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Thread: 9 1 1

  1. #241
    Join Date
    Aug 2013
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    443
    6 6 6 + 2 1 6 + 3 1 1 + 2 0 2 0 = 3 2 1 3

    Nov.7th is usually day 3 1 1 of the year, except in a leap year.

    This year Nov.7th starts after 3 1 1 days of 2 0 2 0 are completed.

    8 6 + 1 1 0 7 + 2 0 2 0 = 3 2 1 3
    Last edited by Scott; 09-03-2020 at 04:27 PM.

  2. #242
    Join Date
    Aug 2013
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    443
    My wifes maiden name has a sum of 9 1 8

    The first occurrence of 9 1 8 is flanked with 5 5 9,

    5 5 9 9 1 8 5 5 9



    1 5 9 0{my name) digits + 5 5 9 digits

    after the completion of the first occurrence of 8 6, is the 9

    in the second 5 5 9 that flanks 9 1 8, and that 9 is digit # 2 2 2 4,

    3 . 1 4 . . . . 8 6(. . . . . . 1 5 9 0 + 5 5 9 . . . . . . 5 5 9 9 1 8 5 5 9)


    3 . 1 4 . . . . . 5 5 9(9 1 8 5 5 9 . . . 1 5 9 0 + 1 5 6 + 9 0 6 . . . . 7 5 1 5 9 0 6)

    In English,

    God = 1 5 6
    Jesus Christ = 9 0 6
    Last edited by Scott; 09-07-2020 at 12:04 AM.

  3. #243
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    443
    1 3 1 8 + 6 6 6 = 1 9 8 4

    1 9 8 4 occurs first starting right after digit # 3 3 5 7

    Counting 3 3 5 7 digits after the completion of the first

    occurrence of 9 8 7{p.11,post # 102), puts us at digit # 4 8 6 9,

    which is the completion of the first occurrence of 1 5 9 0



    3 .(1 4 . . . . . . . 3 3 5 7 . . . .)1 9 8 4

    3 . 1 4 . . . . . 9 8 7(. . . . . 3 3 5 7 . . . . . 1 5 9 0)


    6 6 6 + 2 1 6 digits stand between

    the first occurrence of 1 9 9 5 and digit # 1 5 9 0


    123 45 6 789 0

    1 2 3 + 6 6 6 = 7 8 9
    6 x 6 x 6 = 2 1 6
    6 6 6 - 2 1 6 = 4 5 0

    First occurrence's of 1 5 9 0 and 1 3 1 8{Rev.13:18)

    3 . 1 4 . . . . . . . . (1 5 9 0 . . . . . < 4 5 0 digits > . . . . . 1 3 1 8)

    Those 4 5 0 digits + 2 1 6 digits lands on digit # 5 5 3 1

    Digit # 5 5 3 1 + 1 1 0 7 + 2 0 2 0 digits = digit # 8 6 5 8

    8 6 5 8 is the English sum of the words in Ivan Panin's N.T. of Rev. 13:18
    Last edited by Scott; 09-10-2020 at 01:12 PM.

  4. #244
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    443
    One word in Panin's translation of Rev. 1 3 : 1 8,

    is old english, the word "hath", and if changed to "has",

    the sum of the words are now 8 6 0 4

    Count the number of the beast = 1 6 8 0

    1 6 8 0 + 6 6 6 = 2 3 4 6
    1 5 9 0 + 7 5 6 = 2 3 4 6

    The first 2 3 4 6 completes its occurrence at digit # 2 6 3

    The number 8 6 0 4 completes its first occurrence at digit # 8 8 6 7

    Digit # 2 6 3 + 8 6 0 4 digits = digit # 8 8 6 7

    3 . 1 4 . . . . . 2 3 4 6(. . . . . 8 6 0 4 digits . . . . . 8 6 0 4)

    8 6 0 4 completes its first occurrence 8 6 0 4 digits

    after the first occurrence of 2 3 4 6

    If we make one more change and remove the word "for" from

    "for it is the number of a man",

    Here is the wisdom, who has understanding, let him
    count the number of the beast, it is the number of a man,
    and his number is six hundred sixty six

    then the sum of the verse is 8 3 7 0, and this is what we see

    at the first occurrence of 8 3 7 0,

    2 3 6 8 3 7 0
    Last edited by Scott; 09-11-2020 at 11:20 AM.

  5. #245
    Join Date
    Aug 2013
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    443
    Covid = 3 1 8

    Here's the first occurrence of 9 1 1 3 1 8,

    3 . 1 4 . . . . . . . . . . . . . . . . 9 1 1 3 1 8 6 6 6

    "Coronavirus disease" {Covid-19)= 3 1 8 + 6 6 6 + 3 1 8 { 1 3 0 2 )

    Including the digits of the first occurrence of 8 6

    as the first 2 digits to reach digit # 1 3 0 2,

    leaves, 3 1 8 + 9 1 1 digits,

    3 . 1 4 . . . . . .(8 6 . . . . 3 1 8 + 9 1 1 . . . . . .digit # 1 3 0 2

    Here's what makes an occurrence right before the

    first occurrence of 1 3 0 2,

    3 . 1 4 . . . . . . . . . . . 2 0 1 9 1 3 0 2
    Last edited by Scott; 09-12-2020 at 01:11 PM.

