8 6 + [ 7 x 7 x 7 0 ] = 3 5 1 6{yrs.)
5 0 x 7 0 + 1 6 = 3 5 1 6
8 6 x 7 0 = yr. 6 0 2 0 { 2 0 1 8, Israel's 7 0 th yr.)
1 9 4 8 + 7 0 = 2 0 1 8
Daniel's 7 0 Week's were not fulfilled in 7 0 A.D.!
4 9 0 first occurs at digit # 9 0 7, and completes at digit # 9 0 9,
which would the 9 1 1th position of Pi.
The first occurrence of 9 0 7 is immediately after the first 5 4 1 digits of Pi
5 4 1{Israel/Hebrew sum) completes its first occurrence at digit # 1 1 1 4
digit # 1 1 1 4 + 3 9 9 9{the year Jesus Christ, 2368, was born) + 2 3 6 8 digits,
brings us to the first digit of the first occurrence of 2 3 6 8 starting at digit # 7 4 8 1
Digit # 1 1 1 4 + 5 4 1 digits, brings us to digit # 1 6 5 6, or we can say, 1 digit short of landing
on digit # 1 6 5 6
Digit # 1 1 1 4 is position [ 6 6 6 + 4 5 0 ]
4 0 3 2, year of crucifixion, occurs first starting at digit # 7 6 3 2
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