Hi Craig,

I've been thinking about the probability of finding cubes of 12 if we multiply the values of a random sequence of Hebrew letters and have found that it is not very unlikely. This is because the factors of all the letters are powers of 2, 3, and 5 except for only two letters Zayin = 7 and Ayin = 70. Thus, any verse that does not contain these two letters will be a multiple of 12.

And what is the probability that it will be a multiple of 12 cubed? That's pretty easy. The exponent of the numbers 2 and 3 must be 6 and 3, respectively. Thus, there is a 1/6 x 1/3 = 1/18 = .05 = a five percent chance that any random sequence of Hebrew letters not containing Zayin or Ayin will be a cube of 12.

Five percent is kinda smallish but it's not enough to really impress me or prove that the pattern of cubes is by design. It could be, but I'd need to study it more. I feel it is extremely important that we make every effort to discern between chance and design.

Thanks for sharing! I love this kind of analysis.

Richard

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