  6. #246
    Join Date
    Aug 2013
    Posts
    443
    November Seventh = 1 1 2 2

    First occurrence's of 2 0 2 0 and 1 1 2 2,

    3 . 1 4 . . . . . . 2 0 2 0(. . . . 2 0 2 0 + 1 5 9 0 + 1 1 2 2 . . . . 1 1 2 2)


    The last digit of the first occurrence of 1 1 2 2 being digit # 1 2 0 2 0

    is what i noticed first, then, i counted the measurement

    in digits from 2 0 2 0's occurrence to 1 1 2 2's occurrence.


    1 5 9 0
    +
    1
    +
    5
    +
    9
    +
    0
    +
    One Thousand Five Hundred Ninety
    +
    One
    +
    Five
    +
    Nine
    +
    Zero

    = [ 2 0 2 0 + 1 5 9 0 + 1 1 2 1 ]
    Last edited by Scott; 09-15-2020 at 11:09 AM.

  7. #247
    Join Date
    Aug 2013
    Posts
    443
    My name, 1 5 9 0, completes its first occurrence at digit # 4 8 6 9

    6 6 6 completes its first occurrence at digit # 2 4 4 2

    I was 1 0 3 1 0 days old and entering day 1 0 3 1 1 when i considered

    trying to find the date Ivan Panin spoke of, by counting 6 6 6


    First occurrence's of 6 6 6 and 1 0 3 1 0,

    3 . 1 4 . . . . . 6 6 6(. . . . 4 8 6 9 + 6 6 6 + 2 1 6 . . . . 1)0 3 1 0 {digit # 8 1 9 3

    1 5 9 0 + Count the number of the beast{1 6 8 0) + 6 6 6 = 3 9 3 6

    3 9 3 6 makes its third occurrence right before the first occurrence of 1 0 3 1 0
    Last edited by Scott; 09-16-2020 at 09:48 AM.

  8. #248
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    Aug 2013
    Posts
    443
    Genesis 6 : 1 8 is verse # 1 5 6,

    But with thee will i establish my covenant, and you shall come into
    The (4 5 0) Ark, you, your son's, your wife, and your son's
    wive's with thee.


    In Pi, the first occurrence of number 4 5 0{Noah's Ark)

    is immediately after digit # 1 5 6


    Genesis 1 8 : 2 5 is verse # 4 5 0,

    That (would) be far from thee to do in this manner, to slay the Righteous
    with the Wicked, and that{as tho) the Righteous should be as the wicked, that
    (would) be far from thee,(so,) shall not the Judge of all the earth
    do right
    (as well)


    Verse # 6 6 6 tells us that Abraham lived 1 7 5 years.


    Ivan Panin explained why it was Haran, not Abraham, that was born 1 9 4 8

    years after Adam was created, and Abraham was born 2 0 0 8 years after Adam,

    and God made a covenant with him at the 2 1 0 7 year mark, which was

    4 5 0 years after The Flood ended at 1 6 5 7 years.


    2 1 0 7 - 8 6 = 2 0 2 1

    The place values of the letters of Jesus Christ

    in the Greek alphabet{1st letter a value of 1, last letter a value of 24),

    add to 8 7

    2 1 0 7 - 8 7 = 2 0 2 0


    If we count 2 0 2 1 digits after the first occurrence of 1 5 6,

    the next 4 digits are the first occurrence of 2 0 2 1


    If we count 1 5 9 0 + 6 6 6 + 2 0 2 1

    digits after the completion of 8 6, we land on the 0 in

    the first occurrence of 2 0 2 1
    Last edited by Scott; 09-17-2020 at 02:03 PM.

  9. #249
    Join Date
    Aug 2013
    Posts
    443
    I know now, 29 years later that the words in Ivan Panin's translation of

    Rev. 1 3 : 1 8, that gives instructions to count 6 6 6, add to 8 6 5 8.

    So knowing the connection between the number 8 6 5 8

    and the number 6 6 6, i subtracted those two numbers

    from the number of days{1 0 3 1 1) i had lived on the night i counted 6 6 6

    and immediately after searched for a number having the same mathematical

    features as Enoch's 9 8 7, because i knew God picked 9 8 7

    for a very good reason,


    1 0 3 1 1 - [ 8 6 5 8 + 6 6 6 ] = 9 8 7

    8 6 5 8 + 6 6 6 + 9 8 7 = 1 0 3 1 1

    Turn's out i discovered, that theres only 1 number greater than 9 8 7

    sharing 9 8 7's features,(p.11,post # 102)

    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0
    Last edited by Scott; 09-18-2020 at 12:10 AM.

  10. #250
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    Aug 2013
    Posts
    443
    3 . 1 4 . . . . . . (2 0 2 0 . . . . . . 2 3 6 8 + 2 3 6 8 . . . . . . 1 1 2 2)

    Post # 2 4 6

    3 . 1 4 . . . . . . . 2 0 2 0(. . . 2 0 2 0 + 1 5 9 0 + 1 1 2 2 . . . 1 1 2 2)

    In Greek, "Jesus Christ" = 2 3 6 8
    Last edited by Scott; 09-20-2020 at 10:18 AM.

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