . 8 6(. . . . . . . 4 5 0 + 9 8 7 digits . . . . . . 9 8 7)




    Shortly after i discovered a lesser number than 9 8 7 having the same features, 7 9 8,

    "Seven hundred Ninety eight,
    Nine hundred eighty seven,
    and
    One thousand nine hundred ninety five,
    are connected
    "

    = [ 7 9 8 + 9 8 7 + 1 9 9 5 + 2 4 4 2 ]

    6 6 6 completes its first occurrence at digit # 2 4 4 2

    3 . 1 4 . . . . . . . . . . . . . 6 6 6(. . . . 7 9 8 + 9 8 7 + 1 9 9 5 digits)
    Last edited by Scott; 06-30-2020 at 02:24 PM.

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