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Thread: 9 1 1

  1. #141
    Join Date
    Aug 2013
    Posts
    298
    The 9th + 11th occurrence of 9 1 1 in Pi, begins to occur at digit # 2 3 1 1 4

    1 3 1 8 + 6 6 6 + 2 1 1 3 0{my days,11/7/20) = 2 3 1 1 4

    It was the instructions of Rev. 1 3 : 1 8 to

    count 6 6 6 that led me to Nov.7th 2020.


    The first 9 1 1 begins to occur at digit # 1 5 3 3,

    and 1 5 3 3 begins first at digit # 9 1 1 + 1 1 9

    The first occurrence of number 1 5 3 2, is preceded by 9 1 1 9

    1 5 x 1 5 3 3 + 1 1 9 = 2 3 1 1 4



    9 1 1 + 9 + 1 + 1 + Nine Hundred Eleven + Nine + One + One = [ 1 5 6 + 1 5 9 0 + 9 1 0 ]

    [ 1 5 6 + 1 5 9 0 + 9 1 0 ] + Nine Eleven = [ 9 1 1 + 1 5 9 0 + 6 6 6 + 1 1 9 ]

    3 .(1 4 . . . . . 9 1 1 + 1 1 9 . . . . . . 1)(5 3 3 . . . . . . 1 5 9 0 + 6 6 6 . . . . . )

    9 1 1 + 1 1 9 + 1 5 9 0 + 6 6 6 = [ 7 3 + 3 2 1 3 ]
    3 .(1 4 . . . . . 7 3 . . . . )(8 6 . . . . . . . 3 2 1 3 . . . . . )


    3 .(1 4 . . . . . . . . 8 6 + 1 1 0 7 + 2 0 2 0 digits . . . . . . . . }digit # 3 2 1 3


    ( 3 2 1 3, post #'s 121, 122 )


    3 . 1 4 . . . . . . . . . . . (9 1 1 . . . . . . . . 9 1 0 digits . . . . . . . 6 6 6)
    Last edited by Scott; Yesterday at 10:09 AM.

  2. #142
    Join Date
    Aug 2013
    Posts
    298
    My name adds to 1 5 9 0
    My yr. of birth,
    "Nineteen Sixty Three"
    adds to 1 4 3 4

    God led me to see that only 1 number greater than the number HE used for Enoch's Rapture year, 9 8 7,

    has the same features as 9 8 7, that number is 1 9 9 5. {post #'s 102, 115)

    1 x 9 x 9 x 5 = 4 0 5

    1 9 9 5 - 4 0 5 = 1 5 9 0



    When 1 5 9 0 1 4 3 4 first occurs in Pi more than 17 million digits

    after the decimal point, this is what follows,

    1 5 9 0 1 4 3 4 1 9 9 5



    1 9 6 3 + 1 9 9 5 = [ 1 5 9 0 + 2 3 6 8 ]

    <><><><><><><><><><><><><><><><><>

    I looked for this number which is my name flanked with my years of age this year,

    and found it at digit # 7 7, 1 6 7, 6 6 7

    777 and 7777 first occur together,...the 2nd 7 is digit # 1 5 9 0

    5 7 1 5 9 0 5 7

    The 4 digit number that string of digits sits in the middle of, is 3 6 3 5,... 365715905735 ,

    9 1 1 + 2 7 2 4{November Seventh Two Thousand Twenty) = 3 6 3 5

    5 7 days from 9 / 1 1 to 1 1 / 7

    7 / 1 1 + 1 1 9 days = 1 1 / 7

    "The last Fifty Seven day's" = 1 5 9 0

    A=6 B=12 C=18 D=24 . . . .
    Last edited by Scott; Yesterday at 02:57 PM.

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